Answer:
a. The reaction is exothermic.
b. -87,9 kJ
c. 9,60g of Mg(s)
d. 602kJ are absorbed
Explanation:
Based on the reaction:
2Mg(s) + O₂(g) → 2MgO(s) ΔH = -1204kJ
a. The reaction is exothermic. Because ΔH<0. That means the reaction produces heat when occurs
b. 3,55g of Mg(s) are:
3,55g Mg × ( 1mol / 24,305g) = 0,146 moles of Mg(s)
As 2 moles of Mg(s) produce -1204 kJ of heat:
0,146 moles of Mg(s) × ( -1204kJ / 2mol Mg) = -87,9 kJ
c. If -238 kJ of heat were transferred. The moles of Mg(s) that react must be:
-238kJ × ( 2mol Mg / -1204kJ) = 0,395 moles of Mg(s). In grams:
0,395 moles × ( 24,305g / 1mol Mg) = 9,60g of Mg(s)
d. The reverse reaction is:
2MgO(s) → 2Mg(s) + O₂(g) ΔH = +1204kJ
40,5g of MgO(s) are:
40,5g MgO × ( 1mol MgO / 40,3044g) = 1,00 moles of MgO(s)
As 2 moles of MgO absorbe 1204kJ of energy:
1,00 moles of MgO(s) × ( +1204 kJ / 2mol MgO) = 602kJ are absorbed
I hope it helps!
This response explains whether the reaction is exothermic or endothermic, calculates the amount of heat transferred in different scenarios, and determines the mass of MgO produced during a given enthalpy change. It also calculates the amount of heat absorbed during the decomposition of MgO.
a) This reaction is exothermic because the enthalpy change, represented by delta H, is a negative value (-1204 kJ).
b) To calculate the amount of heat transferred when 3.55 g of Mg(s) reacts, we can use the equation q = m * delta H. Plugging in the given values, we get q = (3.55 g) * (-87.9 kJ/1 mol) / (24.31 g/mol) = -15.98 kJ.
c) To determine the mass of MgO produced during an enthalpy change of -238 kJ, we can use the equation q = m * delta H and solve for m. Plugging in the given values, we get m = (-238 kJ) / (-1204 kJ/mol) * (40.31 g/mol) = 7.90 g.
d) To find the amount of heat absorbed when 40.5 g of MgO(s) is decomposed, we can again use the equation q = m * delta H. Plugging in the given values, we get q = (40.5 g) * (-1204 kJ/mol) / (40.31 g/mol) = -1209 kJ.
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Answer:
C. All electron carriers are mobile and hydrophobic
Explanation:
Hello,
In this case, it is widely known that the electron carriers move inside the inner mitochondrial membrane and consequently move electrons from one to another. In such a way, they are mobile, therefore they are largely hydrophobic as long as they are inside the membrane.
For instance, the cytochrome c is a water-soluble protein in a large range, therefore, the answer is: C. All electron carriers are mobile and hydrophobic.
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(2) 200. K to 400. K (4) 200.°C to 400.°C
An element's placement within a group on the periodic table is indicative of its electron configuration, specifically the number of valence electrons it has. As we move down a group, the principal quantum number increases, essentially moving to a higher energy level. Some elements show exceptions based on stability offered by half-filled or completely filled orbitals.
The placement of an element within a group on the periodic table has a direct correlation with its electron configuration. This connection is based on the fact that elements within the same group share the same number of valence electrons - electrons in the outermost shell of an atom that determine the chemical behavior of an element. This arrangement of elements gives the periodic table its periodic property, with recurring physical and chemical properties. An element's principal quantum number, representing the energy level of the electron, increases as we move down a group.
Although this pattern is generally accurate, there are exceptions to this rule, particularly when half-filled or completely filled orbitals can be formed which add to the atom's stability. Elements like chromium (Cr) and copper (Cu) demonstrate such anomalies.
The electron configuration of an atom, therefore, provides insights into the atom's properties, chemical behavior, and its placement on the periodic table. Understanding this connection between the location of an element on the periodic table and its electron configuration is crucial to predicting how elements will behave in chemical reactions.
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B) extinction
C) fragmentation
D) unification
The correct answer is (C) fragmentation.
Habitat fragmentation is discontinuities in a organism's preferred ecosystem, causing disturbance in a population and ecosystem decay. Cause of fragmentation is geological processes and human activities like deforestation. Habitat loss, which occur through the process of habitat fragmentation, is considered a greatest to species and biodiversity.
B. Solar flares only
C. Solar systems only
D. All of the above
Answer:
Explanation:
D