The height of the water when poured into the empty wide cylinder is;
Option A; To the 7¹/₃ mark
Formula for volume of a cylinder is;
V = πr²h
where;
r is radius
h is height
We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;
V_wide = 4πR²
Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;
V_narrow = 6πr²
Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;
V_wide = V_narrow
4πR² = 6πr²
⇒ R²/r² = 6/4
simplifies to get; R²/r² = ³/₂
Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;
πR²H = 11πr²
R²/r² = 11/H
Earlier, we saw that R²/r² = ³/₂. Thus;
11/H = ³/₂
H = 22/3
H = 7¹/₃
The complete question is;
Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
A) To the 7¹/₃ mark
B)To the 8th mark
C) To the 7¹/₂mark
D)To the 9th mark
E) To the 11th mark
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Answer:
COMPLETE QUESTION:
To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark
e)To the 11th mark
ANSWER : Option D (To the 7 1/3 mark)
Step-by-step explanation:
First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e
Volume of cylinders
π x R² x 4 = πxr²x 6
R²/r² = 6/4
after both cylinder were emptied
π x R² x h = π x r² x 11
R²/r² = 6/4 = 11/h
h = (4 x 11) /6 = 22/3 = 7 1/3 mark
Therefore, the height of the water in the wide cylinder is 7 1/3
Answer:
1.646×10¹¹ km³.
Step-by-step explanation:
From the question given, we obtained the following information:
Radius (r) = 3400 km
Volume (V) =.?
The shape of a planet is spherical in nature. Thus, we shall apply the formula for calculating the volume of a sphere to obtain the volume of Planet Mar as illustrated below:
Radius (r) = 3400 km
Pi (π) = 3.14
Volume (V) =.?
Volume of a sphere = 4/3 πr³
V = 4/3 × 3.14 × (3400)³
V = 4/3 × 3.14 × 3.9304×10¹⁰
V = 1.646×10¹¹ km³
From the calculations made above, the volume of Planet Mar is 1.646×10¹¹ km³
Answer:
He does not have enough money in his checking account
Step-by-step explanation:
quizlet
Answer:
Same answer as the person above. He doesn't have enough money in his checking acc.
Step-by-step explanation:
The portion is $2,475 if the base is 1,850 and the rate is 150%.
Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.
* Multiplication operation: Multiplies values on either side of the operator
For example 12*2 = 24
We have to determine the portion if the base is 1,850.
Here rate is 150% or 150/100 = 1.50.
The base = 1,650.
Since the portion is the multiplication of base and rate.
The portion = base × rate.
The portion = 1650 × 1.50.
The portion = $2,475
Therefore, the portion is $2,475 if the base is 1,850 and the rate is 150%.
Answer:
portion = base * rate. rate is 150% or 150/100 = 1.50. base = 1,650. portion = 1650*1.50. portion = $2,475
Step-by-step explanation:
plz mark brainliest!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
$90
Step-by-step explanation:
300×0.70=210
300-210=90