Answer:
40 deg
Step-by-step explanation:
The vertical sides of the rectangle are parallel, so the triangle is a right triangle.
The triangle is a right triangle, so the acute angles are complementary.
The bottom right angle of the triangle measures 90 - 50 = 40 deg.
The bottom line and the top side of the rectangle are parallel, so corresponding angles are congruent. x and the 40-deg angle are corresponding angles, so they are congruent.
x = 40 deg.
What is the common ratio?
Answer: 1.) 2n 2.) z+6 3.) 20 years old
Step-by-step explanation:
Answer:
answer one: 2n
answer two: z + 6
answer three: 20 years old
Step-by-step explanation:
edge 2020
15/25 Divididing numerator and denominator by 5 we get:
3 / 5
b. if total cost increases.
c. if there is an advance in technology.
d. All of the above are correct.
An iso-cost line will be shifted further away from the origin'' All of the above are correct".
An iso-cost line will shift either because of a change in total outlay or a change in factor prices.
A change in total outlay will cause a parallel shift in the iso-cost line, as there will be no change in its slope, factor prices being constant.
An iso-cost line will be shifted further away from the origin if the total cost increases if the price of both inputs increases or there is an advance in technology.
An iso-cost line can be defined as the graphical representation of various combinations of two inputs factors (labor, L and capital, K) which the firm can afford or purchase with a given amount of money.
Each iso-cost curve represents a fixed level of costs and the isoquant represents a fixed level of output.
Therefore, tracing a line through these set of points represents what combination of labor and capital will be used for a fixed level of costs or output.
The points further away from the origin represent higher levels of costs or output. An iso-costline can be expressed mathematically as:
Where,C = cost of production
w = price of labor or wages
L = units of labor
r = price of capital or interest rate
K =units of capital
Iso-cost is used to determine what combination of factor inputs the firm will choose for the production process.
Hence, An iso-cost line will be shifted further away from the origin'' All of the above are correct".
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Answer:
D. All the above are correct
Step-by-step explanation:
An isocost line will be shifted further away from the origin if the total cost increases, if the price of both inputs increases or there is an advance in technology.
An isocost line can be defined as the graphical representation of various combinations of two inputs factors (labor,L and capital, K) which the firm can afford or purchase with a given amount of money.
An isocost line can be expressed mathematically as:
C = w L + r K
Where,
C = cost of production
w = price of labor or wages
L = units of labor
r = price of capital or interest rate
K =units of capital
Isocost is used to determine what combination of factor inputs the firm will choose for production process.
The value of \(x\) that makes the equation true is
To find the value of \(x\) that makes the equation true, you need to simplify the equation and solve for \(x\). Let's break down the steps:
1. **Distribute the -5 on the left side:**
2. **Move the constant term (100) to the right side by subtracting 100 from both sides:**
3. **Finally, divide both sides by -5 to solve for \(x\):**
To verify, substitute \(x = 13\) back into the original equation:
The equation is true when \(x = 13\).
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Answer:
x=13
Step-by-step explanation:
Divide both sides by -5 then solve the equation for x
Answer: 380000 cells/hour
Step-by-step explanation:
Given that dP/dt = 0.19P(t)
where
P(t) is the size of the culture (measured in millions of cells) at time t > 0 (measured in hours).
The formula above represents a mathematical model for the growth of a certain cell culture. In essence, it represents the time rate of the growth of the cell culture, that is how fast the cell culture is growing.
Therefore, when P = 2 million cells:
dP/dt = 0.19 * 2000000 = 380000 cells/hour
Hence, the cell culture is growing at 380000 cells per hour.
The cell culture is growing at a rate of 0.38 million cells per hour when the size of the culture reaches 2 million cells. This is based on the given differential equation dP/dt = 0.19P(t).
This problem is associated with the concept of differential equations, particularly exponential growth. In this scenario, the rate of change of P(t), the size of the cell culture, is given by the equation dP/dt = 0.19P(t). This can be interpreted as the culture is growing at 19% per unit of time.
To determine how fast the culture is growing when P(t) equals 2 million cells, we need to substitute 2 for P(t) in the given equation: dP/dt = 0.19*2. This calculation returns a value of 0.38 million cells per hour. Therefore, when the size of the culture reaches 2 million cells, it is growing at a rate of 0.38 million cells per hour.
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