Calculate the maximum acceleration of a car that is heading up a 4º slope (one that makes an angle of 4º with the horizontal) under the following road conditions. Assume that only half the weight of the car is supported by the two drive wheels and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the acceleration. (Ignore rolling.) (a) On dry concrete.
(b) On wet concrete.
(c) On ice, assuming that μs = 0.100 , the same as for shoes on ice.

Answers

Answer 1
Answer:

Final answer:

The maximum acceleration of a car moving uphill can be calculated using the formula μs*g*cosθ - g*sinθ where θ is the slope angle, μs is the coefficient of static friction, and g is the acceleration due to gravity. The figures for μs differ depending on the road condition - dry concrete, wet concrete, or ice, substantially affecting the car's acceleration.

Explanation:

The maximum acceleration of a car moving uphill is determined by the force of static friction, which opposes the combined force of the car's weight component down the plane and the force utilized by the driving wheels. The maximum static friction force (F_max) is determined by the coefficient of static friction (μs) multiplied by the normal force (N), which is equivalent to the weight of the car (mg) multiplied by the cosine of the angle (cosθ).

(a) On dry concrete: Since the μs is usually 1.0 on dry concrete and half the weight of the car is supported by the drive wheels, the maximum acceleration can be calculated as μs*g*cosθ - g*sinθ

(b) On wet concrete: The μs is around 0.7 on wet concrete. Substituting this value into the formula would give us the maximum acceleration on a wet surface.

(c) On ice: With a μs value of 0.1 as given, the maximum acceleration on ice can also be calculated using the same formula.

As one can see, the road conditions significantly impact the car's maximum acceleration due to the change in the amount of friction between the tires and road surface.

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Answer 2
Answer:

Final answer:

The maximum accelerations for the car going up a 4º slope are 9.3 m/s² on dry concrete, 6.4 m/s² on wet concrete, and -0.1 m/s² on ice.

Explanation:

The maximum acceleration of the car up the slope can be calculated using the equation: a = μs * g * cosθ - g * sinθ, where a is the acceleration, μs is the coefficient of static friction, g is the acceleration due to gravity, and θ is the angle with the horizontal.

To solve this problem, we must teach the student to take several factors into account, including the various coefficients of static friction corresponding to different road conditions, namely dry concrete, wet concrete, and ice.

Considering that each scenario has different values of μs, we fill in the equation with the angles and coefficients of static friction. As a rule of thumb, μs for dry concrete is generally taken as 1.0, for wet concrete as 0.7 and for ice (mentioned in the question) as 0.100.

  1. For dry concrete, a = 1.0 * 9.8 * cos(4) - 9.8 * sin(4) = 9.3 m/s².
  2. For wet concrete, a = 0.7 * 9.8 * cos(4) - 9.8 * sin(4) = 6.4 m/s².
  3. For ice, a = 0.100 * 9.8 * cos(4) - 9.8 * sin(4) = -0.1 m/s².

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from p1v1/t1 = p2v2/t2
pressure unchanged ... cancelled out
v1=605 , t1=27C = 300K,
t2=-3C = 270K
***remember temperature must be in Kelvin
we got
605/300 = v2/270
v2 = 545