Electric current passes through a filament of an incandescent bulb, thereby increasing it temperature. When current flows, it contains electrons through the filament to produce light. Typically, incandescent light bulb consists of a glass enclosure that contains tungsten filament. The glass enclosure contains either a vacuum or an inert gas that serves as the filament protection from evaporating. Incandescent light bulbs contain a stem attached at to its base to allow the electrical contacts to run through the envelope without gas or air leaks.
Answer:
46
Explanation:
Sodium metal has a molar mass of
22.99
Answer:
pH Scale:
The pH scale refers to the negative logarithm of molar concentration of hydrogen ions: pH = -log [H+].
Characteristics:
The pH scale ranges from 0 to 14. A solution of a compound of pH 7 or pOH 7 is a neutral solution. Solutions of pH less than 7 are acidic and more than 7 are basic.
Low pH of water is acidic in nature as it enters into the ground and collects in streams, it can have bad impacts on the ecosystem.
Grams are the unit of the mass that is used to calculate the moles. From 37.5 gms of iron, 53.6 gms of ferric oxide are produced.
Mass is the measurement of the moles of the substance and the molar mass.
Moles of iron from the mass is calculated as:
Moles of iron = 37.5 gms ÷ 55.84 = 0.671 moles
The balanced chemical reaction:
4Fe + 3O2 → 2Fe2O3
From the above it is deduced that 4 moles of iron produce 2 moles of ferric oxide so, 0.671 moles of iron will produce,
(0.671 × 2) ÷ 4 = 0.3375 moles
Mass of ferric oxide, from moles, is calculated as:
Mass = 0.33 moles × 159.687
= 52.696 gms
Therefore, 53.6 gms of ferric oxide will be produced from 37.5 gms of iron.
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The mass of Fe2O3 that can be produced from 37.5g of iron (Fe) is approximately 53.65g. This is achieved by converting mass of iron to moles, using stoichiometry from the balanced chemical equation to convert moles of iron to moles of Fe2O3, and then converting moles of Fe2O3 back to grams.
First, we need to figure out the molar mass of iron (Fe) which is approximately 55.85 g/mol and the molar mass of iron(III) oxide (Fe2O3) which is approximately 159.69 g/mol. We find this using the atomic masses of Iron (Fe) and Oxygen (O) from the periodic table and add them appropriately.
Next, to find the number of moles of iron we use the provided mass of Fe and its molar mass. We calculate this as (37.5 g Fe / 55.85 g/mol Fe) = 0.671 moles of Fe. Now, the balanced chemical equation for the formation of iron(III) oxide is: 4Fe + 3O2 --> 2Fe2O3. From this balanced equation, we know that it takes 4 moles of iron (Fe) to produce 2 moles of Fe2O3. Therefore, the moles of Fe2O3 formed from 0.671 moles of Fe would be (0.671 moles Fe * 2 moles Fe2O3/4 moles Fe) = 0.336 moles of Fe2O3.
Finally, to find the mass of Fe2O3 produced, we multiply the moles of Fe2O3 by its molar mass. We calculate this as (0.336 moles Fe2O3 * 159.69 g/mol Fe2O3) = 53.657 g of Fe2O3.
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