Answer:
oxidation reaction is the process of electron loss.
1. The reactant oxidised is Al
2. The reactant reduced is Fe2o3
3. The reducing agent is Al
b) The dilution equation works because the molarity remains the same.
c) The dilution equation works because the volume remains the same.
d) The dilution equation works because the number of moles remains the same.
Answer:
d) The dilution equation works because the number of moles remains the same.
Explanation:
Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and M₁V₁ = 1 mol.
Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.
The volume has doubled, but the volume has halved, and M₂V₂ = 1 mol.
b) Wrong. The molar concentration changes on dilution.
c) Wrong. The volume changes on dilution.
a) Wrong, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula M₁V₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.
The dilution equation work M1V1 =M2V2 work because the number of moles of solute remains the same.
Dilution refers to the addition of solvent such as water to a solution. When dilution is done the amount of solute is not affected but the amount of solvent increases while the concentration decreases.
It is the opposite of dilution where by a solvent is removed from a solution thereby increasing the concentration of the solute.
The dilution equation is given by;
M1V1=M2V2
Where M1 is the initial concentration of the solution
V1 is the initial volume of the solution
M1 is the concentration of the new solution
V1 is the volume of the new volume
Initial solution
The initial solution before dilution is called the stock solution. It is the solution before dilution process is done.
Final solution is called the diluted solution. It is the solution obtained after the process of dilution.
Since dilution involves addition of solvent, then the amount of solvent in this case water increases , the amount of solute remains constant while the concentration of solute decreases.
Keywords: Dilution, dilution equation, stock solution, diluted solution.
Dilution: brainly.com/question/3203632
Dilution equation: brainly.com/question/7208939
Application of dilution equation; brainly.com/question/7208939
Level: High school
Subject: Chemistry
Topic: Mole
Sub-topic: Dilution
B. It helps create new colors of light in the visible spectrum.
C. It helps compare the applications of electromagnetic waves.
D. The wavelength of light waves can be changed using the model.
B) 87 g
C) 270 g
D) 349 g
I can't figure out the answer.
Answer:
B) 87g
Explanation:
Usatestprep said it
a. How many grams of Na20 are produced when 57.5 g of Na
reacts ?
b. If you have 18.0 g of Na, how many grams of O2 are
required for reaction?
c. How many grams of O2 are needed in a reaction that
produces 75.0 g of Na2O?
Answer:
Explanation:
a )
4Na(s) + O₂(g) - - 2Na₂O(s)
4 x 23g 32g 2x62
92 g of Na produces 124 g of Na₂O(s)
57.5 g of Na produces (124 / 92) x 57.5
= 77.5 g of Na₂O(s)
b )
92 g of Na requires 32 g of O₂
18 g of Na requires ( 32 / 92 ) x 18
= 6.26 g of O₂
c )
128 g of Na₂O(s) requires 32 g of O₂
75 g of Na₂O(s) requires ( 32 / 128 ) x 75
= 18.75 g of O₂