Solve the problem- 12.4 divided by two-fifths

Answers

Answer 1

Answer: 12.4/2/5
12.4/.4
124/4
31

Answer 2

Answer: Hi

-12.4/2.5
= -4.96

I hope that's help !

Related Questions

Which is a factor of x^2 + 8x – 48?(x – 6) (x + 4) (x – 16) (x + 12)
Which are the roots of the quadratic function f(b) = b2 – 75? Check all that apply.
Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 1.5 m/s, how fast is the area of the spill increasing when the radius is 30 m?
A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal force n acting on the car when it is at the top of the arc. (Use any variable or symbol stated above along with the following as necessary: m and g.) n
Prove that cos(a-b) - cos(a+b) = 2sina sinb

I'm justing starting geometry honors, and I would like to know how to pass this class?! Is it easy or hard? HELP!!

Answers

Its different for different people but for me it was easy.

I found geometry to be very easy it is a lot of fun brain teasers if u CAN do logic puzzles u will do well and enjoy it if you have a good teacher

What is 155 divided by 5 equals ?

Answers

The result of 155 divided by 5 is 31.

To calculate 155 divided by 5, we can perform long division to find the quotient.

Step 1: Set up the long division:

___________

5 | 155

Step 2: Determine how many times 5 can go into the first digit of 155 (which is 1). It goes 0 times, so we write 0 above the division bar.

___________

5 | 155

Step 3: Bring down the next digit (5) and place it next to the 0. Now we have 15.

___________

5 | 155

Step 4: Determine how many times 5 can go into 15. It goes 3 times (5 x 3 = 15). Write 3 above the division bar.

___________

5 | 155

-15

Step 5: Subtract 15 from 15 to get 0. Bring down the next digit (5).

___________

5 | 155

-15

Step 6: Determine how many times 5 can go into 0. It goes 0 times, so we write 0 above the division bar.

__________

5 | 155

-15

Step 7: Since there are no more digits to bring down and no remainder left, the division is complete. The quotient is 31.

Therefore, 155 divided by 5 equals 31.

To know more about divided:

brainly.com/question/15381501

#SPJ6

the answer is 31. 5 goes into 15 3 times and 5 goes into 5 1 time so its 31

What’s the x-intercepts

Answers

The x-intercepts are -6 (put the radical over the 6) and 6 (put the radical over it) or if you need the simplified version they are -2.44 and 2.44

Flyball is a relay race for dogs. In each of the four legs of the relay, a dog jumps over hurdles, retrieves a ball from a fly box, and runs back over the hurdles. The distance of the relay race is 51 feet. The collie starts the course 0.3 second before the sheepdog. The collie is running 23.4 feet per second while the sheepdog is running 24 feet per second. a. Let t represent the time (in seconds) it takes the collie to un the last leg . Write and solve an equation to find the number of seconds after which the sheepdog would catch up with the collie.

Answers

It would take 11.7 seconds for the sheepdog to catch up with the collie.

To determine the number of seconds after which the sheepdog would catch up with the collie, knowing that the distance of the relay race is 51 feet, and the collie starts the course 0.3 second before the sheepdog, and the collie is running 23.4 feet per second, while the sheepdog is running 24 feet per second, the following calculation must be performed:

(23.4 x 0.3) = 7.02
24 - 23.4 = 0.6
7.02 + 23.4X = Y
24X = Y
7.02 / 0.6 = 11.7
7.02 + 23.4 x 11.7 = 280.8
24 x 11.7 = 280.8

Therefore, it would take 11.7 seconds for the sheepdog to catch up with the collie.

Learn more in brainly.com/question/14966099

Your literature class will read 4 novels this year, chosen by class vote from a list of 7 possible books offered by the teacher.a) How many different ways could the course unfold, given that it probably matters what order you read the books in?
b) How many different choices of books could the class make?
a) The number of different ways the course could unfold is

Answers

Answer:

a) 840 different ways

b) 35 different choices of books

Step-by-step explanation:

We know that our literature class will read a total of 4 novels this year.

All novels chosen by class vote from a list of 7 possible books offered by the teacher.

Wherever we have an experiment $''N''$ which is formed by sub - experiments that can occurred in $m_(1),m_(2),...,m_(n)$ ways, the total number of ways in which the whole experiment $''N''$ can be developed is :

$m_(1)$ x $m_(2)$ x ... x $m_(n)$

Then, for a) if it matters what order we read the books in, the total number of different ways could the course unfold is :

$(7).(6).(5).(4)=840$ (I)

Because for the first book there are 7 different choices. Now, given that we choose the first book, we only have 6 different choices for the second one.

Continuing with the idea, we deduce the equation (I).

For item b) :

Wherever we have $''n''$ different objects and we want to find the ways that we can choose $''r''$ objects from that group, we need to use the combinatorial number.

We define the combinatorial number as :

$nCr=\left(\begin{array}{c}n&r\end{array}\right)=(n!)/(r!(n-r)!)$

Then, if we apply this to the problem, the total different choices of books if we want 4 novels voting from a total of 7 possible books is :

$7C4=(7!)/(4!(7-4)!)=35$

a) 840 different ways

b) 35 different choices of books

Final answer:

The number of different ways the course could unfold is 210, and the number of different choices of books the class could make is 35.

Explanation:

The number of different ways the course could unfold is equal to the number of permutations of the 4 books chosen from the list of 7. This can be calculated using the formula for permutations: P(n, r) = n! / (n - r)!. In this case, n = 7 (the number of books) and r = 4 (the number of books chosen). Using the formula, we get P(7, 4) = 7! / (7 - 4)! = 7! / 3! = 7 imes 6 imes 5 = 210.

The number of different choices of books the class could make is equal to the number of combinations of the 4 books chosen from the list of 7. This can be calculated using the formula for combinations: C(n, r) = n! / (r! (n - r)!). In this case, n = 7 (the number of books) and r = 4 (the number of books chosen). Using the formula, we get C(7, 4) = 7! / (4! (7 - 4)!) = 7! / (4! imes 3!) = (7 imes 6 imes 5) / (4 imes 3 imes 2) = 35.

Learn more about Combinations and Permutations here:

brainly.com/question/19917646

#SPJ3

The first term of an arithmetic progression is -3 and the common difference is 8. What is the 28th term? 213
226
229
220

Answers

Hello,

a(28)=a(0)+27*8=-3+27*8=213

Answer A

Other Questions

Lucy needs to hire a host. host a is offering his services for an initial $75 in addition to $13.75 per hour. hostess b is offering her services for an initial $80 in addition to $12.25 per hour. when will the two hosts charge the same amount of money? if necessary, round your answer to the nearest tenth.

Tyler returned $500 worth of merchandise within the discount period. The entry to record the return would be placed into what account?

There are 3 red gumdrops and 2 green gumdrops in a small jar.Also, 4 pieces of butterscotch candy and 1 piece of cinnamon candy are in another jar. If craig draws one piece of candy from from each jar without looking? what is the probability that he will get a red gumdrop and a piece of cinammon candy?

What is bigger 10 pounds or 10 kilograms