MATHEMATICS MIDDLE SCHOOL

Given the figure below, find the values of x and z.

Answers

Answer 1

Answer:

Answer:

X=6°

z=112°

Solution,

FindingthevalueofX,

$11x + 2 = 68$

(beingverticallyoppositeangles)

$11x = 68 - 2 \n 11x = 66 \n x = (66)/(11) \n x = 6$

ValueofX is6

Now,findingthevalueofz

$z + 68 = 180$

(sumofangleinlinearpair)

$z = 180 - 68 \n z = 112$

Valueofzis112.

Hopethishelps....

Goodluck on your assignment...

Answer 2

Answer: answer : x = 12 z = 112
explanation:

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I’m stuck on this problemPls help ASAP

4p+p+12like terms
please help

sorry for asking for so much help

Answers

Answer:

The answer that I got is 5p+12

Answer:

5p+12

Step-by-step explanation:

Freda paid 6.5% sales tax on an item that costed $38 how much did she pay in tax

Answers

6.5%= 6.5/100= 65/1000

$38*(6.5)/(100)=38*(65)/(1000)=(38)/(1)*(65)/(1000)=(2470)/(1000)=2.47$

The correct answer is:
C. 2.47$

Greetings,
n00nst00p :)

What is the answer? -15+9-12

Answers

-15+9-12 = -6-12 = -18

-15+9-12= -18 . If The Big Number Is A Negative, You Carry The Sign To The Final Answer.

Can u translate the algebraic expression on One-half of the sum of q and 4? Plz help me I need it right now

Answers

Don't make something hard out of something easy.

'q' is q .

'4' is 4 .

Their sum is (q + 4) .

One half of that sum is (1/2) (q + 4) .

John, Sally, and Natalie would all like to save some money. John decides that itwould be best to save money in a jar in his closet every single month. He decides
to start with $300, and then save $100 each month. Sally has $6000 and decides
to put her money in the bank in an account that has a 7% interest rate that is
compounded annually. Natalie has $5000 and decides to put her money in the
bank in an account that has a 10% interest rate that is compounded continuously.

How much money have after 2 years?

How much money will sally have in 10 years?

What type of exponential model is Natalie’s situation?

Write the model equation for Natalie’s situation

How much money will Natalie have after 2 years?

How much money will Natalie have after 10 years

Answers

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^(t)$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+(r)/(n))^(nt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\n r=7\%=0.07\nn=1$

substitute in the formula above

$A=6,000(1+(0.07)/(1))^(1*t)\n A=6,000(1.07)^(t)$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(10)=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(2)=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^(rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\nr=10\%=0.10$

substitute in the formula above

$A=5,000(e)^(0.10t)$

Applying property of exponents

$A=5,000(1.1052)^(t)$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^(0.10*10)=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^(0.10*2)=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

How many yards are equal to 18ft

Answers

18ft converts to 6 yards.

6 yards is equal to 18 feet

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