Answer:
It measures the probability of observing your test statistic, assuming the null hypothesis is true.
Step-by-step explanation:
The p-value, also known as the probability value measures the probability of observing your test statistic, assuming the null hypothesis is true.
A low p-value means a higher chance of the null hypothesis to be true.
It lies between 0 and 1. A small p-value indicates fewer chances of the null hypothesis to be true.
Answer: The answer is 1,024.
Explanation: 32^2 is 32 x 32, which is 1,024.
COMPLETE QUESTION:
Chris went on a vacation for a week and asked his brother Paul to feed his old cat Charlie. But Paul is forgetful, and Chris is 70% sure Paul will forget to feed his cat. Without food, Charlie will die with probability 0.5. With food, he will die with probability 0.03. Chris came back from vacation and found Charlie alive. What is the probability that Paul forgot to feed Charlie (round off to third decimal place)?
Answer:
The probability that Paul forgot to feed charlie is 0.546
Step-by-step explanation:
Lets denote F the event 'Paul forgot to feed Charlie', and L the even 'Charlie is alive', we have
P(F) = 0.7
P(L|F) = 1-0.5 = 0.5
P(L|F^c) = 1-P(L^c|F^c) = 1-0.03 = 0.97
We want to calculate P(F|L). We will use Bayesformula at the start and the theoremoftotalprobability to calculate P(L).
Given that Charlie is alive, the probability that Paul forgot to feed charlie is 0.546.
Answer:
P = 0.546
Step-by-step explanation:
Hi,
This is a question of conditional probability, which means to find probability of a situation given that another event has already occured:
In this question, we need to find the probability of Charlie being alive if not fed, with the data given below:
From this data, we can infer the following:
The probability of Charlie staying alive in both cases:
We need to find the probability when not fed:
(Remember this is the variation of the conditional probability formula as per our requirement in this question).
Hence, the probability of Charlie being alive when Paul forgets is 0.546.
Answer:
Average quality rating was 4.54+-0.00549
The estimate for the average quality rating from the production line, given this sample, is 4, with a degree of uncertainty expressed by a 95% confidence interval of 4 ± 0.031. The confidence interval represents a range whereby we can be 95% confident that the true mean lies within.
Since you have the average (mean) quality rating and standard deviation from a sample size of 1000 widgets, we can use these statistics to establish an estimate for the entire production line. The estimate of the average quality rating is given as 4. However, to account for the uncertainty of our estimate due to it being based upon a sample rather than the entire population, we use the concept of a confidence interval.
The formula for a confidence interval is mean ± z* (standard deviation/sqrt(n)), where z is a z-score corresponding to our desired level of confidence. For simplicity, we can use a z-score of 1.96 to represent a confidence level of 95%.
Therefore, the uncertainty in this estimate (at 95% confidence) is calculated as:1.96 * (0.5/sqrt(1000)), approximately equal to 0.031. So the confidence interval for the average quality of widgets is 4 ± 0.031.
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The terms of an expression 4x² – 3xy are:
(a) 4x and -3xy (b) 4x² and 3xy
(c) 4x² and -xy
(d) x
Answer:
(b) 4x² and 3xy
Step-by-step explanation:
The terms of an expression 4x² – 3xy are:
The terms are the factors of the expression, which are 4x² and -3xy. The signal is not counted as a term. So the correct answer is given by option b.
b. 2
c. -2x
d. -2
please explain
Answer:
-2
Step-by-step explanation:
Answer:
L1 and L2 are skew
Step-by-step explanation:
Since the equation of the line is
L1:x=9+6t,y=12-3t,z=3+9t
L2:x=4+16s, y=12-8s, z=16+20s
then if they intersect each other , they will have both in that point P=(xp , yp ,zp) then
1)9+6t = 4+16s
2) 12-3t =2-8s
3) 3+9t = 16+20s
adding 2*2) to 1)
9+6*t + 24-6t = 4+16*s + 4-16*s
33 = 8
since this is not possible , the error comes from our assumption that the lines intersect each other
then they are skew or parallel. They are parallel if their corresponding vectors are parallel , that is
L1 (x,y,z) = (9,12,3) + (6,-3,9)*t
L1 (x,y,z) = (4,2,16) + (16,-8,20)*t
then if they are parallel
(16,-8,20)= k*(6,-3,9)
16=6*k
-8 = -3*k
20= 9*k
since there is no k that satisfy for x , y and z simultaneously then L1 and L2 are not parallel
therefore L1 and L2 are skew
The lines L1 and L2 are neither parallel nor intersecting. Upon comparing their direction vectors and attempting to find a common solution, it is determined that they are skew.
In order to determine whether two lines in three dimensions are parallel, skew, or intersecting, we compare their direction vectors. The given lines L1 and L2 are in the form of parametric equations. The direction vectors for the lines are d1 = <6, -3, 9> for L1 and d2 = <16, -8, 20> for L2. To determine if they are parallel, we check if there is a constant ratio between the corresponding terms. This isn't the case here, so the lines are not parallel.
For skew lines, they neither intersect or are parallel. Since we have already confirmed the lines are not parallel, to confirm if they are skew we must try to find a common solution (point of intersection). If we cannot, then they are skew. However, solving the equations does not give a common solution, so they do not intersect either. Hence, the lines are skew.
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