Which nucleus would be least likely to undergo radioactive decay?

Answers

Answer 1

Answer: A large nucleus. This is because the nuclear forces are not as strong as the repulsive electrical forces between nucleons. The said nuclear force is more or less the surface tension force. In a large nucleus, it is not as strong as the repulsing forces in a smaller nucleus.

Answer 2

Answer:

Answer:

Stable nuclei will not undergo in nuclear decay reactions. Stability of nucleus depends upon the force between nucleons.

If there is strong attraction force between the nucleons then the repulsion force between the protons will be neglected over this strong force and the nuclei is stable.

Also we can check the stability of nucleus by the ratio of neutrons and protons in the nucleus.

here the stability of nucleus is more it the ratio lie between 1 and 1.2 i.e.

$1 < (N)/(P) <1.2$

so the neutron to proton ratio will decide the stability of nucleus.

So it the ratio lie for above range of neutrons and protons then it is least likely to go radioactive decay.

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An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the acceleration a of the object is given by a = g bv, where v is the object's speed and b is a constant. If limiting cases for large and small values of t are considered, which of the following is a possible expression for the speed of the object as an explicit function of time? A) v = g(1-e^-bt)/b B) v = (ge^bt)/b C) v = (g+a)t/b

Answers

Answer:

A) $(g)/(b)(1-e^(-bt))$

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since $(dv)/(dt)= g - bv = b( (g)/(b) - v)$ ⇒ $(dv)/( (g)/(b) - v)= bdt$

So take the integral of both side.

$- ln ((g)/(b) - v) = bt + C$

Since for t=0, v = 0 ⇒ $C =- ln ((g)/(b))$

$v = (g)/(b) + e^{-bt-ln((g)/(b))} = (g)/(b)- (g)/(b)e^(-bt) = (g)/(b)(1-e^(-bt))$

The correct option for the expression of speed as an explicit function of time is option A

A) v = g·(1 - $e^{-b \cdot t$ )/b

The reason why option A is correct is given as follows;

Known:

The initial velocity of the object at time t = 0 is v = 0 (object at rest)

The function that represents the acceleration is a = g - b·v

Where;

v = The speed of the object at the given instant

b = A constant term

By considering the limiting case for time t, we have;

At very large values of t, the velocity will increase such that we have;

$\lim \limits_(t \to \infty) a = 0$ therefore, $\lim \limits_(t \to \infty) g - b\cdot v = 0$ and $\lim \limits_(t \to \infty) \left( v_(max) = (g)/(b) \right)$

The given equation can be rewritten as follows, to express the equation in terms the velocity;

$a = b \cdot \left((g)/(b) - v \right) = b \cdot \left(v_(max) - v \right)$

$Acceleration, \ a = (dv)/(dt)$

Therefore;

$(dv)/(dt) = b \cdot \left((g)/(b) - v \right)$

The above differential equation gives;

$(dv)/( \left((g)/(b) - v \right)) = b \cdot dt$

Which gives;

$\displaystyle \int\limits {(dv)/( \left((g)/(b) - v \right)) } = \int\limits {b \cdot dt} = b \cdot t + C$

$\displaystyle \int\limits {(dv)/( \left((g)/(b) - v \right)) } = -\ln \left((g)/(b) - v \right)$ and $\displaystyle\int\limits{b \cdot dt} = b \cdot t + C$

Therefore

$\displaystyle -\ln \left((g)/(b) - v \right) =b \cdot t + C$

At t = 0, v = 0, therefore;

$\displaystyle -\ln \left((g)/(b) - 0 \right) =b * 0 + C$

$C = \displaystyle -\ln \left((g)/(b) \right)$

Which gives;

$\displaystyle -\ln \left((g)/(b) - v \right) =b \cdot t \displaystyle -\ln \left((g)/(b) \right)$

$\displaystyle \ln \left((g)/(b) - v \right) =-b \cdot t \displaystyle +\ln \left((g)/(b) \right)$

$\displaystyle (g)/(b) - v = e^{-b \cdot t \displaystyle +\ln \left((g)/(b) \right)} = e^(-b \cdot t) * e^\ln \left((g)/(b) \right)} = e^(-b \cdot t) * (g)/(b)$

$\displaystyle (g)/(b) - e^(-b \cdot t) * (g)/(b) = v$

$\displaystyle (g)/(b) \cdot \left(1 - e^(-b \cdot t) \right) = v$

∴ v = g·(1 - $e^{-b \cdot t$ )/b

The correct option is option (A)

Learn more about differential equation here;

brainly.com/question/13309100

Why is there less air pressure at higher altitudes?Air at higher altitudes doesn't have as much air weighing down on it from above.

Air at higher altitudes is cooler and less turbulent.

The molecules in the air lose mass and are less effected by gravity, significantly lowering their weight

The warmer, lighter air rises bringing cooler heaver air to low altitudes.

Answers

Answer:

As ailtitudes rises air pressure drops ...... As altitude increases , the amount of gas molecules in the air decreases - so the air becomes less dense than air nearer to the sea level. So there is less air pressure at high altitudes

Where does wave reflection occur?at boundaries between two different media
while a wave is propagating through a single media
when two waves moving in opposite directions collide
none of the above

Answers

The correct answer for the question that is being presented above is this one: "none of the above." Wave reflection happens there is a change in direction of a wavefront. This wavefront is at an interface between two different media, which makes the wavefront returns into where it is originated.

Answer:

The correct answer is actually "at boundaries between two different media"

Explanation:

Checked and it is said word for word in the corresponding slide

Which of the following are voltage sources?a. ohm's law
b. resistance
c. electric charge
d. batteries and wall sockets

Answers

Batteries and wall sockets

Electric charge, batteries, and wall outlets are voltage sources. So is a lemon with a copper penny and a galvanized nail stuck in it.

A very small tilt in Earth’s axis would likely cause ____.

Answers

This would result to small changes in temperature and pressure at various focal pints of the earth relative to the tilt angle. The earth is already at a 23.5 degree tilt angle thus change of this angle would trigger extremities of both high and low temperatures in specific regions.

Answer:

A very small tilt in Earth’s axis would likely cause _____.

no climate changes

large seasonal variations in temperature

short-term climate changes

small seasonal variations in temperature

Explanation:

Answer small seasonal variations in temperature

The tilt of Earth’s axis changes by about 3 degrees. This affects the severity of the seasons. When Earth’s axis is less tilted, the temperature difference between summer and winter is less.

1. An isotope has the same ________, but a different ________ .Question 1 options:

number of protons, number of electrons

number of neutrons, number of protons

Mass number, number of protons.

Atomic number and Mass number

2.U-232
U-235
U-236
U-238

These nuclei all have a different number of

Question 2 options:

Electrons

Neutrons

Protons

Nucli
Identify the number of neutrons in one atom of sulfur with an isotopic mass number of 34 amu.

Question 3 options:

16

18

32

34

3.Identify the number of neutrons in one atom of sulfur with an isotopic mass number of 34 amu.

Question 3 options:

16

18

32

34

Answers

1:D(Atomic number, Mass number) 2:B(Neutrons) 3:b(18) hope it helps

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