Answer:b
Explanation:
HELP ME!!!!!!¡!!!!
the internal energy of the cube increases by 47000 cal its temperature
increases by:
A
B
C
D
E
5 °C
10 °C
20 °C
100 °C
200 °C
The change in temperature of this cube of aluminum is equal to: B. 10°C
Given the following data:
To find the change in temperature of this cube of aluminum:
First of all, we would determine the volume of this cube of aluminum.
Next, we calculate the mass of this cube of aluminum:
Mass = 21,600 grams.
Now, we can find the change in temperature of this cube of aluminum:
Mathematically, the quantity of heat energy is given by the formula;
Where:
Substituting the parameters into the formula, we have;
Change in temperature = 10°C
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Answer:
10 °C
Explanation:
From the question given above, the following data were obtained:
Egde length (L) of aluminum = 20 cm
Density of Aluminum = 2.7 g/cm³
Specific heat capacity (C) of aluminum = 0.217 cal/ g°С
Heat (Q) energy = 47000 cal
Change in Temperature (ΔT) =?
Next, we shall determine the volume of the aluminum. This can be obtained as follow:
Egde length (L) of aluminum = 20 cm
Volume (V) of aluminum =?
V = L³
V = 20³
V = 8000 cm³
Thus, the volume of the aluminum is 8000 cm³
Next, we shall determine the mass of the aluminum. This can be obtained as follow:
Density of Aluminum = 2.7 g/cm³
Volume of Aluminum = 8000 cm³
Mass of aluminum =.?
Density = mass/volume
2.7 = mass /8000
Cross multiply
Mass of aluminum = 2.7 × 8000
Mass of Aluminum = 21600 g
Finally, we shall determine the change in temperature of the aluminum as follow:
Specific heat capacity (C) of aluminum = 0.217 Cal/g°С
Heat (Q) energy = 47000 Cal
Mass (M) of Aluminum = 21600 g
Change in Temperature (ΔT) =?
Q = MCΔT
47000 = 21600 × 0.217 × ΔT
47000 = 4687.2 × ΔT
Divide both side by 4687.2
ΔT = 47000 / 4687.2
ΔT = 10 °C
Therefore, the increase in the temperature of the aluminum is 10 °C.
Answer:
The two waves will add vectorially to produce a small amplitude wave in a valley phase.
Explanation:
The two waves will add vectorially to produce a small amplitude wave in a valley phase. This is because the amplitudes of the waves are slightly different and in opposite directions. When wave 1 cancels out all of wave 2, the resultant wave would be the slight difference between both waves, and it would be in the direction of wave 1 which is a valley phase.
At constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.
According to Newton's second law of motion, the force applied to a an object is directly proportional to the product of mass and acceleration of the object.
F = ma
Acceleration is the change in the velocity of an object per change in time of motion.
Thus, we can conclude that at constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.
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Answer:
Explanation:
When the puck is sliding on the ice, there is no force being exerted on the puck to keep it moving forward. Instead, inertia keeps the puck moving forward. Friction between the puck and the ice gradually slows the puck down. You hit a hockey puck and it slides across the ice at nearly a constant speed
Answer:
Explanation:
The equilibrium position of the sub is at the surface of the lake
Explanation:
We often refer to the electricity at a typical household outlet as being 120 V. In fact, the voltage of this AC source varies; the 120 V is "the rms value of the voltage".
The rms value of voltage is given by :
Where
is the peak value of voltage
So, the correct option is (d). " rms value of voltage".