A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal force n acting on the car when it is at the top of the arc. (Use any variable or symbol stated above along with the following as necessary: m and g.) n

Answers

Answer 1

Answer:

Answer:

$n=m(g-(v^(2))/(r))$

Step-by-step explanation:

If a car is moving across a circular bridge, made in the shape of a circular arc then the force that balances the car when it is on the top of arc will be

n + F = mg

Where n = normal force acting on the car

F = centripetal force

m = mass of the car

We know centripetal force $F=(mv^(2))/(r)$

where m = mass of the car

v = velocity of the car on the top of the arc

r = radius of the arc

Therefore, the expression for the normal force 'n' will be

$n+(mv^(2))/(r)=mg$

$n=mg-(mv^(2))/(r)$

$n=m(g-(v^(2))/(r))$

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Answers

you divide 240 into 12 and get your answer. the answer is 20

: ) all you have to do is divide 240 into 12 . Hope that helped!

What is the LCD of 1/3 and 1/4?

Answers

Howdy there! :) the answer to your question is 12. 3/12 and 4/12.

Hope I helped! ;)

The lowest common denominator is 12.

1/3 = 4/12
1/4 = 3/12

For what values of x is the expression below defined?√2x^2 divide by √5x

a/x=0
b.x<0
c.x>0
d.x<1

Answers

$√(2x^2):√(5x)\n\n2x^2\geq0\ \wedge\ x > 0\n\nx^2\geq0\ \wedge\ x > 0\n\nx\in\mathbb{R}\ \wedge\ x > 0\Rightarrow x > 0\ (x\in\mathbb{R^+})\n\nAnswer:c.\ x > 0$

A bag contains 6 green marbles, 9 red marbles, 7 white marbles, and 3 black marbles. What is the probability of drawing a red marble out of the bag? A. 1/18

B. 9/16

C. 9/25

D. 1/4

Answers

The answer is C. 9/25.

There are in total 25 marbles:
6 green + 9 red + 7 white + 3 black = 25 marbles.

There are 9 red marbles of the total 25 marbles. You can draw 9 red Thus, the probability of drawing a red marble out of the bag is 9 out of 25, which is 9/25.

Which relation is not a function?A(2,9), (-1,-5), (1,5), (5,0), (12, 3)
B. (-3, 1), (6,2), (8,3), (6,4), (3, 5)
C. (5, 1), (4,2), (3, 3), (2, 4), (1,5)
D. (7,2), (5,3), (3, 4), (1,5),(-1, 6)

Answers

Answer:

B. (-3, 1), (6,2), (8,3), (6,4), (3, 5)

Step-by-step explanation:

This relation is not a function because the number 6 repeats twice.

I need help finding the answer to this math problem:
(m³+m²n)+(mn²+n³)

Answers

$(m^3+m^2n) + (mn^2+n^3)$

Remove parentheses : $(a) = a$

$= m^3+m^2n + mn^2 + n^3$

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