A gas Syringe contains 42.3 milliliters of a gas at 98.15°C. Determine the volume that the gas will occupy if the temperature is decreased to -18.50°C.

Answers

Answer 1
Answer:

The volume that the gas will occupy is "29.00 mL".

According to the question,

Volume,

  • V_1 = 42.3 \ mL
  • V_2 = ?

Temperature,

  • T_1 = 98.15^(\circ) C

             = 371.15 \ K

  • T_2 = -18.50^(\circ) C

             = 254.5 \ K

As we know the relation,

(V_1)/(T_1) = (V_2)/(T_2)

or,

V_2 = (V_1* T_2)/(T_1)

By substituting the values, we get

→      = (41.3* 254.5)/(371.15)

→      = (10765.35)/(371.15)

→      = 29.00 \ mL

Thus the above answer is right.  

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Answer 2
Answer: V₁ = 42.3 mL

T₁ ( K ) = 98.15ºC + 273 = 371.15 K

V₂ = ?

T₂ ( K) = -18.50ºC + 273 = 254.5 K

V₁ / T₁  = V₂ / T₂

42.3 / 371.15 =  V₂ / 254.5

371.15 x V₂ = 42.3 x  254.5

371.15 x V₂ = 10765.35

V₂ = 10765.35 / 371.15

V₂ = 29.00 mL

hope this helps!


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Answers

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Explanation:

Hello,

In this case, we use the ideal gas equation to compute the requested temperature as shown below and considering the proper units:

PV=nRT\nT=(PV)/(nR)=(1950mmHg*(1atm)/(760mmHg)*15500mL*(1L)/(1000mL) )/(1.2mol*0.082 (atm*L)/(mol*K) ) \nT=404.16K=13.1^oC

Best regards.

Replace  with  

1950

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1950mmHg and simplify.

1.2

,

1950

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,

15

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500

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