Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 12 f(x) = 12x2 3x 3 f(x) = 3x – 12.

Answers

Answer 1

Answer:

The correct option is b.

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.) $f(x) = -12x^2+3x+1 \n$

b.) $f(x) = 3x^2+11x-12 \n$

c.) $f(x) = 12x^2+3x+3\n$

d.) $f(x) = 3x -12.$

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

Answer 2

Answer:

Answer:

f(x) = 3x2 + 11x – 12

Step-by-step explanation:

aka B 2022