All sides of △ ABC are tangent to circle PPP.What is the perimeter of the triangle below?

___ units


PLEASE HELP

Answers

Answer 1
Answer:

Answer:

the answer is 58

Step-by-step explanation:

Answer 2
Answer:

Answer:

\frac{9\sqrt{3}}{2}\approx 7.79 square units.

Step-by-step explanation:


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cassidy loves black and yellow jelly beans she noticed when she was counting them that she had 7 less than three times as many black jelly beans as she had yellot jelly beans in total she counted 225 jelly beans how many black jelly beans did she have?

Answers

Most of the information's are already given in the question. It is important to understand the language of the problem for solving the problem. Once the language is understood, then solving the problem is easy.
Let us assume the number of black jelly beans = x
Number of yellow jelly beans = y
Then from the question we can get to a equation.
3x - 7 = y
We also know from the question that
x + y = 225
x + 3x -7 = 225
4x = 225 + 7
4x = 232
x = 232/4
   = 58
So Cassidy has 58 black jelly beans out of the total of 225 jelly beans

Find the unit rate for each relationship below. Include units.
320 miles in 6 hours

Answers

Answer:

53 1/3 mph.

I divided 320 by 6 and got this answer.

Final answer:

This solution represents a unit rate problem in Mathematics. The problem is finding how many miles are covered in one hour when 320 miles are covered in 6 hours. The answer, calculated by dividing the distance (320 miles) by the time (6 hours), is around 53.33 miles/hour.

Explanation:

The question is asking you to find the unit rate for the relationship given, which is 320 miles in 6 hours. A unit rate tells you how many of the first quantity correspond to one unit of the second quantity. In this case, to find the unit rate, we need to find out how many miles are covered in one hour.

To do this, we divide the total distance by the total time. So, 320 miles/6 hours = 53.33 miles/hour. This means that for every hour, approximately 53.33 miles are being covered. This is your unit rate for this relationship.

Learn more about Unit Rate here:

brainly.com/question/11258929

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Evaluate the related series,of each sequence

-9,-16,-23,-30,-37,-44

Answers

I think its just that the series decreases by 7 from n-1 to n

Find the buying price of each of the following when 5% sales tax is added on the purchase of;1. a pillow for RS. 60
2. two bars of soap at RS.25 each

Answers

1. 60 + 60*0.05 = 60 + 3 = 63;
2. 50 + 50*0.05 = 50 + 2.5 = 52.5;

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A ball is thrown vertically upwards from a height of 6 feet with an initial velocity of 40 feet per second. How high will the ball go? Note that the acceleration of the ball is given by feet per (second)2. Round your answer to the four decimal places.

Answers

Answer:

The maximum height that the ball reaches is sf = 31 feet from the ground

Step-by-step explanation:

Solution:-

- A ball is thrown vertically upwards from an initial elevation of si = 6 feet from the ground.

- The velocity with which the ball was thrown up, vi = 40 ft/s

- We can determine the maximum height of the ball when it is thrown vertically up by using the 3rd kinematic equation of motion.

                      vf^2 - vi^2 = 2*g*( sf - si )

Where,

vf : The final velocity of the ball, for maximum height it is = 0

sf : The final height of the ball from the ground

g : Gravitational constant = -32 ft/s^2

                      0 - 40^2 = -2*32*( sf - 6 )

                      sf - 6 = 25

                      sf = 31 feet

- The maximum height that the ball reaches is sf = 31 feet from the ground.

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = -0.06x^2 + 10.1x + 5, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

Answers

Answer:

The horizontal distance from the starting point when rocket lands is:

168.83 meters.

Step-by-step explanation:

We are given a function that models the height of the rocket when it is 'x' meters away from the starting point.

The function is:

y=-0.06x^2+10.1x+5

Now we are asked to find the horizontal distance from the starting point when the rocket will land.

i.e. we are asked to find 'x' ; when y=0

i.e.

Let y=0

-0.06x^2+1.01x+5=0\n\ni.e.\n\n6x^2-1010x-500=0

on solving the quadratic equation we obtain:

x=-0.49360\ and\ x=(125)/(6)=168.83

As the distance can't be negative.

Hence, the viable solution is:

x=168.83

Hello,

y=-0.06x²+10.1x+5
==>6x²-1010x-500=0
Δ=1010²+4*6*500=1032100=(1015,92...)²
x=(1010-1015.92...)/12 <0 exclude
or x=(1010+1015.92..)/12=168.826935... (m)