CHEMISTRY MIDDLE SCHOOL

You start with an equimolar mixture of the gases SO₂ and O₂ in a container. The SO₂ and O₂ react to completion to form SO₃. If the temperature after the reaction is 25°C and the pressure in the container is 1.65 atm, what is the density of the product gas mixture? Assume ideal behavior.

Answers

Answer 1

Answer:

The density of the product gas mixture is 5.39 g/L

Explanation:

Given:

Temperature after the reaction = $25^0$ C

Pressure in the container = 1.65 atm

The ideal gas equation PV = nRT

To find: Density of the product gas mixture

Step 1:

Molarity (M) = P/(RT)

$\[M=(P)/(R T)\]$M=\frac{1.65 \mathrm{atm}}{\left(0.08206 (L \cdot a t m)/(m o l . K)\right)(298.15 K)}$$

M = 0.0674 mol/L

Step 2:

The product of the given reaction is $SO_3$ . Its molar mass is

1S x 32.066 g/mol = 32.066 g/mol

3O x 16 g/mol = 48 g/mol

Adding both we get 80.066 g/mol

Therefore the density of the product gas mixture is $0.0674 \frac{{mol}}{L} * \frac{80.066 g}{1 \mathrm{mol}}$

= 5.39 g/L

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Learn more : brainly.com/question/17726401

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