Answer:
The Jupiter´s mass is approximately 1.89*10²⁷ kg.
Explanation:
The only force acting on Calisto while is rotating around Jupiter, is the gravitational force, as defined by the Newton´s Universal Law of Gravitation:
Fg = G*mc*mj / rcj²
where G = 6.67*10⁻¹¹ N*m²/kg², mc= Callisto´s mass, mj= Jupiter´s mass, and rcj = distance from Jupiter for Callisto= 1.88*10⁹ m.
At the same time, there exists a force that keeps Callisto in orbit, which is the centripetal force, that actually is the same gravitational force we have already mentioned.
This centripetal force is related with the period of the orbit, as follows:
Fc = mc*(2*π/T)²*rcj.
In order to be consistent in terms of units, we need to convert the orbital period, from days to seconds, as follows:
T = 16.69 days* 86,400 (sec/day) = 1.44*10⁶ sec.
We have already said that Fg= Fc, so we can write the following equality:
G*mc*mj / rcj² = mc*(2*π/T)²*rcj
Simplifying common terms, and solving for mj, we get:
mj = 4*π²*(1.88*10⁹)³m³ / ((1.44*10⁶)² m²*6.67*10⁻11 N*m²/kg²)
mj = 1.89*10²⁷ kg.
Answer: Mass of Jupiter ~= 1.89 × 10^23 kg
Explanation:
Given:
Period P= 16.69days × 86400s/day= 1442016s
Radius of orbit a = 1.88×10^6km × 1000m/km
r = 1.88 × 10^9 m
Gravitational constant G= 6.67×10^-11 m^3 kg^-1 s^-2
Applying Kepler's third law, which is stated mathematically as;
P^2 = (4π^2a^3)/G(M1+M2) .....1
Where M1 and M2 are the radius of Jupiter and callisto respectively.
Since M1 >> M1
M1+M2 ~= M1
Equation 1 becomes;
P^2 = (4π^2a^3)/G(M1)
M1 = (4π^2a^3)/GP^2 .....3
Substituting the values into equation 3 above
M1 = (4 × π^2 × (1.88 × 10^9)^3)/(6.67×10^-11 × 1442016^2)
M1 = 1.89 × 10^27 kg
Collecting data and analyzing results
Designing and implementing systems
Maintaining and using diagnostic equipment
Designing and using laboratory equipment
Mark this and return
Another thing that Ernie put in the common section is collecting data and analyzing results.
A Venn diagram is used to show a representation of data. The center of the Venn diagram is often used to indicate the data set that is the same.
Looking at the Venn diagram, another thing that Ernie put in the common section is collecting data and analyzing results.
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Answer:
The power exerted by the mountain lion is 1,472.35 W.
Explanation:
Given;
mass of mountain, m₁ = 21 kg
mass of the cub, m₂ = 3 kg
height jumped by the mountain lion, h = 2 m
time taken for the mountain lion to jump, t = 1 s
Determine the weight of the lions on the top rock;
W = F = (m₁ + m₂)g
F = (21 + 3) x 9.8
F = (24) x 9.8
F = 235.2 N
Determine the final velocity of the mountain rock as it jumped to the top;
v² = u² + 2gh
where;
u is the initial velocity = 0
h is the height jumped = 2 m
v² = 0 + 2 x 9.8 x 2
v² = 39.2
v = √39.2
v = 6.26 m/s
The power exerted by the mountain lion is calculated as;
P = Fv
P = 235.2 x 6.26
P = 1,472.35 W
Therefore, the power exerted by the mountain lion is 1,472.35 W.
Answer:
STRING held by the man
Explanation:
Wave is defined as a disturbance that travels through a MEDIUM and transfer energy from one point to another without causing any permanent displacement of the medium itself.
The medium through which wave travels varies e.g water, string, air etc
According to the diagram, wave travels through the string held by the man. This string is referred to as the MEDIUM through which the wave moves. The wave generated produces both crest (D) and trough (C) when displaced from its initial position (A)
Rope or one could consider it to be C to B or A to D
Answer:
mnbhngbfcvdxc
Explanation:
A) Net Force is -6.86N
B) The y component of momentum.
C) The x component of momentum should remain the same.
D)The y component of momentum decreases.
E)The z component of momentum should remain constant.
The following information should be considered:
(A)
The net force should be
= -9.8 (0.7)
= -6.86N
(B)
Due to the net force is on the y-axis, so only the vertical component of the momentum should be changed because to the force.
(C)
Because there is no resistance of air, the ball should be in projectilemotion problems, this represents hat the x component of the velocity remains constant, also does the mass.
D)
The y component of momentum reduced, this is due to gravity reduced the y component of the velocity.
E)Because there is no z component of the force there is no change in the z component of the momentum.
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With negligible air resistance and low speed, the only significant net force on a 0.7 kg ball is gravity, affecting the ball's y component of momentum. The x component remains constant, and z component changes are not discussed without additional forces.
When a ball of mass 0.7 kg flies through the air at low speed with air resistance negligible, the net force acting on the ball while it is in motion is primarily due to gravity, which will be impacting the y component of the ball's momentum. The x component of the ball's momentum remains unchanged because no horizontal force is applied, while the y component changes due to gravity, and the z component would only change if there were forces acting in a direction out of the horizontal plane, which are not mentioned in the scenario. As for the Earth-ball system, momentum is conserved in the vertical direction because the system experiences no net external vertical force.
Answer:
Answer
The Final Quality of teh R-134a in the container is 0.5056
The Total Heat transfer is
Explanation:
Explanation is in the following attachments