Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard deviation for the given sample data. What do the results tell us? 33 29 97 56 26 78 83 74 65 47 58 Range = (Round to one decimal place as needed.) Sample standard deviations ? = (Round to one decimal place as needed) Sample variance = (Round to one decimal place as needed) What do the results tell us? a. Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless. b. Jersey numbers on a football team vary much more than expected c. The sample standard deviation is too large in comparison to the range. d. Jersey numbers on a football team do not vary as much as expected.

Answers

Answer 1

Answer:

Answer:

Range = 71

Variance = 546.0

Standard Deviation = 23.4

Option A) Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

We are given the following data set in the question:

33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

$\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle(646)/(11) = 58.7$

Sum of squares of differences = 5460.18

$\text{Variance} = (5460.18)/(11) = 546.0$

$S.D = \sqrt{(5460.18)/(10)} = 23.4$

Sorted Data Set: 26, 29, 33, 47, 56, 58, 65, 74, 78, 83, 97

Range = Maximum - Minimum

Range = 97 - 26 = 71

Based on the values, we can say that

Option A) Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

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Find the quotient of 2/5 and 4/5
Give your answer as a fraction in its simplest form.

Answers

What is the quotient?

The quotient is the number which is generated when we perform division operations on two numbers.

The quotient of 2/5 and 4/5.

The quotient of 2/5 and 4/5 is determined in the following steps given below.

$\rm Quotient =((2)/(5))/((4)/(5))\n\nQuotient =(2)/(5)* (5)/(4)\n\n Quotient =(2)/(4)\n\nQuotient =(1)/(2)$

Hence, the quotient of 2/5 and 4/5 is 1/2.

Learn more about quotient here;

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Answer:

$(1)/(2)$

Step-by-step explanation:

The sum of seven and 5 times a number is 48

Answers

Answer:

The sum of seven and five is 12 so the number would be 4 because 12 times 4 is 48 so the answer is "4" please give me brainliest!!

Can you please give me a short brief answer

Answers

Answer:

120 yards 1.

Step-by-step explanation:

In the shape, it is a rectangle with a triangle cut out from it. What is the area of the shape:

Area of rectangle = length × width

12 × 15 = 180 yards²

Area of triangle = ½ × base × height

½ × 10 × 12 = 60 yards²

Now subtract the area of triangle from the area of rectangle:

180 - 60 = 120 yards ²

In a sample of 49 adolescents who served as the subjects in an immunologic study, one variable of interest was the diameter of a skin test reaction to an allergen. The sample mean and standard deviation were 21 and 11 mm erythema, respectively. a. Use a z- or t-distribution? Why?

b. One-sided or two-sided test? Why?

c. Can it be concluded from these data that the population mean is less than 24 mm erythema?

d. What is the range on the p-value?

Answers

Answer:

Step-by-step explanation:

a) We would use a t distribution because the population standard deviation is unknown.

b) it is a one sided test because we are trying to determine if the population mean is less than 24 mm erythema. The lesser than means that it is a left tailed test.

c) To determine the p value, we would apply the formula,

t = (x - µ)/(s/√n)

Where

x = sample mean = 21

µ = population mean = 24

s = samples standard deviation = 11

n = number of samples = 49

t = (21 - 24)/(11/√49) = - 1.91

Since n = 49

Degrees of freedom, df = n - 1 = 49 - 1 = 48

We would determine the p value using the t test calculator. It becomes

p = 0.031

Assuming alpha = 0.05, then

Since alpha, 0.05 > than the p value, 0.031, then we would reject the null hypothesis. Therefore, At a 5% level of significance, it can be concluded from these data that the population mean is less than 24 mm erythema.

d) p value = 0.031

Mrs Perry shares out 21 biscuits betweenGemma and Zak in the ratio 1 : 6
How many biscuits does each child get?
biscuits.
Gemma gets
biscuits and Zak gets

Answers

Answer:

Gemma gets 3 biscuits

Zak gets 18 biscuits

Step-by-step explanation:

1:6 = 1+6

= 7

1/7 * 21 = 3

6/7 * 21 = 18

Step-by-step explanation:

x+6x=21

7x=21

x=3

6x=3×6= 18

Gemma gets 3 and Zak got 18

Drag each expression to match each number with an expression.Number. Expression.
34 34x10*0
3,400 34x10*3
34,000 34x100
340 34x10*1

Answers

Answer:

3,400

Step-by-step explanation:

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