What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make a larger set of waves in the same direction as that of the smaller waves. A label Wave motion is above the series of waves and an arrow next to the label points right. The particles will move up and down over large areas. The particles will move up and down over small areas. The particles will move side to side over small areas. The particles will move side to side over large areas.

Answers

Answer 1
Answer:

Answer:

→A←

Explanation:

D its incorrect in edge

Answer 2
Answer:

Answer:

D

Explanation:

The particles will move side to side over large areas


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Students run an experiment to determine the rotational inertia of a large spherically shaped object around its center. Through experimental data, the students determine that the mass of the object is distributed radially. They determine that the radius of the object as a function of its mass is given by the equation r = km², where k = 3. Which of the following is a correct expression for the rotational inertia of the object?

(A) m3
(B) 1.8 m3
(C) 3.6 m3
(D) 6 m3
(E) 9 m3

Answers

Answer:

(C) 3.6m^(5)

Explanation:

r=km^2\n = 3m^2

Since the object is a solid sphere, the equation for rotational inertia is:

I = (2)/(5)mr^2

I=(2)/(5)m(3m^2)^2=(2)/(5)*9m^5=3.6m^5

Final answer:

The provided question seems to have a discrepancy as the calculated value of rotational inertia for a spherical object with a given mass-radius relationship is 4.5M³, which does not match any of the supplied answer choices.

Explanation:

The question is asking for the correct expression for the rotational inertia of a spherically shaped object with mass distribution given by the radius as a function of mass (r = km² where k = 3). The rotational inertia, or moment of inertia, for a solid sphere is given by the formula ⅒MR², where M is the mass of the sphere, and R is its radius. Considering that R is defined by r = km², we substitute R with km² in the formula:

I = ⅒M(km²)² = ⅒Mk²m⁴ = ⅒Mk²M²

Since k = 3, we further simplify the expression:

I = ⅒M(3M)² = ⅒(3²)M³ = ⅒ × 9M³ = 4.5M³

However, none of the options (A) to (E) match the value 4.5M³, which indicates there may be an error in the supplied options or an error within the initial assumptions or question parameters. It's important to recheck the given data and the calculation steps to ensure accuracy. If the question and the parameters are indeed accurate as stated, additional information or clarification would be necessary.

If the diameter of the black marble is 3.0cm, and bye using the formula for volume, what is a good approximation if it’s volume? Record to the ones place

Answers

Complete question is;

If the diameter of the black marble is 3.0 cm, and by using the formula for volume, what is a good approximation of its volume?

Answer:

14 cm³

Explanation:

We will assume that this black marble has the shape of a sphere from online sources.

Now, volume of a sphere is given by;

V = (4/3)πr³

We are given diameter = 3 cm

We know that radius = diameter/2

Thus; radius = 3/2 = 1.5 cm

So, volume = (4/3)π(1.5)³

Volume ≈ 14.14 cm³

A good approximation of its volume = 14 cm³

A white blood cell has a diameter of approximately 12 micrometers or 0.012 um a model represents its diameter as 24 um what ratio of model size

Answers

Answer:

The ratio of the model size is 1 : 2000

Explanation:

Given

Real Diameter =  0.012 um

Scale Diameter =  24 um

Required

Determine the scale ratio

The scale ratio is calculated as follows;

Scale = (Real\ Measurement)/(Scale\ Measurement)

Substitute values for real and scale measurements

Scale = (0.012\ um)/(24\ um)

Divide the numerator and the denominator by 0012um

Scale = (1)/(2000)

Represent as ratio

Scale = 1 : 2000

Hence, the ratio of the model size is 1 : 2000

The ratio of the model size to the actual size is 1 : 2000. This means the model represents the white blood cell's diameter 2000 times larger than its actual size.

The ratio of the model size to the actual size can be calculated using the given measurements:

Actual Diameter = 0.012 um

Model Diameter = 24 um

Ratio = Model Diameter / Actual Diameter

Ratio = 24 um / 0.012 um

Ratio = 2000

So, the ratio of the model size to the actual size is 1 : 2000. This means the model represents the white blood cell's diameter 2000 times larger than its actual size.

