Answer:
7
3.5
Step-by-step explanation:
Answer: It is a weak negative correlation and it is not likely causal.
Step-by-step explanation:
Given: The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26.
Variables : "number of times a player has golfed in one's lifetime" and "number of strokes it takes the player to complete 18 holes".
Since -0.26 is more closer to 0 as compared to 1 , so it describes a weak negative correlation.
Also, it is not likely causal as number of times a player has golfed in one's lifetime not cause number of strokes it takes the player to complete 18 holes.
Answer: B) It is a weak negative correlation, and it is likely casual
Correct on edge 2020!
Answer:
The length and width of the floor of the shed are 8 feet and 5.5 feet, respectively.
Step-by-step explanation:
Given that the shape of the shed is a rectangle, the expression for the area is:
Where and are the width and length of the shed, measured in feet. In addition, the statement shows that . Then, the equation of area is expanded by replacing length:
If , then, a second-order polynomial is formed:
The roots of this equation are found via General Equation for Second-Order Polynomials:
and
Only the first roots is a physically reasonable solution. Then, the length of the shed is:
The length and width of the floor of the shed are 8 feet and 5.5 feet, respectively.
Answer:
0.25
Step-by-step explanation:
16 ounces = 1 pound
4.00 / 16 = 0.25
The greatest common factor of 42 and 96 is 6.
The greatest common factor (GCF) of a set of numbers is the largest factor that all the numbers share.
42 = 2 x 3 x 7
96 = 2 x 2 x 2 x 2 x 2 x 3
Greatest common factor = 2 x 3 = 6
Learn more about greatest common factor here
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Answer:
6
Step-by-step explanation:
42 and 96
first we will find the factors of 42:
2 21
3 7
7 7
hence, factors of 42 are 2,7 and 3
then, we will find the factors of 96:
2 96
2 48
2 24
2 12
2 6
3 3
1
hence, factors of 96 are 2,2,2,2,2 and 3
Common factors are: 2 and 3
Highest common factor: 6
A. y = (-5/2)x - 3
B. y = (-2/5)x + 3
C. y = (-2/5)x - 3
D. y = (2/5)x + 3
Answer:
B
Step-by-step explanation:
The equation we must find is in y = mx + b form. We are given that it intercepts (0,3), so the y-intercept it 3 and b = 3. We can find the slope with the two points we are given: m = (3-5)/(0(-5)) = -2/5. Substituting these values, we find: y = (-2/5)x + 3
Does this sample data provide evidence that the breeder's claim is correct?
Answer:
The calculated value Z = 1.183 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
A particular greyhound breeder claims that her dogs are faster than the average greyhound
Step-by-step explanation:
Step(i):-
Given the average speed of greyhound dogs is about 18.4 meters per second.
Size of the sample 'n' = 35
mean of the sample x⁻ = 18.7
Population standard deviation = 1.5m/s
level of significance (∝) = 0.05
Step(ii):-
Null hypothesis : H₀ : μ = 18.4
Alternative hypothesis H₁ : μ ≠ 18.4
Test statistic
Z = 1.183
Conclusion:-
The calculated value Z = 1.183 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
A particular greyhound breeder claims that her dogs are faster than the average greyhound
Evaluate the breeder's claim by using a one-sample z-test. The null hypothesis states that the breeder's dogs aren't faster than average, while the alternative hypothesis states that they're faster. If the calculated Z is greater than Zcritical, it supports the breeder's claim.
In this scenario, you would carry out a one-sample z-test to evaluate the breeder's claim. Given an average speed of greyhounds as 18.4 m/s, the breeder's dogs with an average of 18.7 m/s could be faster or this could just be due to statistical fluctuation. Hence, we need to statistically test it to see if this evidence is strong enough (with a significance level of .05) to support the breeder's claim.
Our null hypothesis (H0) is that the breeder's dogs are not faster than the average greyhound (µ = 18.4 m/s), and our alternative hypothesis (Ha) is that they are faster (µ > 18.4 m/s). Using the Z-test formula:
Z = (Xbar - µ) / (σ/√n)
where Xbar is sample mean, µ is population mean, σ is standard deviation, and 'n' is sample size. Applying the provided figures, we get:
Z= (18.7-18.4)/(1.5/√35)
Give the calculated Z value and compare it to the Z critical value for 0.05 significance level (1.645 for one-tail). If the calculated Z is greater than Zcritical, we reject the null hypothesis, providing evidence that the population mean is greater than 18.4 m/s, supporting the breeder's claim.
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