The rate of the reaction is 4.5 mol L⁻¹s⁻¹.
Rate of a reaction is defined as the change in concentration of any one of the reactants or products of the reaction, in unit time.
Here,
The concentration of A, [A] = 1 M
The concentration of B, [B] = 3 M
The partial order with respect to A, m = 2
The partial order with respect to B, n = 1
The rate constant of the reaction, k = 1.5
The rate of the reaction,
r = k[A]^m [B}^n
r = 1.5 x 1² x 3
r = 4.5 mol L⁻¹s⁻¹
Hence,
The rate of the reaction is 4.5 mol L⁻¹s⁻¹.
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#SPJ2
Answer:
k= 1.5
[A] = 1 M
[B] = 3 M
m = 2
n = 1
Explanation:
rate = k[A]”[B]"
Answer:
- Proper urine flow by signalling the kidney cells.
- They act as mechanoreceptors or sensory receptors.
Explanation:
Answer:
Answer: Yes
Explanation:
Density of a liquid depend on its volume. This is because Density is mass of liquid divided by volume.
Density is inversely proportional to volume.
As density increases, volume decreases and vice versa. The density for water is 1g/ milliliter but it changes with changes in temperature or there are impurities dissolved in it. Ice is less dense that liquid water and it's the major reason it's float because it's volume is inversely proportional to it's density.
Reactants take 504.87 yr to reach 12.5% of their original value in first-order decomposition reaction.
....(1)
Here, is the final concentration, t is the time, is the initial concentration, and k is the rate constant.
Given:-
k=
Substitute the above value in equation (1) as follows:-
So, 504.87 yr does it take for the reactant to reach 12.5% of its original value.
Find more information about first- order decomposition reaction here:-
The time required for a reactant to reach 12.5% of its original value in a first-order reaction is approximately 1482 years, obtained by applying the formula for the half-life of a first-order reaction and multiplying by 3.
In a first-order reaction, the half-life of the reaction, which is the time it takes for half of the reactant to be consumed, is independent of the concentration of the reactant. Also, for a first-order reaction, it would take approximately 3 half-lives for the reactant to be reduced to 12.5% of its original value. The Integrated Rate Law for a First-Order Reaction can be applied to determine the time it will take.
Given the rate constant (k) is 0.00140 yr¯¹, we will use the formula for the half-life of a first-order reaction: t₁/₂ = 0.693 / k. After calculating the half-life (t₁/₂), multiply it by 3 to determine the time for the reactant concentration to reach 12.5% of its original value. Hence, it would take approximately 1482 years to reach 12.5% of the original value when rounded to the correct number of significant figures.
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Answer:
The empirical formula is C3H5
Explanation:
Step 1: Data given
Mass of the compound = 7.80 grams
Mass of CO2 = 25.1 grams
Molar mass of CO2 = 44.01 g/mol
Mass of H2O = 8.55 grams
Molar mass of H2O = 18.02 g/mol
Molar mass C = 12.01 g/mol
Molar mass H = 1.01 g/mol
Molar mass O = 16.0 g/mol
Step 2: Calculate moles CO2
Moles CO2 = mass CO2 / molar mass CO2
Moles CO2 = 25.1 grams / 44.01 g/mol
Moles CO2 = 0.570 moles
Step 3: Calculate moles C
For 1 mol CO2 we have 1 mol C
For 0.570 moles CO2 we have 0.570 moles C
Step 4: Calculate mass C
Mass C = 0.570 moles * 12.01 g/mol
Mass C = 6.846 grams
Step 5: Calculate moles H2O
Moles H2O = 8.55 grams / 18.02 g/mol
Moles H2O = 0.474 moles
Step 6: Calculate moles H
For 1 mol H2O we have 2 moles H
For 0.474 moles H2O we have 2*0.474 = 0.948 moles H
Step 7: Calculate mass H
Mass H = 0.948 moles * 1.01 g/mol
Mass H = 0.957 grams
Step 8: Calculate mol ratio
We divide by the smallest amount of moles
C: 0.570 moles / 0.570 = 1
H: 0.948 moles / 0.570 = 1.66
This means for 1 mol C we have 1.66 moles H OR for 3 moles C we have 5 moles H
The empirical formula is C3H5
To find the empirical formula of the hydrocarbon, divide the moles of CO2 and H2O by their molar masses. Use the smallest mole ratio to determine the empirical formula.
To find the empirical formula of the hydrocarbon, we need to determine the mole ratios between carbon and hydrogen in the compound. First, calculate the moles of CO2 produced by dividing the mass of CO2 by its molar mass. Next, calculate the moles of H2O produced by dividing the mass of H2O by its molar mass. Finally, divide the moles of each element by the smallest number of moles to obtain the mole ratio between carbon and hydrogen. The empirical formula is CnHm, where n and m represent the mole ratios of carbon and hydrogen, respectively.
#SPJ3
Answer:
Hydrogen bonding
London dispersion forces
Explanation:
The most pronounced and consequential intermolecular forces at play has to be hydrogen bonding due to the dipole created between the oxygen and hydrogen in the hydroxyl group. And then to a lesser extent there are very weak London dispersion forces that are always going to be there in between any two molecules of any species.