The elasticity of demand for gasoline has been estimated to be 2.0, and the standard error is 1.0. The upper and lower bounds on the 95 percent confidence interval for the elasticity of demand for gasoline are:

Answers

Answer 1
Answer:

Answer:

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_(\alpha/2)(\sigma)/(√(n))   (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_(\alpha/2)=1.96

The standard error for this case is given:

SE =(\sigma)/(√(n))=1

Now we have everything in order to replace into formula (1):

2-1.96*11=0.04    

2+1.96*1=3.96  

Explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X =2 represent the sample mean for the sample  

\mu population mean (variable of interest)  

s represent the sample standard deviation  

n represent the sample size  

Calculate the confidence interval

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_(\alpha/2)(\sigma)/(√(n))   (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_(\alpha/2)=1.96

The standard error for this case is given:

SE =(\sigma)/(√(n))=1

Now we have everything in order to replace into formula (1):

2-1.96*11=0.04    

2+1.96*1=3.96  


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How long is a bus route across a small town

Answers

Answer:

4 kilometers

Explanation:

Final answer:

The length of a bus route in a small town can greatly depend on the specifics of the town and the route. It can range from a couple miles in a very small town to 20 miles or more for larger towns.

Explanation:

The length of a bus route across a small town can vary greatly depending on the size of the town and the specifics of the bus route. In a very small town, the bus route might only be a mile or two long. For larger towns, it could easily be 10-20 miles, or more. If you know the specifics of the route (streets it travels along, the number of stops, etc.), you could use a tool like Go_gle Maps to calculate an approximate distance.

Learn more about bus route here:

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A playground merry-go-round of radius R = 2.20 m has a moment of inertia I = 275 kg · m2 and is rotating at 9.0 rev/min about a frictionless vertical axle. Facing the axle, a 23.0-kg child hops onto the merry-go-round and manages to sit down on the edge. What is the new angular speed of the merry-go-round? rev/min

Answers

Answer:

6.4 rpm

Explanation:

I_(m) = moment of inertia of merry-go-round = 275 kgm²

m = mass of the child = 23 kg

R = radius of the merry-go-round = 2.20 m

I_(c) = moment of inertia of child after jumping on merry-go-round = mR² = (23) (2.20)² = 111.32 kgm²

Total moment of inertia after child jumps is given as

I_(f) = I_(m) + I_(c) = 275 + 111.32 = 386.32 kgm²

Total moment of inertia before child jumps is given as

I_(i) = I_(m) = 275 kgm²

w_(i) = initial angular speed = 9 rpm

w_(f) = final angular speed

using conservation of angular momentum

I_(i)w_(i) = I_(f)w_(f)

(275) (9) = (386.32) w_(f)

w_(f)  = 6.4 rpm

18. Wind speed on Earth is reduced by which?A. temperature
B. friction
C. weather
D. convergence

Answers

Answer:

Temperaturereduces the wind speed on earth.

Explanation:

  • Wind speed is an atmospheric quantity that causes the wind to flow from high to low level due to a change in temperature.
  • Wind speed is controlled by the pressure gradient factor and it increases the wind speed with increase in pressure gradient.
  • Wind speed decreases with an increase in temperature value as it absorbs the heat developed in the system and wind gets slowed down.
  • Wind speed is measured in velocity and anemometer is used to measure the rate of wind speed.

Answer:

your answer would be A. temperature

Explanation:

Wind speed on Earth is reduced by temperature, it depends on the temperature because let's say there is a nice sunny day, then obviously it will reduce the wind speed

To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes the kinetic energy change.'

Answers

Answer: The force is as a function of Distance

Explanation:

The force and distance must be parallel to each other. Only the component of the force in the same direction as the distance traveled does any work. Hence, if a force applied is perpendicular to the distance traveled, no work is done. The equation becomes force times distance times the cosine of the angle between them.

where both the force F and acceleration are vectors. This makes sense since both force and acceleration have a direction.

On the other hand, the kinetic energy

K=12mv2

looks completely different. It doesn't seem to depend on the direction.

Answer:

Distance

Explanation:

dW = F. dx

The cart is initially at rest. ForceF is applied to the cart for time ? t, after which the car has speed v. Suppose the same force is applied for the same time to a second cart with twice the mass. Friction is negligible. Afterward, the second cart's speed will be
a) 2v
b) 1/2v
c) v
d) 4v
e) 1/4v

Answers

Answer:

v'=(1)/(2)v

Explanation:

Given that,

Initial speed of the cart, u = 0

Let F force is applied to the cart for time \Delta t after which the car has speed v. The force on an object is given by :

F = ma

m is the mass of the cart

We need to find the speed of second cart, if the same force is applied for the same time to a second cart with twice the mass. Force becomes,

F=(mv')/(t)

v'=(F t)/(2m)

v'=(1)/(2)v

So, the speed of second cart is half of the initial speed of first cart. So, the correct option is (b).

How much longer will it taketo travel a distance of 6ookm at
a speed of 50kmh than it
would at a
speed of 6okmh?

Answers

Answer:

2hr much longer

Explanation:

Given parameters

  Distance  = 600km

   Speed 1  = 50km/h

   Speed 2 = 60km/h

Unknown:

How much longer will it take to travel a distance  = ?

Solution:

  Speed is the distance divided by time;

          Speed  = (distance)/(time)  

 Now;

           Time taken  = (Distance)/(Speed)  

Time 1;

                        = (600)/(50)

                       = 12hr

Time 2;

                       = (600)/(60)

                       = 10hr

To find how much more time;

            Time 1 will take 12hr - 10hr, 2hr much longer to travel the distance at that rate.