Answer:
constant horizontal force developed in the coupling C = 11.25KN
the friction force developed between the tires of the truck and the road during this time is 33.75KN
Explanation:
See attached file
The total force resisting the motion of the car, boat, and trailer is 990 N. The friction force developed between the tires of the truck and the road can be calculated using the equation Ffriction = μN.
To determine the constant horizontal force developed in the coupling C, we need to calculate the total force resisting the motion of the car, boat, and trailer. We can use Newton's second law, which states that force equals mass times acceleration (F = ma). The mass of the car, boat, and trailer combined is 1800 kg (1100 kg + 700 kg). The acceleration is 0.550 m/s². Therefore, the total force resisting the motion is 990 N (1800 kg * 0.550 m/s²).
To determine the friction force developed between the tires of the truck and the road during this time, we need to consider the force of friction. The force of friction can be calculated using the equation Ffriction = μN, where μ is the coefficient of friction and N is the normal force. In this case, the normal force is equal to the weight of the truck, which can be calculated as the mass of the truck times the acceleration due to gravity (9.8 m/s²). Assuming the coefficient of friction is 0.62 (as given in the example), the friction force can be calculated as Ffriction = 0.62 * (1800 kg * 9.8 m/s²).
Answer:
a n c
Explanation:
The volume rate of flow can be determined using the equation Q = Av, where Q is the volume rate of flow, A is the cross-sectional area of the pipe, and v is the average speed of the water. Given the diameter of the wider section of the pipe is 6.0 cm and the gauge pressure is 32.0 kPa, we can calculate the volume rate of flow using the provided information. The volume rate of flow is found to be 0.0018 m³/s.
The volume rate of flow can be determined using the equation Q = Av, where Q is the volume rate of flow, A is the cross-sectional area of the pipe, and v is the average speed of the water.
Given that the diameter of the wider section of the pipe is 6.0 cm, the radius is 3.0 cm and the gauge pressure is 32.0 kPa. Similarly, for the narrower section with a diameter of 4.0 cm, the radius is 2.0 cm and the gauge pressure is 24.0 kPa.
Using the equation Q = Av and the fact that the flow rate must be the same at all points along the pipe, we can set up the equation A₁v₁ = A₂v₂. Solving for v₂, we have v₂ = A₁v₁ / A₂ = πr₁²v₁ / πr₂², where r₁ is the radius of the wider section and r₂ is the radius of the narrower section.
Substituting the values, we get v₂ = (3.14)(3.0 cm)²(32.0 kPa) / [(3.14)(2.0 cm)²] = 18.0 cm/s. Since v = d/t, we can convert cm/s to m³/s by multiplying by 0.0001, so the volume rate of flow is 0.0018 m³/s.
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(b) Calculate the magnification.
Answer:
A) Calculate the distance
Answer:
In the clarification portion elsewhere here, the definition of the concern is mentioned.
Explanation:
So like optical telescopes capture light waves, introduce it to concentrate, enhance it, as well as make it usable through different instruments via study, so radio telescopes accumulate weak signal light waves, introduce that one to focus, enhance it, as well as make this information available during research. To research naturally produced radio illumination from stars, galaxies, dark matter, as well as other natural phenomena, we utilize telescopes.
Optical telescopes detect space-borne visible light. There are some drawbacks of optical telescopes mostly on the surface:
Although radio telescopes monitor space-coming radio waves. Those other telescopes, when they are already typically very massive as well as costly, have such an improvement surrounded by optical telescopes. They should be included in poor weather and, when they travel through the surrounding air, the radio waves aren't obscured by clouds. Throughout the afternoon and also some at night, radio telescopes are sometimes used.
Answer:
venus - 2
earth - 3
mars - 4
mercury - 1
The problem discusses the change in acceleration when a passenger is added to a car. It requires understanding of Newton's second law of motion, force equals mass times acceleration, and then recalculating the acceleration with the passenger added to the total mass.
This problem pertains to Newton's second law of motion, stating that the force applied on an object equals its mass times its acceleration (F = ma). Given that the initial acceleration of the Lamborghini Huracan with a driver is 0.80g or 0.80*9.80 m/s², we can calculate the force applied by the car. By multiplying the car's mass (1510 kg) with its acceleration, we will find the force.
Οnce we have the force, we can calculate the new acceleration if the 80 kg passenger rode along. Given that the force is constant, we determine the car's new acceleration by dividing this force with the new total mass (car mass + passenger's mass). So the question ultimately requires an application of the concepts of force, mass, and acceleration.
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The new acceleration of the Lamborghini Huracan with an added passenger can be calculated by finding the initial force using the car's mass and acceleration, and then using this force with the increased mass (original mass + passenger's mass) to find the new acceleration. The new acceleration will be less than the initial acceleration due to the increased mass.
To determine the new acceleration of the Lamborghini Huracan with an added passenger, we first calculate the initial force acting on the car. This can be done by using Newton's second law which states that Force = mass * acceleration. Initially, the acceleration is 0.80g (where g is acceleration due to gravity = 9.81 m/s²), and the mass is 1510 kg (including the driver). Therefore, the initial force = 1510 kg * 0.8 * 9.81 m/s².
However, when an 80-kg passenger rides along, the total mass becomes 1510 kg + 80 kg = 1590 kg. To find the new acceleration, we keep the force constant (as it is not affected by the introduction of the passenger) and rearrange the formula F = m*a as a = F/m. Use the increased mass to find the new acceleration. Please note that the new acceleration will be less than the initial acceleration due to increased mass.
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"The equation can be used to calculate the power absorbed by any surface" statement concerning the Stefan-Boltzmann equation is correct.
Answer: Option A
Explanation:
According to Stefan Boltzmann equation, the power radiated by black body radiation source is directly proportionate to the fourth power of temperature of the source. So the radiation transferred is absorbed by another surface and that absorbed power will also be equal to the fourth power of the temperature. So the equation describes the relation of net radiation loss with the change in temperature from hotter temperature to cooler temperature surface.
So this law is application for calculating power absorbed by any surface.