Answer:
total profit margin for all 12 concert is $6,400.
profit margin for all one concert is $533.33
Step-by-step explanation:
Amount of money received for one event = $1700
Total no of concert = 12
Total money received for 12 event = Amount of money received for one event * Total no of concert
Total money received for 12 event = $1700 *12 = $20,400
Total cost of sponsorship = $14,000
Profit margin is the difference money invested and money earned.
here total investment is $14,000
Total money earned is $20,400
Therefore profit margin = money earned - total investment
= $20,400 - $14,000 = $6,400
Therefore total profit margin for all 12 concert is $6,400.
However to calculate profit margin for one concert we can simply divide the total profit margin for all 12 concert by no of concert (i.e 12)
profit margin for one concert = total profit margin for all 12 concert/total no of concert = $6,400/12 = $533.33
profit margin for all one concert is $533.33
Find the lower quartile and upper quartile of
the data set.
lower quartile: $
upper quartile: S
?
$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80
Answer:
Lower quartile: $1.42
Upper quartile: $1.64
Step-by-step explanation:
The median is the middle value when all data values are placed in order of size.
The ordered data set is:
$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80
There are 8 data values in the data set, so this is an even data set.
Therefore, the median is the mean of the middle two values:
Place "||" in the middle of the data set to signify where the median is:
$1.39 $1.40 $1.44 $1.50 ║ $1.60 $1.63 $1.65 $1.80
The lower quartile (Q₁) is the median of the data points to the left of the median. As there is an even number of data points to the left of the median, the lower quartile is the mean of the the middle two values:
The upper quartile (Q₃) is the median of the data points to the right of the median. As there is an even number of data points to the right of the median, the upper quartile is the mean of the the middle two values:
Answer:
to find the lower quartile and upper quartile of the given dataset, we need to first arrange the data in ascending order:
$1.39, 1.40, 1.44, 1.50, 1.60, 1.63, 1.65, 1.80$
The median of the dataset is given as $1.55$. Since there are an even number of data points, the median is the average of the two middle values, which in this case are $1.50$ and $1.60$.
Now, we need to find the lower quartile and upper quartile. The lower quartile is the median of the lower half of the data set, and the upper quartile is the median of the upper half of the data set.
The lower half of the dataset is $1.39, 1.40, 1.44, 1.50$. The median of this half is the average of the middle two values, which are $1.40$ and $1.44$.
Therefore, the lower quartile is $1.42$.
The upper half of the dataset is $1.60, 1.63, 1.65, 1.80$. The median of this half is the average of the middle two values, which are $1.63$ and $1.65$.
Therefore, the upper quartile is $1.64$.
Hence, the lower quartile of the dataset is $1.42$ and the upper quartile is $1.64$.
a)
1 2 3 4 5 6
b)
0 1 2 3 4 5 6
C)26
O i 2 3 4
D)5
0 1 2
3 4 5
6
A
B
оооо
С
D
Answer:
a. -7 + 3
b. draw 7 negatives + 7 positives
Step-by-step explanation:
Answer:
3.a) -7 + 3
3.b) 4
I hope this helps!
Answer:
1/3 + 1/4 = 4/12 + 3/12 = 7/12
7/12 = both brothers ate 7 crackers out of 12 crackers
there were 5 crackers left on the plate means 5/12 crackers left on the plate
answer: 12 crackers at the beginning
Step-by-step explanation:
Answer:
-0.2222
Step-by-step explanation:
If its multiple choice choose an answer close to this. Or don't I can't tell what to do.
Answer: -2/9
Decimal form: -0.2
Step-by-step explanation:
Calculate the mean, median, range, and midrange of the number of cups of tea sold for the week.
Answer:
mean = 7
median = 7
range = 9
mid range = 7.5
Step-by-step explanation:
3, 5, 6, 7, 7, 9, 12
Range is the difference between the highest and lowest values of a set of observations
Range = highest value - lowest value
12 - 3 = 9
Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order
3, 5, 6, 7, 7, 9, 12
median = 7
Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number
Mean = sum of the numbers / total number
(6 + 12 + 5 + 7+ 7 + 3 + 9) / 7 = 7
Mid range = (highest value + lowest value) / 2
(12 + 3) / 2 = 7.5