The value of \(x\) that makes the equation true is
To find the value of \(x\) that makes the equation true, you need to simplify the equation and solve for \(x\). Let's break down the steps:
1. **Distribute the -5 on the left side:**
2. **Move the constant term (100) to the right side by subtracting 100 from both sides:**
3. **Finally, divide both sides by -5 to solve for \(x\):**
To verify, substitute \(x = 13\) back into the original equation:
The equation is true when \(x = 13\).
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Answer:
x=13
Step-by-step explanation:
Divide both sides by -5 then solve the equation for x
Answer:
Step-by-step explanation:
Hello,
This is the equation of a line so if you know two points of the line you can graph it, right?
For x = 0 y = -3 so the point A (0,-3) is on the graph
For x = 3 y =-4 so the point B (3,-4) is on the graph
And then you can draw the line as below
Thanks
Answer:
V = π (-2 (ln 2)² + 4 ln 2 − 1)
V ≈ 2.55
Step-by-step explanation:
V = π ∫₁² (1 − (ln x)²) dx
V/π = ∫₁² (1 − (ln x)²) dx
V/π = ∫₁² dx − ∫₁² (ln x)² dx
V/π = x |₁² − ∫₁² (ln x)² dx
V/π = 1 − ∫₁² (ln x)² dx
To evaluate the second integral, integrate by parts.
If u = (ln x)², then du = 2 (ln x) / x dx.
If dv = dx, then v = x.
∫ u dv = uv − ∫ v du
= (ln x)² x − ∫ x (2 (ln x) / x) dx
= x (ln x)² − 2 ∫ ln x dx
Integrate by parts again.
If u = ln x, then du = 1/x dx.
If dv = dx, then v = x.
∫ u dv = uv − ∫ v du
= x ln x − ∫ x (1/x dx)
= x ln x − ∫ dx
= x ln x − x
Substitute:
∫ (ln x)² dx = x (ln x)² − 2 ∫ ln x dx
∫ (ln x)² dx = x (ln x)² − 2 (x ln x − x)
∫ (ln x)² dx = x (ln x)² − 2x ln x + 2x
Substitute again:
V/π = 1 − ∫₁² (ln x)² dx
V/π = 1 − (x (ln x)² − 2x ln x + 2x) |₁²
V/π = 1 + (-x (ln x)² + 2x ln x − 2x) |₁²
V/π = 1 + (-2 (ln 2)² + 4 ln 2 − 4) − (-1 (ln 1)² + 2 ln 1 − 2)
V/π = 1 − 2 (ln 2)² + 4 ln 2 − 4 + 2
V/π = -2 (ln 2)² + 4 ln 2 − 1
V = π (-2 (ln 2)² + 4 ln 2 − 1)
V ≈ 2.55
Answer:
357 mi²
Step-by-step explanation:
The shape is made of a triangle and a half-square
we will calculate the area of each one
let A1 be the area of the half-circle:
A1= (10²*π)/2 = 50π mi²
Let A2 be the area of the triangle:
A2= 10*20=200 mi²
let At be the total area:
At =A1+A2= 200+50π =357.07≈ 357 mi²
To solve the system of equations by graphing, plot the given points on a coordinate plane and find the intersection point.
To solve the system of equations by graphing, we can plot the given points on a coordinate plane and see where the lines intersect. From the given points, we can see that the lines intersect at approximately (-1.1, 3.2). So, the solution to the system of equations rounded to the nearest tenth is (-1.1, 3.2).
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Answer: Answer:The solution to the given system of equations is (2.8,0.1)
Step-by-step explanation: I got it correct on the Unit Test