Suppose an object starts out electrically neutral. Through some process, 11 electrons are removed from the object. What is the electric charge of the object afterward? ANSWER 1. Unselected It has a net charge somewhere between the charge of 11 electrons and 11 protons, but we can’t tell exactly how much.
2. Unselected The stated situation isn’t possible.
3. Unselected It has the same net charge as 11 protons.
4. Unselected It has the same net charge as 11 electrons.

Answers

Answer 1

Answer:

Answer:

3. It has the same net charge as 11 protons.

Explanation:

An electrically neutral object contains the same number of protons and electrons. Therefore, if 11 electrons are removed from it, there will be 11 more protons compared to the number of electrons in the object. Thus, the object It has the same net charge as 11 protons.

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Salmon often jump waterfalls to reach theirbreeding grounds.
Starting 3.16 m from a waterfall 0.379 m
in height, at what minimum speed must a
salmon jumping at an angle of 37.6
◦
leave the
water to continue upstream? The acceleration
due to gravity is 9.81 m/s
2
.
Answer in units of m/s.

Answers

The problem corresponds to the motion of a projectile (the salmon), with initial speed $v_0$ , initial direction $\theta=37.6^(\circ)$ and vertical acceleration $g=9.81 m/s^2$ downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

$S_x (t) = v_0 cos \theta t$ (1)

$S_y (t) = v_0 sin \theta t - (1)/(2)gt^2$ (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

$t=(S_x)/(v_0 cos \theta)$

And substituting this expression of t into eq.(2), we get the following expression for $v_0$ :

$v_0 =\sqrt{(g S_x^2)/(2(tan \theta S_x -S_y)cos^2 \alpha)}$

And substituting the numbers into the equation, we find

$v_0 = 6.16 m/s$

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Answers

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Answers

D.
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Answer:

Explanation:

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Answers

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