MATHEMATICS HIGH SCHOOL

Which are the roots of the quadratic function f(b) = b2 – 75? Check all that apply.

Answers

Answer 1

Answer: $f(b)=b^2-75\nf(b)=0\nb^2-75=0\nb^2=75\nb=\pm√(75)=\pm√(25*3)=\pm5√(3)$

Answer 2

Answer:

Answer:

The roots of the given quadratic function $f(b) = b^2-75$ is $5√(3)\quad$ and $-5√(3)\quad$

Step-by-step explanation:

Given: Quadratic function $f(b) = b^2-75$

We have to find the roots of the given quadratic function $f(b) = b^2-75$

Since, roots of the quadratic equation is the points where the value of function is zero.

That is f(x) = 0

Consider the given function $f(b) = b^2-75$

Put f(b) = 0

$\Rightarrow b^2-75=0$

Simplify , we have,

$\Rightarrow b^2=75$

Taking square root both side, we have,

$\Rightarrow b=√(75)$

Simplify we have,

$\Rightarrow b=\pm 5√(3)\quad$

Thus, The roots of the given quadratic function $f(b) = b^2-75$ is $5√(3)\quad$ and $-5√(3)\quad$

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Two equations are given below:m + 4n = 8 m = n − 2 What is the solution to the set of equations in the form (m, n)? (4, 6) (2, 4) (0, 2) (6, 8)
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In the next 3 hours, the crew was digging at a rate of -2.5 feet each hour. During the last 2 hours, the crew slowed to a rate of -2.25 feet each hour. What number would they record for the location after the 8 hours?

Answers

To calculate the location after 8 hours of digging at different rates, you can sum up the distances they dug during each time period.

In the first 3 hours, they dug at a rate of -2.5 feet per hour, so they dug a total of:
3 hours * (-2.5 feet/hour) = -7.5 feet

In the next 2 hours, they dug at a rate of -2.25 feet per hour, so they dug a total of:
2 hours * (-2.25 feet/hour) = -4.5 feet

Now, add these two distances together to find their location after 8 hours:
-7.5 feet + (-4.5 feet) = -12 feet

So, they would record a location of -12 feet after 8 hours of digging.

You've decided you want a plant for your room. At the gardening store, there are 4 different kinds of plants (tulip, fern, cactus, and ficus) and 4 different kinds of pots to hold the plants (clay pot, plastic pot, metal pot, and wood pot). If you randomly pick the plant and the pot, what is the probability that you won't get a clay pot or a cactus?

Answers

There are 4×4 = 16 different combinations of plant and pot. Of those, 7 are either clay pot or cactus. Thus the probability you won't get a clay pot or a cactuis is 9/16.

Answer:

9/16

Step-by-step explanation:

Compare the two fractions using <, >, or =.
1/2____7/15

Answers

1/2 < 7/15
because
15/ 30 < 14/ 30
(these are equivalent fractions- they have the same denominator so that it is easier to compare)

Answer:

1/2 < 7/15

Step-by-step explanation:

If you flip three fair coins, what is the probability that you’ll get a head on the first flip, a tail on the second flip, and another head on the third flip?

Answers

Answer:

1/8.

Step-by-step explanation:

Probability of getting a head in one throw = probability of getting a tail in one throw = 1/2.

Prob (H T H) = 1/2 * 1/2 * 1/2 = 1/8.

NOTE: The probabilities are multiplied because the 3 events are independent.

1+4 =5 2+5=12 3+6=21 8+11=

Answers

1 + 4 = 5
2 + 5 + 5 = 12
3 + 6 + 12 = 21
8 + 11 + 21 = 40
So the missing number is 40 and that we can see from the above deduction. Actually the number that we get from the previous addition is added with the next addition to get the result. This is the link between the equations.

It would be 40 because it adds the sum of the equation before it

7 times as much as the sum of 1/3 and 4/5

Answers

$7( (1)/(3) + (4)/(5) )$

$=7( (1(5))/(3(5)) + (4(3))/(5(3)) )$

$=7( (5)/(15) + (12)/(15) )$

$=7( (17)/(15))$

$=(7)/(1) ( (17)/(15))$

$=(119)/(15)$

$= 7(14)/(15)$ ≈ 7.93

¹¹⁹/₁₅ or 7¹⁴/₁₅ or 7.93

Further explanation

The Problem:

7 times as much as the sum of $(1)/(3)$ and $(4)/(5)$
Write an expression to match, and then solve it.

The Process:

Here are some early expressions that need attention.

one-third is $\boxed{(1)/(3)}$
four-fifth is $\boxed{(4)/(5)}$
the sum of $(1)/(3) \ and \ (4)/(5)$ is $\boxed{(1)/(3) + (4)/(5)}$

Let us write an expression to match for 7 times as much as the sum of $(1)/(3)$ and $(4)/(5)$

$\boxed{\boxed{ \ 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }}$

Let us calculate the operation in parentheses at first.

$\boxed{(1)/(3) + (4)/(5)}$

A least common multiple of 3 and 5 is 15. We use to equate the denominator.

$\boxed{(1 * 5)/(3 * 5) + (4 * 3)/(5 * 3)}$

$\boxed{(5)/(15) + (12)/(15)}$

$\boxed{(17)/(15)}$

And now we solve the full expression.

$\boxed{ \ = 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }$

$\boxed{ \ = 7 * (17)/(15) \ }$

We do not cross out 7 and 15 because they both cannot be divided.

$\boxed{ \ = (119)/(15) \ }$

$\boxed{\boxed{ \ = (119)/(15) \ }}$

In mixed fraction:

$\boxed{ \ (119)/(15) = \ ? \ }$

$\boxed{ \ = (105)/(15) + (14)/(15) \ }$

$\boxed{ \ = 7 + (14)/(15) \ }$

$\boxed{\boxed{ \ = 7(14)/(15) \ }}$

In decimal:

$\boxed{ \ 7(14)/(15) = \ ? \ }$

$\boxed{ \ (14)/(15) = 0.93 \ }$

$\boxed{ \ = 7 + (14)/(15) \ }$

$\boxed{ \ = 7 + 0.93 \ }$

$\boxed{\boxed{ \ = 7.93 \ }}$

$\boxed{\boxed{ \ Thus, \ the \ result \ is \ (119)/(15) \ or \ 7(14)/(15) \ or \ 7.93 \ }}$

- - - - - - - - - -

Quick Steps:

$\boxed{ \ = 3 * \bigg((1)/(3) + (4)/(5) \bigg) \ }$

$\boxed{ \ = 3 * \bigg((5 + 12)/(15) \bigg) \ }$

$\boxed{ \ = 3 * \bigg((17)/(15) \bigg) \ }$

$\boxed{\boxed{ \ = (119)/(15) \ }}$

$\boxed{\boxed{ \ = 7(14)/(15) \ }}$

$\boxed{\boxed{ \ = 7.93 \ }}$

Learn more

7 copies of the sum of 8 fifths and 4 brainly.com/question/961462
$(2)/(3)$ of the product of $(3)/(8)$ and 16 brainly.com/question/961462
15 times as much as 1 fifth of 12 is brainly.com/question/348151

Keywords: 7 times, as much as, the sum of 1/3 and 4/5, write an expression to match, and then solve, the result, in mixed fraction, decimal, ¹³/₄ or 3¹/₄ or 3.25

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