Answer:
(0, –2)
Step-by-step explanation:
I am assuming that point 'B' is (-5 , 0).
The translation rule is: .
Apply the rule to point 'B':
B' should be (0, -2).
Answer:
Guy above me might be right but Im not sure. Im on the cumulative exam on edge.
Step-by-step explanation:
Answer:
Yes, letter D is correct.
Step-by-step explanation:
The shape is a trapezoid so you'll have two congruent pairs of base angles.
Answer:
3 times
Step-by-step explanation:
if we look at 193 times 1 its 193, times 2, its 386, times 3, 579 with a remainder of 131
B=n2 + 6n + 1
C=2n2 + 6n – 1
D=3n2 + 5
Answer:
Step-by-step explanation:
Given :
To Find: AB-C
Solution:
Since A=n
B=2n+6
So,
Now since
Thus
⇒
⇒
Thus option B is correct .
also elements of F.
Greetings from Brasil...
G = {4; 8; 12; 16; 20; 24; 28; 32; 36; 40; 44; 48; 52; 56; 60; 64; 68; 72; 76; 80; 84; 88; 92; 96; 100; 104; ...}
F = {1; 4; 9; 16; 25; 36; 49; 64; 81; 100; ...}
So, according to the statement, it is desired:
G ∩ F - the intersection between the 2 sets, that is, which numbers are present simultaneously in the 2 sets....
Looking at the sets we conclude that
OBS: note that in truth G are the multiples of 4
The first five elements of set H, which include positive integers divisible by 4 that are also perfect squares, are 4, 16, 36, 64, and 100.
The two sets mentioned in the problem are Set G, which contains positive integers divisible by 4, and Set F, which contains perfect squares. The intersection of these two sets is Set H. To find the elements of Set H, we look for numbers that are both divisible by 4 and perfect squares. The first five such numbers are 4, 16, 36, 64, and 100. For example, 16 is both a multiple of 4 and a perfect square because it can be expressed as 4*4 and is the square of 4. Similarly, 36 fits both criteria because it can be expressed as 4*9 and is the square of 6. We continue this pattern to identify the first five elements of Set H.
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