Why aren’t there more craters on earth than the moon.

Answers

Answer 1

Answer:

Answer:

Earths atmosphere causes most small to medium meteors to burn up disintergrate before hitting the earth the moon does not have a protective atmosphere

Related Questions

A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find the initial speed of the rock.a. 3m/sb. 30.3 m/sc. None of the above
The pedals on a bicycle give a mechanical advantage by allowing you to turn the pedals a __________ distance to turn the __________ circumstance of the wheels.
If you know the distance of an earthquake epicenter from three seismic stations, how can you find the exact location of the epicenter of the earthquake.
A long, thin superconducting wire carrying a 17 A current passes through the center of a thin, 3.0-cm-diameter ring. A uniform electric field of increasing strength also passes through the ring, parallel to the wire. The magnetic field through the ring is zero.a. At what rate is the electric field strength increasing? b. is the electric field in the direction of the current or opposite to the current?
Which statement best describes how the first quatrain relates to the second quatrain? The first shows the beloved’s actions; the second describes how she imitates them. Both the first and the second show the actions of the speaker and the beloved. The first shows the speaker’s actions; the second shows the beloved’s opposition to them. The first shows the speaker’s sadness; the second shows the beloved’s anger.

In college softball, the distance from the pitcher's mound to the batter is 43 feet. If the ball leaves the bat at 110 mph , how much time elapses between the hit and the ball reaching the pitcher?

Answers

The time taken should be 0.000074 hours or 0.2664 seconds.

Calculation of the time taken:

Here we assume the time be t

And, The distance from the pitcher's mound to the batter is 43 feet, d = 43 feet = 0.00814 miles

So, the following formula should be used.

$= 0.00814 / 110$

= 0.000074 hours or 0.2664 seconds.

Learn more about the time here: brainly.com/question/15094745

Explanation:

It is given that,

The distance from the pitcher's mound to the batter is 43 feet, d = 43 feet = 0.00814 miles

Speed with which ball leaves the ball, v = 110 mph

Let t is the time elapses between the hit and the ball reaching the pitcher. It is given by :

$t=(d)/(v)$

$t=(0.00814)/(110)$

t = 0.000074 hours

t = 0.2664 seconds

So, the time between the hit and the ball reaching the pitcher is 0.2664 seconds. Hence, this is the required solution.

A 4 kg bowling ball accelerates 1 m/s2. what is the net force on the ball?

Answers

Answer:4N

Explanation:

mass=4kg

Acceleration=1m/s^2

Force=mass x acceleration

Force=4 x 1

Force=4N

An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and inductor, or a capacitor. At time t = 0 the voltage is zero. At time t = T/4 the current in the unknown element is equal to zero, and at time t = T/2 the current is I = -Imax, where Imax is the current amplitude. What is the unknown element?

Answers

Answer:

This satisfy the above given condition so we can say that this capacitor.

Explanation:

Let's take one by one option and check whether is wrong or right

For inductor:

$I=I_osin(wt-(\pi )/(2))$

Given that at t=T/4 ,I=0 and we know that

$w=(2\pi )/(T)$

So at T/4

$I=I_osin((2\pi )/(T)* (T)/(4)-(\pi )/(2))$

I=0 A

At t=T/2

$I=I_osin((2\pi )/(T)* (T)/(2)-(\pi )/(2))$

$I=I_o$

It means that this not a indutor.

For capacitor:

$I=I_osin(wt+(\pi )/(2))$

At T/4, I=0

At t=T/2

$I=I_osin((2\pi )/(T)* (T)/(2)+(\pi )/(2))$

$I= -I_o$

This satisfy the above given condition so we can say that this capacitor.

Final answer:

The nature of the unknown ideal element in the given AC circuit can be determined based on the phase difference between the current and voltage. In this case, since the current is zero at T/4 and a maximum at T/2, it suggests the current is lagging the voltage, indicating that the element in the circuit is a capacitor.

Explanation:

The question relates to an alternating current (AC) circuit connected to an unknown ideal element, and from the given conditions, it appears this element is a capacitor. Let us understand why.

Firstly, in an AC circuit, we can determine the nature of the circuit elements—resistor, inductor, or capacitor—based on the phase difference between the current and voltage. In a resistor, the current and voltage are in phase. In an inductor, the current lags behind the voltage by 90 degrees (or π/2 radians), whereas in a capacitor, the current leads the voltage by 90 degrees (or π/2 radians).

Based on the given problem, at time t = T/4, the current is zero. Considering that in one period of the AC voltage, it starts from zero, reaches a maximum, comes back to zero (at T/2), goes to a minimum (at 3T/4), and returns back to zero (at T), the current would reach its peak either at T/4 (if it's leading, a capacitor) or at 3T/4 (if it's lagging, an inductor). Here, since the current is zero at T/4 and it is a maximum at T/2 (albeit negative), it suggests the current is lagging the voltage, and hence, it suggests the element in the circuit is a capacitor.

Learn more about AC Circuits here:

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Một vật chuyển động tròn đều có chu kì T = 0,25 s. Tính tần số chuyển động f của vật?

Answers

Answer:8pi

Explanatio

omega=2pi/T

Answer:

0000

Explanation:

A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave perspective, the antenna is a circular aperture through which the microwaves diffract. What is the diameter of the radar beam at a distance of 30 km

Answers

Answer:

915m

Hope this helps.

The sun does not normally affect the tides to a noticeable degree. however, under certain circumstances the gravitational pull of the sun does affect the tides. under what two (2) conditions.the sun does not normally affect the tides to a noticeable degree. however, under certain circumstances the gravitational pull of the sun does affect the tides. under what two (2) conditions.

Answers

The answers are :
1) when the sun, moon, and earth are in a line only
2) when the gravitational forces of the Moon and the Sun are
perpendicular to one another with respect to the Earth.

Answer:

High and low tides are result of combined effect of gravitational pull of the sun and the moon. When the two align in a straight line, the range of tides is maximum. This happens on new moon and full moon day.

On the other hand, when the sun and the moon align at right angles, the effect of gravity is minimum and the range of the tides is minimum.

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A research Van de Graaff generator has a 2.00-m diameter metal sphere with a charge of 5.00 mC on it. (a) What is the potential near its surface? (b) At what distance from its center is the potential 1.00 MV?(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?

Find the force on a 5 pС charge in a place where the electric field is 400 N/C.