The heat capacity of a sample should be divided by which quantity to find the specific heat capacity?

Answers

Answer 1
Answer:

The heat capacity of a sample should be divided by the number of moles of a substance to find the specific heat capacity of that substance. For example, the specific heat capacity of methane is 4.475 kJ/kg-K.


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Use the axes below to graph the skydiver's velocity. Remember that a negative velocity should be graphed below the X-axis. Be sure to include numerical and word labels, with units, for both axes.

Answers

Don’t we need a photo

Answer: This is the graph we are supposed to fill out.

Explanation:

What type of reaction is shown below? Ba(OH)2 + 8H20 + 2NH4NO3 + heat ?10H2O + 2NH3 + Ba(NO3)2

Answers

Double Displacement Reaction

An element from each of two compounds switch places.
Example: compound + compound ⇒ compound + compound

Chemical reactions are processes in which substances change into other substances. A chemical reaction takes place if one or more of these occur:
Color changes - Different combinations of molecules reflect light differently. A color change indicates a change in molecules.
Heat content changes- In all chemical reactions, the heat content of the reactants and the heat content of the products is never the same. Sometimes the difference is great and can be easily detected. At other times, the difference is slight and more difficult to detect.
Gas produced - Whenever a gaseous product forms in a liquid solution, bubbles can be seen. A colorless gas produced in a reaction of solids is much harder to detect.
Precipitate forms- Precipitates are insoluble products formed by a reaction taking place in a liquid solution. This insoluble product will eventually settle to the bottom, but might immediately appear by turning the clear solution cloudy.

Answer:

Endothermic.

Explanation:

I took the same test and this was the correct answer.

I hope this helps you!

When the temperature of water increases from room temperature to 90ºC the process of heating the water is... Question 9 options: A. adiabatic
B. exothermic
C. isothermic
D. endothermic
E. all of the above

Answers

Answer : The correct option is, (D) Endothermic

Explanation :

Adiabatic : It is a process in which a heat is constant. That means no heat is lost or gained by the system.

Isothermic : It is a process in which a temperature is constant.

Exothermic : It is a process in which heat released from system to surrounding. In this process, surrounding temperature increases and system temperature decreases.

Endothermic : It is a process in which heat required from the surrounding. In this process, surrounding temperature decreases and system temperature increases.

When the temperature of water increases from room temperature to 90ºC the process of heating the water is endothermic.

Hence, the correct option is, (D) Endothermic

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C? A. 0.002010812m3
B. 0.004021624m3
C. 0.002021624m3
D. 0.000010812m3

Answers

As per the question the volume of mercury  is given as 0.002 m^3 at 20 degree Celsius.

We are asked to calculate the volume of the mercury at 50 degree Celsius.

This problem is based on thermal expansion of matter.

Let us consider the initial and final volume of the mercury is denoted as -

                                  v_(1) \ and\ v_(2)

Let the initial and final temperature of the mercury is denoted as -

                                                                    T_(1)\ and \ T_(2)

As per question

v_(1) =0.002 m^3                v_(2) =?

T_(1) =20^0 C                      T_(2) =50^0 C

The change in temperature is

                                             T_(2) -T_(1)

                                         = 50^0 C -20^0 C

                                               = 30^0 C

Mercury is a fluid.So we have to apply volume expansion of liquid .

The coefficient of of volume expansion of mercury [ \gamma ] at 20 degree Celsius is 0.00018 per centigrade.

As per volume expansion of liquid,

                                       V_(T) = v_(1) [1 +\gamma [T_(2) -T_(1) ]]

Here V_(T) is the volume at T degree Celsius.

Hence volume at 50 degree Celsius is calculated as-

                               v_(2) =v_(1) [1+\gamma[50-30]]

                                       = 0.002[1+0.00018*30]

                                       =0.0020108m^3  [ans]

As per the options given in the question ,option A is close to the calculated value. So option A is right.


The answer to this question lies in understanding the Combined Gas Law in chemistry, which combines Boyle's, Charles', and Gay-Lussac's gas laws. This law shows the relationship between pressure, volume, and temperature of gases and is represented by the equation P1V1/T1 = P2V2/T2. Changes in pressure (P) and volume (V) are directly proportional to one another, but these are inversely proportional to changes in temperature (T). This question must assume that pressure is constant, so the Ps cancel out and the equation becomes V1/T1 = V2/T2. Additionally, temperature should be converted to Kelvins (K) by adding 273 to the temperature in Celsius (so 20 C = 293 K, and 50 C = 323 K). If V1 = 0.002 and T1 = 293 and T2 = 323, then we solve the equation as V2 = T2*V1/T1 or V2 = (323*0.002)/293, so the answer is approximately equal to 0.0022... or answer (C).

A football is kicked with a velocity of 18 m/s at an angle of 20. What is the balls acceleration in the horizontal direction as it flies through the air

Answers

If we perform all of our experiments on Earth and ignore
air resistance, then vertical acceleration is always 9.8 m/s²
downward, and horizontal acceleration is always zero.

My apex test just corrected my original answer of 9.8 m/s^2 to 0 m/s^2.  

A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency ___ that actually being produced by the object. higher than
lower than
same as

Answers

The answer is higher than.
A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency higher than that actually being produced by the object.

Why?
As the source of the waves is moving toward the observer, each of the successive wave crest is emitted from a position closer to the observer than the previous wave.
Thus each wave takes slightly less time to reach the observer than the previous wave. So, the time between the arrival of successive wave crests at the observer is reduced, increasing the frequency. 

Answer: higher than 

This phenomenon is known as the Doppler Effect. It occurs when a sound producing object is approaching towards an observer, it can be noticed that the sound is higher than what it really is. The sound usually fades as the object passes by.