Please help! Correct answer only!For a fundraiser, there is a raffle with 100 tickets. One ticket will win a $150 prize, and the rest will win nothing. If you have a ticket, what is the expected payoff?


$ ___
Please help! Correct answer only! For a fundraiser, there is - 1

Answers

Answer 1
Answer:

Answer:

Expected Payoff ⇒ $ 1.50 ; Type in 1.50

Step-by-step explanation:

Considering that 1 out of the 100 tickets will have a probability of winning a 150 dollar prize, take a proportionality into account;

100 - Number of Tickets,\n1 - Number of Tickets You Can Enter,\n\n1 / 100 - Probability of Winning,\n$ 150 - Money Won,\n\nProportionality - 1 / 100 = x / 150, where x -

Thus, Solution ; Expected Payoff ⇒ $ 1.50


Related Questions

1 7/3 in simplest form
The sum of the measures of the interior angles in a polygon is 540 degrees. How many sides does the polygon have?
Given: y // z Prove: measure of angle 5 plus measure of angle 2 plus measure of angle 6 equals 180 degrees
A car rents for $45 per day plus 21 cents per mile. You are on a daily budget of $66. What mileage will allow you to stay within your budget?
In forming a contract, "consider" is

Two Factors of 36 add up to 15. what are they

Answers

the answer is three and twelve

Can you help me with they, a picture is attached to this. thank you

Answers

Simple,

it's B.

(a-b)/(b) = (3)/(7)

That's giving you an example...

(a)/(b)= (10)/(7) it's telling you to plug it in, simple...

a=10
and
b=7

(10-7)/(7) = (3)/(7)

True, or not true?

Thus, your answer. B.

Write expression as a complex number in standard form and show work [(13i)/(1-2i)]

Answers

the solution
let A = 13i /1-2i 
    so A = 
13i (1+2i) /(1-2i) ( 1+2i) = 13i (1+2i) /1² - (2i)² = 13i -26 / 1  
finally A = 13i -26 

There are 20 counters in a box . A counter is chosen and replaced 100 times , The results are 32 blue and 62 red . How many of each colour do you think there are in the box , can someone help me out on this please ? I'm very confused

Answers

The numbers in the question are wrong.  It says you pulled something
out of the box and put it back in the box 100 times.  The total of
everything you pulled out should be 100, but it says you got
(32 + 62) = 94 things. 

I'm going to change the numbers slightly, so you'll see how to do it.
We're going to say that you get blue ones  33  times, and you get
red ones  67 times.   That's better, because  (33 + 67) = 100 .


When you do the experiment, the things in the box are shaken and
completely mixed up, and when you reach in to pick one, you always
keep your eyes closed so you don't see what you're getting.  The
choice is always "random".  That means what you get is determined
completely by chance, not by anything you do.

Then the result of your experiment is:

-- A blue thing comes out  33  times in  100 draws.
   That's  33%  of the time.

-- A red thing comes out  67  times in  100 draws.
   That's  67%  of the time.

If the choice is really random chance every time, then the only thing
that can influence what you get is how many of each thing is in the box. 
Whatever there are more of, you'd expect to get more often.  Whatever
there's less of, you'd expect to get less often.

-- You pulled things out of the box 100 times.
-- You got blue things 33% of the times.
-- You got red things 67% of the times.
-- Now, you take an educated guess, and you tell everyone: 

         "I estimate that roughly 33% of the things in the box are blue,
          and roughly 67% of the things in the box are red."

Then you ask:   "How many things are in the box all together ?"

There are 20 things in the box all together, Makookoo.

"Well OK then.  33% of 20 things is  6-2/3 things.  But all the things
in the box are whole things. There aren't any pieces of things.  So I'll round my estimate to the nearest whole thing.  6-2/3 rounds to 7 . . .  Roughly 7 of the things in the box are blue.

And furthermore . . .

"67% of 20 things is 13.4 things.  But all the things in the box are
whole things. There aren't any pieces of things.  So I'll round my
estimate to the nearest whole thing.  13.4 rounds to 13 . . .  Roughly
13 of the things in the box are red."

I was confused too. I'd say 60 red and 40 blue because I multiplied 62*2 and 32*2

I got 124 and 64.

Then, I subtracted 124 and 64 to get 60 for red and added 40 to get 100

so... red is 60 and blue is 40.

Make w the subject of the formula!!!!! HELP!!!!

y=3w-a

Answers

y = 3w - a
We need to isolate w here
so, we do these steps:
1 - add a
y = 3w - a
+a      + a
y + a = 3w

Divide by 3 to isolate w
(y+a)/(3) = (3w)/(3)
3 and 3 cancels out

Final answer:
(y+a)/(3) = w

Shown are lines p , r , t , and w. Suppose angles 8 and 10 are congruent. Given this fact, which two line must be congruent? Show all work to receive credit.

Answers

Answer:

  lines t and w must be parallel

Step-by-step explanation:

Angles 8 and 10 are alternate interior angles with respect to transversal r across lines t and w. If those angles are congruent, then lines t and w must be parallel.