PHYSICS HIGH SCHOOL

A 20 kg box moving at an initial speed of 10 m/s slides 25 m to the right on a horizontal floor before it comes to a complete stop. What is the coefficient of friction between the box and the floor?

Answers

Answer 1

Answer:

The coefficient of friction between the 20 kg box and the floor is 0.2

We'll begin by calculating the acceleration of the box. This can be obtained as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 0 m/s

Distance (s) = 25 m

Acceleration (a) =?

v² = u² + 2as

0² = 10² + (2 × a × 25)

0 = 100 + 50a

Collect like terms

0 – 100 = 50a

–100 = 50a

Divide both side by 50

a = –2 m/s²

Finally, we shall determine the coefficient of friction. This can be obtained as follow:

Mass (m) = 20 Kg

Acceleration (a) = –2 m/s²

Acceleration due to gravity (g) = 10 m/s²

Frictional Force (F) = –ma = – (20 × –2) = 40 N

Normal reaction (N) = mg = 20 × 10 = 200 N

Coefficient of friction (μ) =?

$\mu = (F)/(N) \n\n\mu = (40)/(200)\n\n$

μ = 0.2

Therefore, the coefficient of friction between the box and the floor is 0.2

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Answer 2

Answer:

The coefficient of friction between the box and the floor is 0.204.

Given data:

The mass of box is, m = 20 kg.

The initial speed of box is, u = 10 m/s.

The sliding distance is, s = 25 m.

The linear force acting on the fox is providing it necessary friction. Then,

$F = -F_(f)\nma = -\mu mg\na= -\mu * g$

Here, a is the linear acceleration and $\mu$ is the coefficient of friction between the box and the floor.

Applying the third kinematic equation of motion as,

$v^(2)=u^(2)+2as\n0=10^(2)+2(a)* 25\na = (-100)/(50)\na =- 2\;\rm m/s^(2)$

Then,

$a=- \mu * g\n-2= -\mu * 9.8\n\mu = 0.204$

Thus, we can conclude that the coefficient of friction between the box and the floor is 0.204.

Learn more about frictional force here:

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Answers

Type 2 diabetes is a common and illness that is largely preventable. In adults, types about 90 to 95 percent of all diagnosed cases of diabetes; the remainder are adult-onset (or adult-diagnosed) type 1 diabetes, a form of diabetes for which the cause is unknown

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Answers

Given:

Mass of the Beaker = 12.023 g

Total Mass of the Beaker and the Ball = 23.050 g

To Find:

The Mass of the Ball.

Solution:

Total Mass of the Beaker and the Ball - Mass of the Beaker = Mass of the Ball

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Answer:

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Answers

The statement is false because the energy released from the sun is the result of a nuclear fusion reaction. This type of nuclear reaction involves the fusing of two hydrogen nuclei to form a heavier helium atom. The energy involved here is much greater than nuclear fission, and involves higher temperature.

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Answers

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A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A horizontally launched object that defies gravity is referred to as a projectile.

Thus, a stone is thrown horizontally at 8.0 m/s from a cliff 78.4 m high. The distance from the base of the cliff does the stone strike the ground is 64 m.

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give the answer in watts to three significant figures

Answers

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Work done = mgh
Mass, m = 33kg ( Am presuming it is 33 kg).
h = 85 m.
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Time taken.
Since object was dropped from height, it fell under gravity.
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