MATHEMATICS COLLEGE

A small jar of peanut butter sells for 0.08 per ounce. A large jar of peanut butter sells for $1.20 per pound. Which is the better buy and by how much (in cents per pound)?

Answers

Answer 1

Answer:

Answer:

a small jar of penuts buteer sells for 0.08 per ounce

A large jar of penut buttter sells for $1.20 per pound

the answer is :

hope it will help you

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which of the following is among the likely causes of a non-random sample? a. non response bias b. parameter c. statistics d. population
Which number(s) below belong to the solution set of the inequality? Check all that apply. 9x 117A. 12 B. 14 C. 19 D. 13 E. 6 F. 8
The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function? A. Locate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points. B. Locate the ordered pair (0, –6). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points. C. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points. D. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.

A local doctor’s office logged the number of patients seen in one day by the doctor for ten days. Find the means, median, range, and midrange of the patients seem in 10 days. 27 31 27 35 35 25 28 35 33 24

Answers

Answer:

Mean = 30, Median = 29.5, Range = 9 and Mid-range = 29.5.

Step-by-step explanation:

We are given that a local doctor’s office logged the number of patients seen in one day by the doctor for ten days.

Arranging the given data in ascending order we get;

24, 25, 27, 27, 28, 31, 33, 35, 35, 35.

(a) Mean is calculated by using the following formula;

Mean, $\bar X$ = $\frac{\text{Sum of all values}}{\text{Total number of observations}}$

= $(27+ 31+ 27+ 35+ 35+ 25+ 28+ 35+ 33+ 24)/(10)$

= $(300)/(10)$ = 30

So, the mean of the given data is 30.

(b) For calculating the median, we have to first have to observe that the number of observations (n) in the data is even or odd.

If n is odd, then the formula for calculating median is given by;

Median = $((n+1)/(2))^(th) \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{((n)/(2))^(th) \text{ obs.}+ ((n)/(2)+1)^(th) \text{ obs.} }{2}$

Here, the number of observations is even, i.e. n = 10.

So, Median = $\frac{((n)/(2))^(th) \text{ obs.}+ ((n)/(2)+1)^(th) \text{ obs.} }{2}$

= $\frac{((10)/(2))^(th) \text{ obs.}+ ((10)/(2)+1)^(th) \text{ obs.} }{2}$

= $\frac{(5)^(th) \text{ obs.}+ (6)^(th) \text{ obs.} }{2}$

= $(28+31)/(2)$

= $(59)/(2)$ = 29.5

So, the median of the data is 29.5.

(c) The range of the data is given by = Highest value - Lowest value

= 35 - 24 = 9

So, the range of the data is 9.

(d) Mid-range of the data is given by the following formula;

Mid-range = $\frac{\text{Highest value}+\text{Lowest value}}{2}$

= $(35+24)/(2)$ = 29.5

Final answer:

The mean of the patients seen in 10 days is 30, the median is 29.5, the range is 11, and the midrange is 29.5.

Explanation:

To find the mean, median, range, and midrange of the numbers, we first need to understand what these terms mean. The mean is the average, the median is the middle number in a sorted set, the range is the difference between the highest and lowest values, and the midrange is the average of the highest and lowest values.

First, let's sort the numbers: 24 25 27 27 28 31 33 35 35 35.

To calculate the mean, add all the numbers and divide by the count (10): (24+25+27+27+28+31+33+35+35+35)/10 = 30.

The median is the average of the two middle numbers (which are 28 and 31 in this case): (28 + 31) / 2 = 29.5.

The range is the highest number minus the lowest number: 35 - 24 = 11.

The midrange is the average of the highest and lowest values: (35 + 24) / 2 = 29.5.

Learn more about Mean, Median, Range

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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experience that 1%, 3%, and 2% of the products made by each machine, respectively, are defective. A finished product is randomly selected and found to be non-defective, what is the probability that it was made by machine B1?

Answers

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = $(P(B|A)P(A))/(P(B)) = (P(B|A)P(A))/(P(B|A)P(A) + P(B|a)P(a))$

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) = $(P(N|B1)P(B1))/(P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3))$ = $((0.297)(0.3))/((0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5))$ = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

Which option correctly shows 4 6 as a division expression? A. 4 ÷ 1 6 B. 6 ÷ 1 4 C. 4 ÷ 6 D. 6 ÷ 4

Answers

The answer is to the problem is d

Answer: D

Step-by-step explanation:

I took the quiz

Which of the following ratios is equivalent to 12/20? Answers A. 3/10 B. 5:3 c. 120 to 200 D. 60/80

Answers

A is 3/10 , if we multiply top and bottom by 4 we get 12/40 , which is not equivalent to 12/20.

B is 5:3 , it cannot be equivalent to 12/20.

C is 120 to 200 , if we divide both numerator and denominator by 10 we get 12/20, So option C is correct.

D is 60/80 , if we divide both numerator and denominator by 5, we get 12/16 , which is not equivalent to 12/20.

Hence option C is the correct answer.

12 : 20
12 x 10 : 20 x 10
120 : 200 (Answer C)

Graph and find the x-intercept, y-intercept, domain, range, and horizontal asymptote of the function y = 4x

Answers

The function $y=4x$ is a line. As such, its domain and range is the whole real number set $\mathbb{R}$ , and it has no horizontal nor vertical asymptotes.