Solve the given equation for z :
2iz - 5 + i = i - (z - 2i )
2iz - 5 = 2i - z
(2i + 1) z = 2i + 5
z = (2i + 5)/(2i + 1)
z = (2i + 5)/(2i + 1) × (2i - 1)/(2i - 1)
z = (4i ² + 10i - 2i - 5) / (4i ² - 1)
z = (8i - 9)/(-5)
z = 9/5 - 8/5 i
Then
w = z - 1 + i = 4/5 - 3/5 i
What's the value if D(15)
100-2
100*2
100/2
For this case we have the following division:
We want to rewrite the problem in an equivalent way.
For this, we can use the following symbols that represent a division.
We have then:
100 ÷ 2
Answer:
If you wanted to use the numeric key pad to divide 100 by 2, you would type 100/2
Answer:
and are the roots of given quadratic equation.
Step-by-step explanation:
Given quadratic equation is
We have to check all the given options.
If the value of f(b) gives 0 when put the value of b in above equation then only that b value is the root of quadratic equation.
hence, only first two values gives the value of f(b)=0 .
⇒ and are the roots of given quadratic equation.
3 times b
Answer:
3b
Step-by-step explanation:
It`s just . . . 3b lol
When numbers and variables multiply, they are put in the form of (integer)(variable). They phrase can only be further simplified if there is a number substitution for b.
No. The trials are fixed, but the probability of success changes for every trial.
No. The probability of success remains the same for every trial, but the trials are not fixed.
Yes. The outcomes can be classified into two categories, the trials are fixed, and the events are independent.
Answer:
Yes. The outcomes can be classified into two categories, the trials are fixed, and the events are independent.
Step-by-step explanation:
Hope this helps!!