Learn more about white blood from the link given below.

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A block m1 rests on a surface. A second block m2 sits on top of the first block. A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.(a)
What is the normal force exerted by the surface on the bottom block? (Use the following as necessary: m and g as necessary.)

Answers

(a) The normal force exerted by the surface on the bottom block is N1 = 2mg.

Given that,

  • A block m1 rests on a surface.
  • A second block m2 sits on top of the first block.
  • A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.

Based on the above information, we can say that the N1 is 2mg.

Learn more: brainly.com/question/17429689

Answer:

N = 2mg

Explanation:

Assuming the surface is horizontal

The surface must provide enough normal force to prevent the masses from accelerating in the vertical direction.

Which equation represents inverse proportionality?Responses

y=m/x
y equals m divided by x

y=mx2+b for nonzero b
y equals m x squared plus b for nonzero b

y=mx
y equals m x

y=mx2

Answers

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Inverse proportionality means that the two terms should be proportional to inverse of each other ~

That is :

\qquad \sf  \dashrightarrow \: y \propto (1)/(x)

And according to given options, only option 1 shows inverse proportionality. where y is inversely proportional to x and m is proportionality constant.

\qquad \sf  \dashrightarrow \: y = (m)/(x)

Final answer:

The equation that represents inverse proportionality in mathematics is y=m/x, where y is inversely proportional to x, and m is the constant of proportionality.

Explanation:

In mathematics, inverse proportionality, or inversely proportional, is a concept where one variable increases when the other variable decreases, and vice versa. It lies at the heart of various mathematical and real-world applications. The equation y=m/x represents inverse proportionality, where 'y' is inversely proportional to 'x'. In this equation, 'm' is the constant of proportionality. As 'x' increases, 'y' decreases given 'm' remains unchanged and vice versa.

Learn more about Inverse Proportionality here:

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A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the railing with his outstretched arms. During the stopping process, his center of mass moves 30 cm toward the railing. (a) What is the change in the kinetic energy of his center of mass during this process? (b) What average force must he exert on the railing?

Answers

Answer:

(a). The change in the kinetic energy of his center of mass during this process is -495 J.

(b). The average force is 1650 N.

Explanation:

Given that,

Mass = 110 kg

Speed = 3.0 m/s

Distance = 30 cm

(a). We need to calculate the change in the kinetic energy of his center of mass during this process

Using formula of kinetic energy

\Delta K.E=K.E_(2)-K.E_(1)

\Delta K.E=(1)/(2)mv_(f)^2-(1)/(2)mv_(i)^2

Put the value into the formula

\Delta K.E=(1)/(2)*110*0^2-(1)/(2)*110*(3.0)^2

\Delta K.E=-495\ J

(b). We need to calculate the average force must he exert on the railing

Using work energy theorem

W=\Delta K.E

Fd=\Delta K.E

F=(\Delta K.E)/(d)

Put the value into the formula

F=(-495)/(30*10^(-2))

F=-1650\ N

The average force is 1650 N.

Hence, (a). The change in the kinetic energy of his center of mass during this process is -495 J.

(b). The average force is 1650 N.

Answer

given,

mass of ice hockey player = 110 Kg

initial speed of the skate = 3 m/s

final speed of the skate = 0 m/s

distance of the center of mass, m = 30 cm = 0.3 m

a) Change in kinetic energy

    \Delta KE = (1)/(2)mv_f^2 - (1)/(2)mv_i^2

    \Delta KE = (1)/(2)m(0)^2 - (1)/(2)* 110 * 3^2

    \Delta KE = - 495\ J

b) Average force must he exerted on the railing

     using work energy theorem

      W = Δ KE

      F .d  = -495

      F x 0.3  = -495

      F = -1650 N

the average force exerted on the railing is equal to 1650 N.