Hi,
Here is the step by step procedure to find the answer:
First of all we need to find out the molecular mass of H2SO4
So mass of H2 SO4 will be : (2x1.008) + (1x32.065) + (16x4)
= 98.081 g/mole
This shows that 1 mole of H2So4 contain 98 grams.
Now we need to fin out the no. of moles of H2SO4 in 250 grams
250 g x (1mole/250g)
= 2.5489 moles
Now we need to find out how many moles of oxygen are present in 2.5489 moles of H2SO4.
So, as mentioned in the formula of H2SO4, we can see that four moles of oxygen are present in one mole of H2SO4
It means that 2.5489 moles of H2SO4 contain:
2.5489 x4
= 10.19565 moles of oxygen
Now, it is very simple to determine the mass of 10.19565 moles of oxygen by using the formula:
no. of mole= mass/molar mass
10.19565 moles= X/ 16 g
10.19565 x 16= X
X= 163.13 grams
Therefore, mass of oxygen in 250 g of H2SO4 is 163.13 grams
Hope it help!
finding the average precipitation in your city
B.
determining the highest temperature in your state
C.
finding a source of copper or iron in your state
D.
finding the lowest point in your city
Plz help me
the answer is D. because a topographic map measures the lowest and highest points in a certain place
Hope this helps
Answer:
Use the formula v=fλ Divide the velocity by the frequency to find the wavelength. (Make sure you add the unit λ for your final answer)
V: Velocity
F: Frequency
λ: Wavelength
The balanced chemical equation between solid chromium and solid iodine to form solid chromium(III) iodide is: 2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
Let's consider the unbalanced equation that occurs when solid chromium reacts with solid iodine to form solid chromium(III) iodide. This is a synthesis or combination reaction.
Cr(s) + I₂(s) ⇒ CrI₃(s)
We will balance it using the trial and error method.
First, we will balance I atoms by multiplying I₂ by 3 and CrI₃ by 2.
Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
Finally, we get the balanced equation by multiplying Cr by 2.
2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
The balanced chemical equation between solid chromium and solid iodine to form solid chromium(III) iodide is: 2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
You can learn more about balancing equations here: brainly.com/question/7181548
Answer:
2 Cr(s) + 3 I2(s) → 2 CrI3(s)
Explanation:
Reactants:
Solid Chromium
• Chromium is a transition metal with an elemental symbol → Cr
• It can exist as a stable monatomic solid → Cr(s)
Solid Iodine
• Iodine is a non-metal halide of Group 7A → I
• It exists as a diatomic solid → I2(s)
Products:
Chromium(III) iodide
• Chromium, Cr → roman numeral III → +3 charge → Cr3+
• Iodide, I → from group 7A → -1 charge → I-
• When ions combine, their charges or oxidation numbers crisscross to become subscripts
• Cr will have a subscript of 1 from I- → Cr
• I will have a subscript of 3 from Cr3+ → I3
• Subscript 1 is no longer indicated → CrI3(s)
Unbalanced Chemical Reaction: Cr(s) + I2(s) → CrI3(s)
Balancing the chemical reaction:
1. Balance I:
Cr(s) + I2(s) → CrI3(s)
• There are 2 I in the reactant and 3 I in the product side
• Balance I by adding the coefficient 3 in I2 and 2 in CrI2
• There would be a total of 6 I in the reactant and product sides
Cr(s) + 3 I2(s) → 2 CrI3(s)
2. Balance Cr:
Cr(s) + 3 I2(s) → 2 CrI3(s)
• There is 1 Cr in the reactant and 2 Cr in the product side
• Balance Cr by adding the coefficient 2 in Cr(s)
• There would be a total of 2 Cr in the reactant and product sides
2 Cr(s) + 3 I2(s) → 2 CrI3(s)
a compound reaction is when two or more elements that have been bonded together chemically.
Answer:
Noho3 helps rise the cookies
Explanation:
It airs out the dough