Answers
Answer:
The electric force increases by a factor of 4.
Explanation:
The electric force between two charges and
separated a distance d can be calculated using Coulomb's Law:
where is the Coulomb constant.
If the value of each charge is doubled, then we will have a force between them which is:
So the new force is 4 times larger than the original force.
Final answer:
Doubling the charge on each particle increases the electric force between them by a factor of 4.
Explanation:
The force between two charged particles is given by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. So, if we denote the electric force as F, the charges as q1 and q2, and the distance as r, we can write Coulomb's law as F = k* q1*q2/r^2, where k is a constant.
Now if you double the charges (q1 and q2 become 2q1 and 2q2), and use these values in the formula, we get Fnew = k*(2q1) *(2q2)/r^2 = 4 * k*q1*q2/r^2 = 4F.
So, by doubling the charge on each particle, the electric force between them is multiplied by the factor of 4. So, the force increases fourfold.
Learn more about Coulomb's Law here:
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Make the following conversion.56.32 kL = _____ L0.0563200.563205,63256,320
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Answers
The question is incomplete. Here is the complete question.
Lightning bolts can carry currents up to approximately 20kA. We can model such a current as the equivalent of a very long, straight wire.
(a) If you were unfortunate enough to be 5.5m away from such a lightning bolt, how large a magnetic field would you experience?
(b) How does this field compare to one you would experience by being 5.5cm from a long, straight household current of 5A?
Answer: (a) B = 7.27 x 10⁻⁴ T
(b) Approximately 40 times higher than a household one.
Explanation: Using Biot-Savart Law, the magnetic field in a straight, long wire is given by
where:
(permeability of free space) =
T.m/A
(a) If lightning bolt is compared to a long and straight wire, then magnetic field is
B = 7.27 x 10⁻⁴ T
The magnitude of magnetic field in a lightning bolt is 7.27 x 10⁻⁴ T
(b) Magnetic field in a household wire will be
B = 1.82 x 10⁻⁵ T
Comparing fields:
≈ 40
The filed for a lightning bolt is approximately 40 times higher than for a household wire.
Answers
Answer:
Explanation:
Width of slit = 10⁻³ / 1200
d = 8.3 x 10⁻⁷ m
First order maxima will be observed at
x = λD/d
D = 75 cm = 75 x 10⁻² m
56.2 x 10⁻² = λ₁D/d
= λ₁ x 75 x 10⁻² / 8.3 x 10⁻⁷
λ₁ = 56.2 x 8.3 x 10⁻⁷ / 75
= 6.219 x 10⁻⁷ m
= 6219 A
Similarly
λ₂ = 65.9 x 8.3 x 10⁻⁷ / 75
= 7293 A
λ₃ = 93.5 x 8.3 x 10⁻⁷ / 75
= 10347 A
Answers
Answer:
The constant speed of second submarine is 31.16 km/hr
Explanation:
Given that
v₁=20 km/hr ,d₁= 500 Km
v₂=40 km/hr ,d₂=500 km
v₃=30 km/hr, d₃=500 km
v₄=50 km/hr ,d₄=500 km
We know that
Displacement = Velocity x Time
d = v t
Total displacement = Average velocity x Total time
Now by putting the values
So the constant speed of second submarine will be the average speed of first submarine because they have to meet at the same time.
The constant speed of second submarine is 31.16 km/hr
Answers
The distance between the adjacent bright fringes is : 1.7 * 10⁻³ M
Given data :
separation between slits ( d ) = 1.5 x 10⁻³ m
wavelength of light ( λ ) = 514 * 10⁻⁹ m
Distance from narrow slit ( D ) = 5.0 m
Determine the distance between the adjacent bright fringes
we apply the formula below
w = D * λ / d ---- ( 1 )
where : w = distance between adjacent bright fringes
Back to equation ( 1 )
w = ( 5 * 514 * 10⁻⁹ ) / 1.5 x 10⁻³
= 1.7 * 10⁻³ M
Hence we can conclude that The distance between the adjacent bright fringes is : 1.7 * 10⁻³ M
Learn more about bright fringes calculations : brainly.com/question/4449144
Answer:
m
Explanation:
d = separation between the two narrow slits = 1.5 mm = 1.5 x 10⁻³ m
λ = wavelength of the light = 514 nm = 514 x 10⁻⁹ m
D = Distance of the screen from the narrow slits = 5.0 m
w = Distance between the adjacent bright fringes on the screen
Distance between the adjacent bright fringes on the screen is given as
m
Answers
Answer: The magnitude of torque is 38.7Nm
Explanation: Please see the attachment below
The magnitude of the torque on the door about its h1nges due to the applied force is 38.7 Nm.
How to calculate the magnitude of the torque?
The magnitude of the torque on the door about its h1nges due to the applied force is calculated by applying the following formula as shown below;
τ = rF
where;
- r is the perpendicular distance of the applied force
- F is the applied force
The given parameters include;
perpendicular distance, r = 86 cm = 0.86 m
the applied force , F = 45 N
The magnitude of the torque on the door about its h1nges due to the applied force is calculated as;
τ = rF
τ = 0.86 m x 45 N
τ = 38.7 Nm
Learn more about torque here: brainly.com/question/30338159
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