Can you please help me with this question and i will give you a Brainiest

Answers

Answer 1

Answer:

The paperclip is a typical example of something with a mass of about a gram. The other items are significantly more massive. I'm in the US so I remember there are 28 grams in an ounce and 454 grams in a pound.

Answer: paperclip

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Which set represents the range of the function shown? {(8,2),(6,5),(4,7),(11,-2)}

A.) {-2, 2, 5, 7}

B.) {4,6,8,11}

C.) {(2,8),(5,6),(7,4),(-2,11)

D.) {-2,2,4,5,6,7,8,11}

Answers

Answer:

A.) {-2, 2, 5, 7}

Step-by-step explanation:

The range of a set of ordered pairs is the set of second numbers in the pairs.

Here, the second numbers are 2, 5, 7, -2. When written as a set, it is convenient (though not required) that they be written in numerical order:

{-2, 2, 5, 7} . . . . matches choice A

Answer:

A.) {-2, 2, 5, 7}

Step-by-step explanation:

Simplify, 5(2x + 3y) - 4(3x - 5y)

Answers

5(2x + 3y) - 4(3x - 5y)

5(2x) + 5(3y) - 4(3x) + 4(5y)

(10x + 15y) + (-12x + 20y)

(10x - 12x) + (15y + 20y)

-2x + 35y

Answer:

$-2x+35y$

Step-by-step explanation:

$5\left(2x+3y\right)-4\left(3x-5y\right)$

Expand:-

$\hookrightarrow 10x+15y-4\left(3x-5y\right)$

$\hookrightarrow 10x+15y-12x+20y$

Combine $10x$ and $-12x$ = $-2x$

$\hookrightarrow -2x+15y+20y$

Combine $15y$ and $20y$ = $35y$

$\hookrightarrow -2x+35y$

______________________

ProblemThe formula for the remaining volume of fuel in a car's tank is I-E\cdot DI−E⋅DI, minus, E, dot, D, where III is the initial volume of fuel, EEE is the fuel efficiency, and DDD is the distance traveled.

Carson drove a distance of 120120120 kilometers. He initially had 303030 liters of fuel, and his car's fuel efficiency is 100100100 cubic centimeters per kilometer.

What calculation will give us the estimated volume of fuel that remains in Carson's tank by the end of the drive, in liters?

Answers

Answer:

18 litres

Step-by-step explanation:

The formula for the remaining volume of fuel in a car's tank is expressed as;

V = I - E.D

where;

I is the initial volume of fuel,

E is the fuel efficiency, and;

D is the distance traveled.

Given

I = 30 litres

1m³ = 1000L

x = 30L

x = 30/1000

x = 0.03m³

I = 0.03m³

E = 100cm³/km

E = 100*10^-6m³/km

E = 10^-4m³/km

E = 10^-4m³/1000m

E = 10^-7m²

D = 120km

Convert km to metres

D = 120km = 120,000m

Substitute the results into the formula;

V = I - E.D

V = 0.03 - (10^-7)(120,000)

V = 0.03 - 0.012

V= 0.018 m³

Convert 0.018 m³ to litres

Since 1 m³ = 1000L

0.018 m³ = y

cross multiply;

y = 1000 * 0.018

y = 18 litres

Hence volume of fuel that remains in Carson's tank by the end of the drive is 18 litres

What is the first step of the following division problem?(8x^3 – x^2 + 6x + 7) ÷ (2x – 1)

A. Divide 8x^3 by 2x.
B. Divide 2x by 8x^3.
C. Divide 6x by 2x.
D. Divide 2x by 6x.