Identify the value of x that makes each pair of ratios equivalent. 9 over 36 x over 4 A. 1 B. 4 C. 9

Answers

Answer 1

Answer: A, 9/36=1/4. Remember to reduce the fraction

Answer 2

Answer: Reduce the fraction in this problem of the value that makes each pair.

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Volunteers at an animal shelter are building a rectangular dog run so that one shorter side of the rectangle is formed by the shelter building as shown. They plan to spend between $100 and $200 on fencing for the sides at a cost of $2.50 per ft. Write and solve a compound inequality to model the possible length of the dog run.

Answers

Answer:

20 ≤ L + W ≤ 40

Step-by-step explanation:

[answer is marked by ** symbol]

The perimeter (P) of a rectangle is given by the formula:

P = 2L + 2W

In this case, you want to spend between $100 and $200 on fencing, and the cost is $2.50 per foot. So, you can write the cost equation as:

Cost = 2.50 (2L + 2W)

Now, you want the cost to be between $100 and $200, which leads to a compound inequality:

$100 ≤ 2.50 (2L + 2W) ≤ $200

Now, divide each part of the compound inequality by 2.50 to isolate the expression (2L + 2W):

$100 / 2.50 ≤ 2L + 2W ≤ $200 / 2.50

40 ≤ 2L + 2W ≤ 80

Now, divide each part by 2 to find L + W:

**20 ≤ L + W ≤ 40

**This compound inequality models the possible length of the dog run. It states that the length plus the width of the dog run must be between 20 feet and 40 feet to stay within the budget of $100 to $200 for fencing.

Answer
Write and solve a compound inequality to model the possible length of the dog run.
The inequality to model the possible length of the dog run is;. 100 ≤ 2.50x ≥
200
And the possible length of the dog run is 80ft.
Minimum spending = $100
Maximum spending = $200
Cost per square feet = $2.50
let
× = possible number of square feet

Minimum spending = $100
Maximum spending = $200
Cost per square feet = $2.50
let
× = possible number of square feet
The inequality:
100 ≤ 2.50× ≥ 200
This means possible number of square feet constructed is greater than or equal to $100 or less than or equal to $200
solve:
100 < 2.50× ≥ 200
divide the inequality into 2
100 < 2.50x
× ≤ 100/2.5
× ≤40
the other part:
2.50x ≥ 200
× ≥ 200/2.50
× ≥ 80
Therefore,
the possible length of the dog leash is 80

Write the equation in function form.then graph the equation

x-3y=-9 ???

Answers

$x-3y=-9 \n \n-3y=-x -9 \ \ / :(-3) \n \ny=(1)/(3)x + 3$

meyer has 0.64 GB of space remaining on his ipod.he wants to download a pedometer app (0.24 GB), a photo app (0.403 GB), and a math app (0.3 GB).which combinations of apps can he download? explain your thinking

Answers

He can either download both the pedometer and the math apps,
or he can download only the photo app and no more.

Pedometer + math = 0.54 GB. Fits in 0.64 GB.

Photo = 0.403 GB. Fits in 0.64 GB, but only 0.237 GB left.
Not enough for pedometer (0.24)
or math (0.3) .

The possible combination in which the app can be downloaded in ipod is $\boxed{\text{pedometer app}+\text{math app}}$ or $\boxed{\text{Photo app}}$ .

Further explanation:

The total memory space available in the ipod is $0.64\text{ GB}$ .

The memory space required for the pedometer app is $0.24\text{ GB}$ .

The memory space required for a photo app is $0.403\text{ GB}$ .

The memory space required for a math app is $0.4\text{ GB}$ .

As per teh question meyer wants to download the app as mentioned above in his ipod.

So, in order to download the app the most important point is that the total memory space available in the ipod should no be less than the memory space required for all the apps.

The objective is to determine the combination in which the different app can be stored in the ipod.

Consider three cases for the given question.

Case 1:

Consider that all the three apps are needed to be downloaded in the ipod.

If all the three apps are required to be downloaded then the total memory space required is calculated as follows:

$\boxed{0.24+0.403+0.3=0.943}$

As per the above calculation it is concluded that the all the three apps requires a memory space of $0.943\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.943>0.64$ so, this case is not possible.

Therefore, it is not possible to download all the three apps in ipod.

Case 2:

Consider that only pedometer app and a photo app is required to be downloaded.

The memory space required by pedometer app and a photo app is calculated as follows:

$\boxed{0.24+0.403=0.643}$

As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of $0.643\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.643>0.64$ so, this case is not possible.

Therefore, it is not possible to download pedometer app and a photo app in ipod.

Case 3:

Consider that only pedometer app and a math app is required to be downloaded.

The memory space required by pedometer app and a math app is calculated as follows:

$\boxed{0.24+0.3=0.54}$

As per the above calculation it is concluded that a math app and a pedometer app requires a memory space of $0.54\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.64>0.54$ so, this case is possible.

Therefore, it is possible to download pedometer app and a math app in ipod.

Case 4:

Consider that only a photo app and a math app is required to be downloaded.

The memory space required by math app and a photo app is calculated as follows:

$\boxed{0.3+0.403=0.703}$

As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of $0.703\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.703>0.64$ so, this case is not possible.

Therefore, it is not possible to download math app and a photo app in ipod.

This implies that either meyer can download pedometer app and math app or only a photo app.

Thus, the possible combination in which the app can be downloaded in ipod is $\boxed{\text{pedometer app}+\text{math app}}$ or $\boxed{\text{Photo app}}$ .

Learn more

1. Problem on the slope-intercept form brainly.com/question/1473992.

2. Problem on the center and radius of an equation brainly.com/question/9510228

3. Problem on general form of the equation of the circle brainly.com/question/1506955

Answer details:

Grade: Junior school

Subject: Mathematics

Chapter: Simplification

Keywords: Combination, simplification, meyer, memory, download, app, photo app, pedometer app, GB, 0.64, 0.24, math app, ipod.

Madison created two functions. For Function A, the value of y is two less than four times the value of x.

The table below represents Function B.
-3,-9
-1,5
1,-1
3,3

In comparing the rates of change, which statement about Function A and Function B is true?

A.

Function A and Function B have the same rate of change.
B.

Function A has a greater rate of change than Function B has.
C.

Function A and Function B both have negative rates of change.
D.

Function A has a negative rate of change and Function B has a positive rate of change.

Answers

Answer:

B. Function A has a greater rate of change than Function B has.

Step-by-step explanation:

Function A.

The value of y is two less than four times the value of x.

This statement can be expressed as

$y=4x-2$

This linear function is expressed as slope-intercept form. Where the slope is

$m=4$

Function B.

This function is represented by the given table.

If you observe, the domain is defined as -3, -1, 1, 3. The range is defined as -9, -5, -1, 3.

The domain values increase two units. Range values increase by 4. So, the ratio or slope of this function is

$m=(4)/(2)=2$

If we compare the ratio of change (or slopes) of both function, we would find that Function A as a doble ratio of change than Function B. In other words, Function A has a greater rate of change than Function B.

Therefore, the right answer is B.

Simplify the algebraic expression 8y-2(y+4)