Express your emotions on how bad fraud and corruption and how they must be avoided
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Fraud is dishonest activity causing actual or potential financial loss to any person or entity including theft of personal identity, moneys or other property by employees or persons external to the University and where deception is used at the time, immediately before or immediately following the activity. This also includes the deliberate falsification, concealment, destruction or use of falsified documentation used or intended for use for a normal business purpose or the improper use of information or position for personal financial benefit.
The concept of fraud involves fraudulent or corrupt conduct by internal parties or external entities targeting the University, or fraudulent or corrupt conduct by the University itself targeting external entities.
What is corruption?Corruption is dishonest activity in which a person abuses his/her position of trust in order to achieve some personal gain or advantage for themselves, or provide an advantage/disadvantage for another person or entity.
Corrupt conduct can take many forms including:
conflicts of interesttaking or offering bribesdishonestly using influenceblackmailfraudtheftembezzlementtax evasionforgerynepotism and favouritismNOTE: Corruption does not include mistakes or unintentional acts.
Related Questions
Which of the following is NOT an example of accelerated motion?A. an airplane taking off down a straight runwayB. a boulder falling off a cliff in a straight pathC. a ball being thrown straight upD. a bicyclist moving in a straight line at a constant speed
An observer on Earth measures the length of a spacecraft travelling at a speed of 0.700c to be 78.0 m long. Determine the proper length of the spacecraft.
A 15 cm3 block of gold weighs 2.8 N. It is carefully submerged in a tank of mercury. One cm3 of mercury weighs 0.13 N. a. Will the mercury be displaced by the gold?b. Will the gold sink or float in the mercury?
Which example illustrates Newton's second law?A. A wheelbarrow remains stationary when no one pushes on it.B. More mass is added to a wheelbarrow, and a larger force isrequired to move it.C. A person pushes a wheelbarrow, causing it to move forward.D. The force of a wheelbarrow on the ground is equal to the force ofthe ground on the wheelbarrow.
Answers
The total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.
What will be the distance and displacement of the girl?
Distance = total amount of path followed by any body called distance.
Displacement= The minimum distance between two points irrespective to the path followed by the body is displacement.
It is given that
Distance traveled to north direction = 10 metres
Distance traveled to south direction= 30 metres
So the path followed by the girl in total = North direction + south direction
= 10+30
= 40 meters
And the displacement = min distance between History class and fountain
= 30 meters
total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.
To learn more about Distance and Displacement follow
Answers
Answer: plasma
Explanation:
Plz give Brainlies. I have 0.
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Answer:
162.78 m/s is the most probable speed of a helium atom.
Explanation:
The most probable speed:
= Boltzmann’s constant =
T = temperature of the gas
m = mass of the gas particle.
Given, m =
T = 6.4 K
Substituting all the given values :
162.78 m/s is the most probable speed of a helium atom.
Answers
Answer:
508Hz
Explanation:
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production
frequency is the number of oscillation a wave makes in one seconds.
f1-f2=beats
therefore f1=512Hz
f2=?
beats=4Hz
512Hz-f2=4Hz
f2=512-4
f2=508Hz
the original frequency of the violin is 508Hz
Final answer:
The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Explanation:
The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.
Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.
Learn more about Beat Frequency here:
#SPJ11
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Continuity in Psychology accounts for visual perception of immediate environments that piece together a background's individual elements to form a panoramic image.
The choices are:
A.) depth perception.
B.) perception.
C.) similarity.
D.) continuity.
Was D the correct answer?
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Answer:
4.1. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. In other words, when one object exerts a force on another object, the second object exerts an equal force in the opposite direction on the first object.
4.2. Here's a labeled free-body diagram for Block A:
```
T (tension in the string)
↑
│
│
│
│
│
F (applied force)
──→ (direction of motion)
```
In this diagram, "T" represents the tension in the string, and "F" represents the applied force at an angle of 30° to the horizontal. The arrow indicates the direction of motion.
4.3. To find the frictional force acting on block A as it accelerates, we can use Newton's Second Law:
\[F_{\text{net, A}} = m_A \cdot a\]
Where:
- \(F_{\text{net, A}}\) is the net force acting on block A.
- \(m_A\) is the mass of block A (given as 15 kg).
- \(a\) is the acceleration (given as 2.08 m/s²).
Rearranging the equation to solve for \(F_{\text{net, A}}\):
\[F_{\text{net, A}} = 15 kg \cdot 2.08 m/s² = 31.2 N\]
Now, we need to consider the frictional force, which opposes the motion and acts in the direction opposite to the applied force. So, the frictional force is 31.2 N in the opposite direction of motion, making it:
Frictional force on block A = -31.2 N
However, since you want it in magnitude, it's 31.2 N.
4.4. To calculate the mass of block B, we can use the fact that block A and block B are connected by a string, so they experience the same acceleration. Therefore, we can use the following equation:
\[F_{\text{net, B}} = m_B \cdot a\]
Where:
- \(F_{\text{net, B}}\) is the net force acting on block B, which is the tension in the string.
- \(m_B\) is the mass of block B (unknown).
- \(a\) is the acceleration (given as 2.08 m/s²).
We already calculated that the tension in the string is 31.2 N. Plugging in the values:
\[31.2 N = m_B \cdot 2.08 m/s²\]
Now, solving for \(m_B\):
\[m_B = \frac{31.2 N}{2.08 m/s²} \approx 15 kg\]
So, the mass of block B is approximately 15 kg.