A good baseball pitcher can throw a baseball toward home plate at 90 mi/h with a spin of 1950 rev/min. How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.

Answers

Answer 1

Answer:

The baseball will undergo 16 revolutions on its way to home plate.

Explanation:

As the parameters which are given are speed at which the baseball is thrown, (v = 90 mi/h) and the distance between the home plate and the ball thrown is 60 ft. Also the spin is said to 1950 rev/min, it indicates that the ball will undergo 1950 revolution in every single minute. So in order to determine the number of revolutions the baseball will make in its way to home plate, we have to first determine the time taken for the baseball to reach its home plate with the given speed.

As we know that speed can be obtained by the ratio of distance with time, in the present case, we know the speed and distance, then time can be obtained by ratio of distance with speed.

At first, we have to convert the speed from mi/h to ft/min

1 mi/hr = 5280/ 60 ft/min = 88 ft/min.

Then, Time = Distance/Speed = 60/(90×80)=60/7200=8.33 × 10⁻³ min

Since the ball undergoes 1950 revolutions in 1 min, then in 8.33 × 10⁻³ min, the number of revolutions will be 1950×8.33 × 10⁻³ = 16 rev

Thus, the baseball will undergo 16 revolutions on its way to home plate.

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A crane raises a 150 N weight to a height of 2.0 m in in 5.0 s. The crane does work at a rate of

Answers

The work done is (force) x (distance) = (150N) x (2m) = 300 joules.

The crane does the work at the rate of (300 J) / (5 sec) = 60 joules per second.

That rate ... (work done) / (time to do the work) ... is called power.

That 60 joules per second is called 60 watts .

Answer:

60. W

Explanation:

60 Watts

A long jumper leaves the ground at a 30 degree angle and travels 8.50 m. What is his take off speed?

Answers

Explanation:

To find the takeoff speed of the long jumper, we can utilize the physics principles of projectile motion. Given that the long jumper leaves the ground at a 30-degree angle and travels a distance of 8.50 m, we need to find the initial velocity (takeoff speed) of the jumper.

In projectile motion, we can break down the motion into horizontal and vertical components. The horizontal component remains constant, while the vertical component is affected by gravity.

To solve for the takeoff speed, we can focus on the vertical component of motion. The equation that relates the vertical displacement, initial velocity, launch angle, and acceleration due to gravity is as follows:

Δy = v₀y t + (1/2) g * t²,

where:

- Δy is the vertical displacement (8.50 m),

- v₀y is the vertical component of initial velocity (takeoff speed),

- t is the total time of flight, and

- g is the acceleration due to gravity (approximately 9.8 m/s²).

Since the vertical displacement at the peak of the jump is zero (the jumper is at the highest point), we can rewrite the equation as:

0 = v₀y * t + (1/2) g t².

However, we can derive a relation between the time of flight t and the initial velocity v₀y by using the launch angle θ. The time of flight is given by:

t = (2 v₀y sin(θ)) / g.

Substituting this expression for t in the above equation, we have:

0 = v₀y [(2 v₀y sin(θ)) / g] + (1/2) g [(2 v₀y sin(θ)) / g]².

Now, we can solve for v₀y:

0 = v₀y² (2 sin(θ) + sin²(θ)) / g.

Rearranging and isolating v₀y, we get:

v₀y = √[(g Δy) / (2 * sin(θ) + sin²(θ))].

With the given values:

Δy = 8.50 m,

θ = 30 degrees,

g ≈ 9.8 m/s²,

we can substitute these values into the formula:

v₀y = √[(9

What do you mean by average velocity

Answers

Answer:

Here is the answer. Hope this helps you!

Explanation:

Average velocity is the sum of initial and final velocity divided by 2. I t is the same as total Displacement divided by total time. Average velocity is calculated when the body is in non-uniform motion (also when total displacement and time is not given). The formula is as follows:

u + v/2 = $v_(av)$

Average velocity = Average speed

during motion in a straight line. therefore, the above mentioned formula can be used for calculating average speed as well, when the direction is one and only the same, that is, during motion in a straight line. The S.I unit remains the same-

m/s.

Since velocity is vector, average VELOCITY is also vector. However, Average SPEED is scalar as speed is scalar. both can be equal only when the distance = displacement and when they are following the same direction of motion.

An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine the power output and the rate of heat rejection

Answers

Efficiency = Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

= 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s = 0.061667 MW J/s = Watts

Power input = 0.061667 MW = 61 667 W

From Efficiency = Power Output / Power Input

   28% = Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W

Power Output = 17 267 W

Rate of heat Rejection = Power input - Power output

      = 61667 - 17267 = 44400 W

Rate of heat Rejection = 44 400 W.

C- Copyright.

A series circuit contains four light bulbs. The switch is opened and one of the bulbs is removed, but not replaced. Then the switch is closed again. What would you expect to see?A) All three remaining light bulbs will be on.
B) None of the remaining light bulbs will be on.
C) Only the bulb closest to the switch will be on.
D) All three remaining light bulbs will be brighter than before.

Answers

The correct answer is option B) None of the remaining light bulbs will be on.

What will happen if one light bulb is removed from a series circuit?

In a series connection when a bulb is removed, it will be creating a open circuit. Since the circuit is series and is open at a point current will not flow and hence the other bulb will not glow.

Why did the series circuit stop working when one of the light bulbs was removed?

That's because the basic requirement for the circuit to operate a continuous, closed-loop path is no longer met. This is the main disadvantage of a series circuit. If any one of the light bulbs or loads burns out or is removed, the entire circuit stops operating.

Learn more about the series circuit here: brainly.com/question/19865219

#SPJ

for series circuit, components are in the same path. removing component, the path is broken. so without replacing the bulb, current could not flow -- open circuit. all bulbs are dead.

What is the density of 244 grams of aluminum that has a volume of 90 ml?