The number 68,979 is divisible by 3 but not by 5, 6, or 11.
To test a number for divisibility by 3, we sum up its individual digits. If the sum is divisible by 3, then the number itself is divisible by 3. For the number 68,979, the sum of its digits is 6 + 8 + 9 + 7 + 9 = 39. Since 39 is divisible by 3, 68,979 is also divisible by 3.
To test a number for divisibility by 5, we simply check if the last digit is either 0 or 5. In the number 68,979, the last digit is 9, which is neither 0 nor 5. Therefore, 68,979 is not divisible by 5.
To test a number for divisibility by 6, we need to check if it is divisible by both 2 and 3. From the previous tests, we already know that 68,979 is divisible by 3, so we now need to check if it is divisible by 2. Since the last digit is 9, which is an odd number, 68,979 is not divisible by 2, and therefore not divisible by 6.
To test a number for divisibility by 11, we take the alternating sum of its digits. In this case, we have 6 - 8 + 9 - 7 + 9 = 9. Since 9 is not divisible by 11, 68,979 is not divisible by 11.
Answer: -1 1/8
Step-by-step explanation: When you have a problem like this, you have to divide.
So you turn the improper fraction into a mixed number which (4 1/2 turns into 9/2) and then you do KCF (Keep Change Flip). So you keep the 9/8, change division into multiplication, and since we are going to put the four over a 1 like this 4/1, we need to change it into 1/4. Then you multiply across. 9x1=9 and 2x4=8 so it would be 9/8. But it's an improper fraction right? So you do long division, and you get -1 1/8.
-103
if he lost the same weight each week that means -412 (the weight he lost) ÷ 4 (number of weeks) = -103 (amount of weight lost in one week)
Answer:
Step-by-step explanation:
Hello,
This is the equation of a line so if you know two points of the line you can graph it, right?
For x = 0 y = -3 so the point A (0,-3) is on the graph
For x = 3 y =-4 so the point B (3,-4) is on the graph
And then you can draw the line as below
Thanks
b. y-y1=m(x-x1)
c. y1=mx1+b
d. Ax1+by1=C
e. y=mx+b
f. y1-y=m(x-x1)
Please explain why, if you can. Thanks! :)
The equation of the line, in point-slope form, is given by:
Option b.
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The equation of a line, in point-slope form, is given by:
In which
A similar problem is given at brainly.com/question/24144915
Answer:
b. y-y1 = m(x-x1)
Step-by-step explanation:
It's a matter of definition. There are perhaps a dozen useful forms of equations for a line. Each has its own name (and use). Here are some of them.
Adding y1 to the point-slope form puts it in an alternate form that is useful for getting to slope-intercept form faster: y = m(x -x1) +y1. I use this when asked to write the equation of a line with given slope through a point, with the result in slope-intercept form.
Answer:
56, 57, and 58.
Step-by-step explanation:
of the expression?
21.3 + (-34.87)
Answer:
-13.57
Step-by-step explanation:
21.3 + (-34.87) = -13.57
Mark me as brainliest if you want to.