Please help find the MAD
Answers
Answer: 0.5
Step-by-step explanation:
1. I calculate the mean= sum of the data/number of data=
(3+5+4+4 )/4=16/4=4
2. I calculate distance between the data and the mean
|3-4|=|-1|=1
|4-5|=|-1|=1
|4-4|=0
|4-4|=0
3. Add the distances
1+1+0+0=2
4. Divide the sum by the number of data points
2/4=0.5
answer: 0.5
3 + 5 + 4 + 4 = 16 ÷ 4 = 4
4 - 3 = 1
4 - 5 = 1
4 - 4 = 0
4 - 4 = 0
1 + 1 + 0 + 0 = 2 ÷ 4 = 0.5
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(1 pt) Segment km is 18 cm long. How long is the radius of circle N?
Answers
Answer:
Number of Large Pizzas: 30
Number of Medium Pizzas: 8
Number of Small Pizzas: 27
Step-by-step explanation:
L = # of large Pizzas
M = # of medium Pizzas
S = # of small Pizzas
Amount:
L = 4M - 2
S = 3M + 3
Cost:
21L + (I'm assuming you meant 14) 14M + 7S = 931
Plus in the Amounts to the Cost:
21(4M - 2) + 14M + 7(3M + 3) = 931
84M - 42 + 14M + 21M +21 = 931
Combine like terms:
119M - 21 = 931
Isolate the Variable:
119M - 21 + 21 = 931 + 21
119M = 952
119M/119 = 952/119
M = 8
Plug it into the Amount equations:
Large: L = 4(8) - 2
L = 32 - 2
L = 30
Small: S = 3M + 3
S = 3(8) + 3
S = 24 + 3
S = 27
Check your work (plug the values into Cost.):
21(30) + 14(8) + 7(27) = 931
630 + 112 + 189 = 931
931 = 931
Final answer:
The number of medium pizzas ordered was 10. Hence, based on the given relationships, the number of large pizzas was 38 and the number of small pizzas was 33.
Explanation:
To solve this problem, really, we are using three algebraic expressions that represent the total cost, the relationship between the large and medium pizzas, and the relationship between the small and medium pizzas.
We can define M as the number of medium pizzas, L as the number of large pizzas, and S as the number of small pizzas. We can then set up the following equations based on the problem:
- $21L + $14M + $7S = $931
- L = 4M - 2
- S = 3M + 3
We can substitute equations 2 and 3 into equation 1 to get a single equation in terms of M:
$21(4M-2) + $14M + $7(3M+3) = $931
Which simplifies to:
93M = 931
Then, M=10, hence, the number of medium pizzas is 10, number of large pizzas (4M-2) is 38, and the number of small pizzas (3M+3) is 33.
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Part B)Applications to the university from boys represented 40Percent of all applications. How many applications did the university receive In all?
I don't how to do part b so please help me and plz tell how you got your answer
Answers
Part A) 1246 applications were received from other sides.
Part B) The university received a total of 8900 applications.
What is the percentage?
A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.
Given, Last Year, a state university received 3,560 applications from boys. Of those applications, 35 Percent were from boys who lived in other states.
Assuming x no. of boys live in other states.
So, 35% of 3560 is x.
∴ (35/100)×3560 = x.
x = 0.35×3560.
x = 1246.
1246 applications were received from other sides.
Now, The university received 40% of the applications from boys, Assuming the total no. of applications to be y.
∴ 40% of y is 3560.
So, (40/100)y = 3560.
0.40y = 3560.
y = 3560/0.40.
y = 8900
The university received a total of 8900 applications.
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5%=356/2=178
30%=356X3=1068
35%=1068+178=1246
b)10% of 40%=3560/4=890
100%890x10=8900(answer)
hope this helps
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Your image appears to be that of the aftermath of a supernova explosion.
Content
Ratios such as x apples to y apples can be written in fraction form as x/y. Usually ratios compare non-like objects like apples and oranges.
Anyways, we can write 24 messages:10 messages as:
It can thus be simplified. Note, however, that we cannot write this in mixed fraction form because it is a ratio; it must stay in improper form.
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WHY?
Because the 9 is in the thousands place. So, therefore, our answer is correct.
Hope this helps! :D
60000+9000+100+40+3. Try that in the calculator and you'll know I'm correct