Karissa is conducting an experiment on the amount of salt that dissolves in water at different temperatures. She repeats her tests several times using the same procedure.What can Karissa do to further increase confidence in the results of her experiment?

have another scientist run the same exact procedure in her lab
include several other liquids for comparison
calculate the average amount of salt that dissolves to summarize findings
make sure the experiment follows a specific procedure that allows other scientists to produce the same findings

Answers

Answer 1

Answer:

Answer:

C.) Calculate the average amount of salt that dissolves to summarize findings

Explanation:

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Answer 2

Answer:

Answer:

Calculate the average amount of salt that dissolves to summarize finding

-The third choice/ C-

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The splitting of an atom to produce energy is called a ________ reaction.a. fusion
b. fission
c. physical
d. chemical

Answers

The correct answer is fission.

Answer: The answer to this question is fission

Explanation: Can I get brainliest

What is the density of the block? Assume that the block is 40.0% submerged.First Sketches says block weigh 50g
Express the density numerically in grams per cubic centimeter.

Answers

There are forces are acting on the block: 1. Fs = upward force from scale (up = + Fs) 2. W = downward weight force (down = - W) 3. Fb = upward buoyancy force (up = + Fb)
Since the block is at rest, (net force = 0), the force equation is:
Fs + Fb - W = 0 ~(eq1)
Substituting Fs, Fb and W into ~(eq1): ==> {m (on scale) x g} + {ρ x V x g} - (m (block) x g} = 0
Dividing both sides of equation by g: m (on scale) + (ρ x V) - m (block) = 0 ~(eq2)
Given: V = volume of water displaced = 40% volume of the block = 0.40 x V (block)
Substituting 0.40 x V (block) into ~(eq2): m (on scale) + (ρ x 0.40 x V (block)) - m (block) = 0 ~(eq3) where, m (on scale) = 5.6 g ρ = density of water at 20ºC = 0.99821 g/cm^3 m (block) = 50 g
Substituting m (on scale), ρ and m (block) into ~(eq3): 5.6 g + (0.99821 g/cm^3 x 0.40 x V (block)) - 50 g = 0 ~(eq4)
Simplifying ~(eq4) and solving for V (block): ==> 5.6 g + 0.399284 g/cm^3 x V (block) - 50 g = 0 ==> 0.399284 g/cm^3 x V (block) - 44.4 g = 0 ==> 0.399284 g/cm^3 x V (block) = 44.4 g ==> V (block) = 44.4 g / (0.399284 g/cm^3) ==> V (block) = 111.199 cm^3
ρ (block) = density of block = m (block) / V (block) = 50 g / 111.199 cm^3 = 0.449644 g / cm^3

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C. with smaller amplitudes than the molecules in a longitudinal wave.
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Answers

So we wan't to know how the molecules of the medium vibrate when a transverse wave propagates trough that medium. A transverse wave is a wave whos oscilations are perpendicular to the direction of it's propagation. So the molecules in a medium will vibrate perpendicular to the direction of propagation of the wave. So if the wave is moving in the x-direction, the molecules will vibrate in the y-z plane. The correct answer is A. at right angles to the direction in which the wave propagates.

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Answers

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Answers

A is the answer

Hope it helps

d. halogen is the answer

the pressure of a sample of gas was 97.8 kPa and the volume of the gas was 3.75 l. if the gas occupied a container with a volume of 8.00 L, what would the pressure in the container be?

Answers

If the temperature stays the same then:
P1V1=P2V2
so:
97.8*3.75=8P
366.75=8P
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