MATHEMATICS MIDDLE SCHOOL

Can someone help me please!
You just have to resolve it, the ones that doesn’t have an x

Answers

Answer 1

Answer:

Answer:

5. =1

6. = $-(1)/(3)$

10. = The last solution

Step-by-step explanation:

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PLEASE GIVE CORRECT ANSWER THANK YOU !!!!!! : ) 1.) 2x+8+4x-52.) b +72y-4.2y+13.) 10r-5+3+r4.) 3x+14 -x -155.) -6.6z+11+1.3+ +2z
Suppose that 30% of a population has dimples. You want to estimate the probability that it will take at least a sample of three to find one person with dimples. You set up a random digit simulation where 0, 1, 2 represents a person with dimples and 3, 4, 5, 6, 7, 8, 9 represents a person that does not have dimples. Which would constitute a trial for this simulation? A) two random digits B) three random digits C) eight random digits D) ten random digits

What is the quotient of 43.8 and 12

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Answer:

The quotient of our given numbers is 3.65.

Step-by-step explanation:

We are asked to find the quotient of 43.8 and 12.

To find the quotient of 43.8 and 12, we need to divide 43.8 by 12 as shown below:

$\text{Quotient}=(43.8)/(12)$

$\text{Quotient}=3.65$

Therefore, the quotient of our given numbers would be 3.65.

When you divide 43.8 / 12 you get 3.65.

Round 6,664,195 to the nearest 100,000

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6,664195 rounded to the nearest hundred-thousand? Let's solve below ↓

I have a little rounding trick that could help you in the future!

° 5 or more, raise the score!

° 4 or less, let it rest!

So, based on the math trick, we can tell that 6,664,195 rounded to the nearest hundred-thousand simply equals 6,700,000.

The 6 tells us to round up, so, therefore, our final answer is 6,700,000

↑ ↑ ↑ Hope this helps! :D

6,664,195 rounded to the nearest 100,000 would be 6,700,000. This is because we 1st look at the number after d 100 thousands place (6,664,195). If this number comes AFTER 5 we will round to d next number, tho if it were LESS than 5 we would leave it. But since it is AFTER 5 we will round it to d next number which would make 6,664,195 rounded to d nearest 100,000 is 6,700,000.

Hope I helped ya!!! xD

A van is carrying 486 pounds. There are 27 boxes in the van What is the average weight of each box in the van

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the answer is 18 all u have to do is divide 27 divided by 486

A number squared added to 16

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Answer:

Sry i dont understand what ur trying to say but if ur asking what number squared will give u 16 its 4

Step-by-step explanation:

Answer:

im pretty sure the answer is 4 but i don't rlly understand the question

Step-by-step explanation:

PLSSSS HELP ITS DUE TODAY!!!!!

Answers

Answer:

Both Jules' and Lauren's equations are correct because they have slopes that are the negative reciprocal of the slope of the given line, making them perpendicular to the given line.

Step-by-step explanation:

Let's reevaluate the equations based on the corrected given line equation:

$\sf y - 2 = (1)/(5)(x - 3)$

The given line equation is in point-slope form: $\sf \boxed{\sf y - y_1 = m(x - x_1)}$ , where m is the slope.

Given line equation: $\sf y - 2 = (1)/(5)(x - 3)$

While comparing, we get

$\textsf{The\underline{ slope (m) }of the given line is }(1)/(5)$

For a line to be perpendicular to the given line, its slope must be the negative reciprocal of the slope of the given line.

The negative reciprocal of $\sf (1)/(5)$ is $\sf -5.$

Now let's check the slopes of the equations provided by Jules and Lauren:

1. Jules' equation: $\sf y = -5x + 1$

The slope of Jules' equation is -5, which matches the negative reciprocal of the slope of the given line.

2. Lauren's equation: $\sf y = -5x + 7$

The slope of Lauren's equation is also -5, which again matches the negative reciprocal of the slope of the given line.

Both Jules' and Lauren's equations have a slope of -5, which is the negative reciprocal of the slope of the given line $(1)/(5)$ .

Therefore, both equations are correct and satisfy the condition of being perpendicular to the given line $\sf y - 2 = (1)/(5)(x - 3)$

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$y-2=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{5}}(x-3)\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array} \n\n[-0.35em] ~\dotfill$

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{1}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{1} \implies -5}}$

so ANY line that is perpendicular to that equation above, will have a slope of -5, so any of these are all perpendicular to it

$\begin{array}{llll} \stackrel{ Jules }{y=-5x+1} \n\n\n \stackrel{ Lauren }{y=-5x+7} \n\n\n y=-5x+999999999 \n\n\n y=-5x-93789 \end{array}\hspace{5em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\n \cline{1-1} \n y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \n\n \cline{1-1} \end{array}$

A radio station requires DJs to play 2 commercials for every 10 songs they play. What is the unit rate of songs to commercials?

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5 songs to each commercial
hope it helps!
select brainiest answer!

Can someone help me please! You just have to resolve it, the ones that doesn’t have an x

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Can someone help me please!
You just have to resolve it, the ones that doesn’t have an x