What’s the area of parallelogram A shown?

Answer:

x=-2±√14/1 is the answer

Step-by-step explanation:

2x²+12x+11=0

by using quadratic formula

x=(-b±√b²-4ac)/2a

here a=2,b=12,c=11

x={(-12)±√(12)²-4(2)(11)}/2

x=(-12±√144-88)/2

x=-12±√56/2

x=-6±2√14/2

x=-4±√14/2

x=-2±√14/1

i hope this will help you :)

Final answer:

The roots of the equation 2x^2+12x+11=0 are -1.13 and -4.87, found by substituting a, b, and c into the quadratic formula, simplifying, and solving for x.

Explanation:

The roots of the quadratic equation 2x^2+12x+11=0 can be found with the quadratic formula: x = [-b ± sqrt(b^2-4ac)] / (2a). Here, a=2, b=12, and c=11.

Substitute these into the formula to get: x = [-12 ± sqrt((12)^2 - 4*2*11)] / (2*2).

This becomes x = [-12 ± sqrt(144 - 88)] / 4.

Finally, we have x = [-12 ± sqrt(56)] / 4. The sqrt(56) can be simplified to approximately 7.48 for calculation.

Hence, the two roots of the equation are x = [-12 + 7.48] / 4 = -1.13 and x = [-12 - 7.48] / 4 = -4.87.

Learn more about Quadratic Equation Roots here:

brainly.com/question/26090334

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I really don't know what you are asking for but 280/40 is 7.

Answer:

7

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

12-2= m(2+3)

m= 10/5=2