Answer:
excretion
Explanation:
The bodily process of discharging waste.
b. grams.
c. Calories.
d. kilowatts.
b. Newtonian focus
c. Schmidt-Cassegrain focus
d. Schmidt focus
B. 2.2 m/s^2
C. 4.5 m/s2
D. 3.3 m/s^2
The acceleration of the sled is 2.2 m/s^2.
To determine the acceleration of the sled, we can use Newton's second law of motion which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration: F = m * a. Rearranging the formula, we have a = F / m. Plugging in the given values, we get a = 540 N / 250 kg = 2.16 m/s2. Therefore, the correct answer is B. 2.2 m/s2.
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wire has a resistance of 1.3 ohms. The crosssectional
area of this wire is
(1) 7.9 × 10^−8 m2 (3) 4.6 × 10^0 m2
(2) 1.1 × 10^−7 m2 (4) 1.3 × 10^7 m2
The cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
Resistance is obstacle for the current flow in the circuit. It is the measure of reverse act to current flow in through a material. It can be given as,
Here, (ρ) is the specific resistance (l) is the length of the wire and (A) is the cross-sectional area of the wire.
During a laboratory experiment, the student finds that at 20° Celsius, a 6.0-meter length of copper wire has a resistance of 1.3 ohms.
The value of resistivity of copper wire is 1.72×10⁻⁸ ohm-m. Put these values in the above formula as,
Thus, the cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
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ρ = resistivity of copper at 20 °C = 1.72 x 10⁻⁸ ohm-m
R = resistance of the copper wire = 1.3 ohm
L = length of the copper wire = 6 meter
A = area of cross-section of the copper wire = ?
Resistivity of copper wire is given as
R = ρL/A
inserting the values in the above equation
1.3 = (1.72 x 10⁻⁸) (6)/A
A = 7.9 x 10⁻⁸ m²
Hence the correct choice is
(1) 7.9 x 10⁻⁸ m²
b. electron transport
c. glycolysis
d. Krebs cycle
Fermentation is the stage where it is not part of the cellular respiration. The answer is letter A. fermentation does not require oxygen to do respiration, rather, these are the glycolysis, Kreb’s cycle and electron transport.
Fermentation is NOT a stage of cellular respiration. Therefore option A is correct.
Fermentation is not a stage of cellular respiration. Cellular respiration is the process by which cells break down glucose and other organic molecules to produce energy in the form of ATP (adenosine triphosphate).
It occurs in three main stages: glycolysis, the Krebs cycle (also known as the citric acid cycle or the tricarboxylic acid cycle), and the electron transport chain.
Fermentation is an alternative metabolic pathway that occurs in the absence of oxygen (anaerobic conditions). It is a partial breakdown of glucose or other organic molecules that do not involve the complete oxidation of glucose to produce ATP.
Instead, it produces a small amount of ATP and end products such as lactic acid or ethanol.
Therefore option A is correct.
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O A. Nitrogen, N
O B. Aluminum, Al
O C. Phosphorus, P
D. Boron, B
The elements that would form positive ions with a +3 charge are aluminum (Al) and boron (B).
Based on their locations on the periodic table, the two elements that would form positive ions with a +3 charge are aluminum (Al) and boron (B).
When an element gains or loses electrons to form an ion, it takes on a charge that corresponds to the number of electrons gained or lost. Aluminum, located in Group 13 of the periodic table, tends to lose its three valence electrons to form an ion with a +3 charge. Likewise, boron, located in Group 13 as well, will also lose its three valence electrons to achieve a +3 charge.
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Answer:
i think it would be B. Aluminum, Al and D. Boron, B
Explanation:
since they're both in group 13 and they forms a 3+ ion