What is the magnitude of a point charge that would create an electric field of 1.18 N/C at points 0.822 m away?

Answers

Answer 1
Answer:

Answer:

q = 8.85 x 10⁻¹¹ C

Explanation:

given,

Electric field, E = 1.18 N/C

distance, r = 0.822 m

Charge magnitude = ?

using formula of electric field.

E = (kq)/(r^2)

k is the coulomb constant

q= (Er^2)/(k)

q= (1.18* 0.822^2)/(9* 10^9)

  q = 8.85 x 10⁻¹¹ C

The magnitude of charge is equal to q = 8.85 x 10⁻¹¹ C


Related Questions

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. Calculate the magnitude and direction of the net horizontal force on the rope.
Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.2 s and was brought jarringly back to rest in only 1 s. Calculate his (a) magnitude of acceleration in his direction of motion and (b) magnitude of acceleration opposite to his direction of motion. Express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity. g g
Ultraviolet light is typically divided into three categories. UV-A, with wavelengths between 400 nm and 320 nm, has been linked with malignant melanomas. UV-B radiation, which is the primary cause of sunburn and other skin cancers, has wavelengths between 320 nm and 280 nm. Finally, the region known as UV-C extends to wavelengths of 100 nm. (a) Find the range of frequencies for UV-B radiation. (b) In which of these three categories does radiation with a frequency of 7.9 * 1014 Hz belong
The brakes of a car moving at 14m/s are applied, and the car comes to a stop in 4s. (a) What was the cars acceleration? (b) How long would the car take to come to a stop starting from 20m/s with the same acceleration? (c) How long would the car take to slow down from 20m/s to 10m/s with the same acceleration?
What kind of energy is produce when sun reaches solar panel?

While a roofer is working on a roof that slants at 37.0 ∘∘ above the horizontal, he accidentally nudges his 92.0 NN toolbox, causing it to start sliding downward, starting from rest. If it starts 4.25 m from the lower edge of the roof, how fast will the toolbox be moving just as it reaches the edge of the roof if the kinetic friction force on it is 22.0 N?

Answers

Answer:

The speed is   v =8.17 m/s

Explanation:

From the question we are told that

      The angle of slant is  \theta = 37.0^o

       The weight of the toolbox is  W_t = 92.0N

       The mass of the toolbox is m = (92)/(9.8) = 9.286kg

       The start point is  d = 4.25m from lower edge of roof

        The kinetic frictional force is  F_f = 22.0N

Generally the net work done on this tool box can be mathematically represented as

      Net \ work done  =  Workdone \ due \ to \ Weight + Workdone \ due \ to \ Friction

The workdone due to weigh is  =    mgsin \theta * d

 The workdone due to friction is  = F_f \ cos\theta  *   d

Substituting this into the equation for net workdone  

                 W_(net) = mgsin\theta  * d + F_f  \ cos \theta *d

      Substituting values

                  W_(net)  =  92 * sin (37)  * 4.25 + 22 cos (37) * 4.25

                          = 309.98 J

 According to work energy theorem

             W_(net) = \Delta Kinetic \ Energy

              W_(net) = (1)/(2) m (v - u)^2

From the question we are told that it started from rest so  u = 0 m/s

              W_(net) = (1)/(2) * m v^2

Making v the subject

               v = \sqrt{(2 W_(net))/(m) }

Substituting value

              v = \sqrt{(2 * 309.98)/(9.286) }

             v =8.17 m/s

true or false A permanent magnet and a coil of wire carrying a current both produce magnetic fields

Answers

Answer:

True. A permanent magnet like the earth produces its own B field due to movement of the iron core. The earths magnetic field is the reason why we have an atmosphere and it also is the only defense against solar flares. A coil of wire or solenoid that has current have so much moving charge that the motion of the electrical charge can create a significant G b-field

Consider three drinking glasses. All three have the same area base, and all three are filled to the same depth with water. Glass A is cylindrical. Glass B is wider at the top than at the bottom, and so holds more water than A. Glass C is narrower at the top than at the bottom, and so holds less water than A. In which glass is the pressure on the base greatest liquid pressure at the bottom?a. Glass Ab. Glass B
c. Glass C
d. All three have equal non-zero pressure at the bottom.
e. All three have zero pressure at the bottom.

Answers

Answer:

d

Explanation:

Pressure of the fluid in any container is a function of density of the fluid in the container, and depth of the fluid.

The static pressure of fluid in a container with depth h is given by:

P = p * g* h

Where p : density of fluid

g: gravitational constant 9.81 m/s^2

h : depth of the fluid

Since, all the glasses filled have same Area base, same depth and same density of fluid and g is constant. The pressure at the bottom of each drinking glass is equal for all cases. As supported by the relationship given above.  

Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the transition from n=3 to n= 2.

Answers

Answer:

Ionization potential of C⁺⁵ is 489.6 eV.

Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.

Explanation:

The ionization potential of hydrogen like atoms is given by the relation :

E = (13.6Z^(2) )/(n^(2) ) eV     .....(1)

Here E is ionization potential, Z is atomic number and n is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for Z and 1 for n in the equation (1).

E = (13.6*(6)^(2) )/(1^(2) )

E = 489.6 eV

The wavelength (λ)  of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

(1)/(\lambda) =RZ^(2)[(1)/(n_(1) ^(2))-(1)/(n_(2) ^(2) )]     ......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

(1)/(\lambda) =1.09*10^(7) *6^(2)[(1)/(2 ^(2))-(1)/(3 ^(2) )]

(1)/(\lambda)  = 5.45 x 10⁷

λ = 1.83 x 10⁻⁸ m

As the Moon revolves around the Earth, it also rotates on its axis. Why is it that the same side of the Moon is always visible from Earth?

Answers

Answer: The speed of the moon's rotation keeps the same side always facing Earth.

Explanation: Please mark me brainiest

Answer:

The speed of the Moon's rotation keeps the same side always facing Earth.

Explanation:

got it right on study island :)

Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? a. Nina experiences a force equal to f/2. b. Nina experiences a force equal to f^2. c. Nina experiences a force equal to 2f. d. Nina experiences a force equal to f.

Answers

Answer:

A

Explanation:

• Nina experiences a force equal to f.

Answer:

Nina experiences a force equal to f

Explanation:

got to get that 2nd answer slot correct too before an abusive expert verifier with an alt comes in and purposely verifies the wrong answer

Other Questions