4 consecutive odd integers whose sum is 232 are : 55, 57, 59, 61
Let the first integer be x and x is an odd number.
Let Four consecutive odd integers are;
x, x + 2, x + 4, x + 6
(x) + (x + 2) + (x + 4) + (x + 6) = 232
4x + 12 = 232
4x = 232 - 12
4x = 220
x = 220/4
x = 55
x + 2 = 55 + 2 = 57
x + 4 = 55 + 4 = 59
x + 6 = 55 + 6 = 61
The numbers are : 55, 57, 59, 61
Learn more about the concept here;
#SPJ2
There are 132 ways of selecting them.
permutations and combinations, the various ways in which objects from a set may be selected, generally without replacement, to form subsets. This selection of subsets is called a permutation when the order of selection is a factor, a combination when order is not a factor.
According to the question,
So if there are 12 trumpet players, then teacher may take the leader, then, after he's taken, there are 11 ways of picking co-leader.
Multiply both numbers of possibilities
= 12× 11
=132
Hence ,There are 132 ways of selecting them.
To learn more about permutation and combination from here
#SPJ2
Rational root theorem is used to determine the possible roots of a function.
The potential roots are: -3 and 3/2
The function is given as:
For a function,
The potential roots are:
So, we have:
---- factors of 3
---- factors of 6
The potential roots are:
From the options, the potential roots are:
Read more about rational roots theorem at:
Answer:
-3 and 3/2
Step-by-step explanation:
6x^3 - 2x^2 + x + 3
possible roots are p/q where p = factors of 3 and q are factors of 6
So from the 4 choices possible roots are -3 and 3/2
Answer: vertex: (1,-9); intercepts: x=4,-2
Step-by-step explanation:
Just got it wrong on ap3x so I could give y’all the right answer
t's gonna be a long problem: Remember PEMDAS
3n-5=8(6+5n)
3n-5= 48 + 40n Distribute 8 into parenthesis
3n-3n-5=48+40n-3n Put variable on one side.
-5-48=48-48+37n Isolate the variable
-43/37=37n/37 Isolate variable more
-1.162=n Simplify
The answer is repeating; that is a shortened version.