There are 67 questions on an exam. If you miss 8 of these questions your grade is _______ %.

Answers

Answer 1

Answer:

If you miss 8 out of 67 questions on the exam, your grade percentage would be approximately 88.06%.

Given that there are 67 questions on an exam. If you miss 8 of these questions then Subtract the number of questions missed (8) from the total number of questions (67):

Number of questions answered correctly = Total questions - Questions missed

= 67 - 8

= 59

Now, Grade percentage = (Number of questions answered correctly / Total questions) * 100

= (59 / 67) * 100

≈ 88.06% (rounded to two decimal places)

Therefore, if you miss 8 out of 67 questions on the exam, your grade percentage would be approximately 88.06%.

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A trapezoid is shown:

What is the area of the trapezoid?

Answers

Answer:

Area of trapezoid is:

162 cm²

Step-by-step explanation:

Area(A) of trapezoid is given by:

$A=(1)/(2)* (sum\ of\ parallel\ sides)* (Height)$

Here, we are given Height=9 cm

One parallel side=6 cm

Other parallel side=(12+6+12) cm

= 30 cm

Sum of parallel side=(6+30) cm

= 36 cm

Area= $(1)/(2)* 36* 9$

= 162 cm²

Hence, Area of trapezoid is:

162 cm²

A = 1/2(6+30)(9)
A = 1/2(36)(9)
A = 162
answer
162 cm^2

Will the quotient of 5 divided by 7/8 be greater than or less than 5? explain

Answers

Answer:

7/8 x 5/1 = 35. 35/8= 4.375 is less than 5

Step-by-step explanation:

Answer:

Greater

Step-by-step explanation:

If you divide 5 by 7/8, you will get 40/7. Convert to a decimal to compare, and you will see that 5<5.7

The dimensions of a rectangular flower bed on a sketch are 4 cm by 6 cm. In real life, the shorter side of the flower bed is 5 m. Find the length of the longer side.

Answers

The length of longer side of the rectangular flower bed is 7.5m .

Given, that sketch dimensions of the rectangular flower are 4 cm by 6 cm.

Conversion of meter to centimeter.

1m ⇒ 100cm

So, 100 x 5 = 500cm

Now the shorter side of the flower corresponds to 4cm.

In actual the value in centimeters,

500 ÷ 4 = 125

Length of longer side of the rectangle.

125 x 6 = 750 cm

Convert cm to m.

1cm ⇒ 0.01 m

750/100 = 7.5 m

Therefore the length of longer side of rectangle is 7.5 m

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Answer:

125.15

Step-by-step explanation:

Just do it!

A student is trying to solve the set of two equations given below:Equation A: x + z = 6
Equation B: 3x + 2z = 1

Which of the following is a possible step used in eliminating the z-term?
Multiply equation A by −2.
Multiply equation B by 2.
Multiply equation A by 3.
Multiply equation B by 3.

Answers

a possible step used in eliminating the z-term is "multiply equation A by −2."

x + z = 6
3x + 2z = 1

x + z = 6 / *(-2)
3x + 2z = 1

-2x - 2z = -12
3x+ 2z = 1

-2x + 3x -2z +2z = -12 +1
x = -11

-11 + z = 6
z = 6 + 11
z = 17

Answer:Multiply equation A by -2 is correct everyone

Step-by-step explanation:

I just took the test and checked;)

1/3 x− 1/8 y=3
7y+9x=−2
please solve the system
45 points for who does

Answers

Answer:

$x=6\ny=-8$

Step-by-step explanation:

$(1)/(3)x-(1)/(8)y=3\n 7y+9x=-2$

One method could be rewriting the second equation as x in terms of y and solving by replacing in the first equation.

$7y+9x=-2\n9x=-2-7y\nx=(-7y-2)/(9)$

Replace...

$(1)/(3)x-(1)/(8)y=3$

$(1)/(3)((-7y-2)/(9))-(1)/(8)y=3$

$(-7y-2)/(27)-(1)/(8)y=3$

$-(7)/(27)y-(2)/(27)-(1)/(8)y=3$

add $(2)/(27)$ on both sides.

$-(7)/(27)y-(1)/(8)y=3+(2)/(27)$

Combine like terms

$((-7)(8)-(1)(27))/((27)(8)) y=((3)(27)+2)/(27)$

$(-56-27)/(216) y=(81+2)/(27)$

$(-83)/(216)y =(83)/(27)$

Now, to get rid of the fraction and isolate y, multiply by the reciprocal or the inverted fraction.

$((216)/(-83)) (-83)/(216)y =(83)/(27)((216)/(-83))$

$y=(216)/(-27)$

Simplify

$y=-8$

Now replace the value of y in either equation to find x.

$7y+9x=-2\n7(-8)+9x=-2\n-56+9x=-2$

add 56

$56-56+9x=-2+56\n9x=54\n$

Divide by 9

$(9x)/(9)=(54)/(9)\n x=6$

To check whether these values are accurate, replace in either equation both values and you should have an equality. In this case I'll do it in both equations.

$(1)/(3)x-(1)/(8)y=3$

$(1)/(3)(6)-(1)/(8)(-8)=3$

$2-(-1)=3\n2+1=3\n3=3$

-----------------------------------------------------------------

$7y+9x=-2\n7(-8)+9(6)=-2\n-56+54=-2\n-2=-2$

Use the rules for logarithms and exponents to write this equation in logarithmic form.?For the equation K = Ae^(-ΔH/RT), solve for ln K using logarithms and exponents.