HELP !!The equation of the graphed line in point slope form is (blank) and its equation in slope intercept form is (blank)

first blank
y-0=-3/5(x-3)
3y=-5(x-3)
y-3=3/5(x-0)

second blank
y=-9/5x+3/5
5y=-3(x-3)
y=-3/5x+9/5

Answers

Answer 1

Answer: I think, I not know is good but...

first blank is:
~ Y= -3/5x - 3.5
~ Y= -5/3 + 5
~ Y = 3/5x - 3

Second blank
~ -9/5x + 3/5 or 0.6
~ Y = -3/5X + 1.8
~ Y = -3/5x + 1.8

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Find the range of the following piecewise function. A. [2,16)

B. (2,16]

C. [2,∞)

D. (2,∞)

Answers

Answer:

None of the Above

Step-by-step explanation:

The range is [2, ∞) excluding (2, 7) and [11, 16). No part of the piecewise function will give f(x) = 5, for example.

5. Which point lies on the line: y - 4 = -3(x + 2)?

Answers

Answer:

(- 2, 4 )

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = - 3(x + 2) ← is in point- slope form

with (a, b ) = (- 2, 4 )

Lim -> 0 sin(2x) /(x*cos(x) )

help

Answers

sin (2x) can be written like:sin (2x) = 2sin(x)cos(x)
substituting this expresion in the original one:sin(2x) /(x*cos(x) =2sin(x)cos(x)/x*cos(x)=2sinx/x
taking limits, and noticing that lim as x->0 of sinx/x=1:lim 2sinx/x=2*1=2x->0

What is the difference between class limits and class boundaries?

Answers

Answer:

Step-by-step explanation:

Class limits are the minimum data value(lower) and maximum data value (upper) that a class can contain. They usually have the same numerical accuracy as the original data values.

Class boundaries are boundary lines that mark or separate where one class stops and the other begins. The lower class boundary of a given class is got by finding the average of the previous upper class limit and the given lower class limit while the upper class boundary is got by finding the average of the given upper class limit and the next lower class limit.

Final answer:

Class limits and class boundaries are statistical terms used in frequency distributions. Class limits are the smallest and largest values of a class, while class boundaries are the points separating one class from another.

Explanation:

The terms class limits and class boundaries are used in the field of statistics, particularly in the context of frequency distributions. Class limits are the smallest and largest values that can fall within each class in a frequency distribution, whereas class boundaries are the points that separate one class from another, and each boundary forms the end of one class and the start of the next.

For example, imagine you are analyzing the frequency of test scores and you have a class with limits of 80 and 89. These limits are the smallest and largest scores that fit into that class. However, the class boundaries are 79.5 and 89.5, serving as the dividing lines between this class and the next ones.

Learn more about Class Limits and Class Boundaries here:

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Calculate the slope of a Line that intersects point (6,2) And ((-4,-3). A.1/2. B.2/3 C.4/5. D.7/8. For me the answer are a. Please help me.

Answers

$A(6;\ 2);\ B(-4;-3)\n\nslope:\n\nm=(y_B-y_A)/(x_B- x_A)\n\nm=(-3-2)/(-4-6)=(-5)/(-10)=(1)/(2)$

$(6,2), \ \ \ (-4, -3) \n \n Slope \ Formula : \n \nm= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm= ( -3-2)/(-4-6) =(-5)/(-10)=(1)/(2) \n \n Answer : \ A. \ \ (1)/(2)$

Jon paid $20 towards the cost of an $80 sweater. Write a numeric equation to show how much he still owes on the sweater.